JS Question
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I know this is possible with Reverse() but IE9.0 is not supported I have to thanks for everything
Hakan cursed chats dealer :)
If you are referring to array.reverse, then it is possible, even with IE 9.0 and as far back as IE 3.0. The browser doesn't affect Javascript features, only the revision (version) supported. Javascript features are not controlled by Microsoft, only the implementation. ECMA controls Javascript features. Most of the time I have to figure out (guess) what you want. And I don't always get a reply. a simple :thumbsup: or Yes, ok. or :thumbsdown: or No, not ok. I think your problem is storing numbers in strings, and applying C++ use (ie pointers) to them. Obviously the lack of computer books in your own language means that you could be learning from bad translation where the meaning of concepts is lost. Maybe you should learn English. Then the barriers to understanding won't slow you down.
"It's true that hard work never killed anyone. But I figure, why take the chance." - Ronald Reagan That's what machines are for. Got a problem? Sleep on it.
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If you are referring to array.reverse, then it is possible, even with IE 9.0 and as far back as IE 3.0. The browser doesn't affect Javascript features, only the revision (version) supported. Javascript features are not controlled by Microsoft, only the implementation. ECMA controls Javascript features. Most of the time I have to figure out (guess) what you want. And I don't always get a reply. a simple :thumbsup: or Yes, ok. or :thumbsdown: or No, not ok. I think your problem is storing numbers in strings, and applying C++ use (ie pointers) to them. Obviously the lack of computer books in your own language means that you could be learning from bad translation where the meaning of concepts is lost. Maybe you should learn English. Then the barriers to understanding won't slow you down.
"It's true that hard work never killed anyone. But I figure, why take the chance." - Ronald Reagan That's what machines are for. Got a problem? Sleep on it.
Finally, I tried the following code.
var arrIns = [
"1","21","24","28","42","48",
"9","13","14","16","24","49",
"3","18","19","25","44","45"
];
var arr = [];
var tmp = 0;
var IsElm = 0;
function indexe(){
for(var i=0; i<arrIns.length-1; i++)
{
if(arrIns[i] != arrIns[i+1]) { // arrIns[arrIns.Length - 1] = tmp;
IsElm = i; // i temp
arr[tmp++] = arrIns[i];
arrIns.splice(arrIns[IsElm]);
}
return --IsElm;
document.write(arr[tmp++] + " : " + arrIns.indexOf(arrIns[i]) + "<BR>");
//return arrIns.indexOf(arrIns[i]);
}
}Hakan cursed chats dealer :)
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If you are referring to array.reverse, then it is possible, even with IE 9.0 and as far back as IE 3.0. The browser doesn't affect Javascript features, only the revision (version) supported. Javascript features are not controlled by Microsoft, only the implementation. ECMA controls Javascript features. Most of the time I have to figure out (guess) what you want. And I don't always get a reply. a simple :thumbsup: or Yes, ok. or :thumbsdown: or No, not ok. I think your problem is storing numbers in strings, and applying C++ use (ie pointers) to them. Obviously the lack of computer books in your own language means that you could be learning from bad translation where the meaning of concepts is lost. Maybe you should learn English. Then the barriers to understanding won't slow you down.
"It's true that hard work never killed anyone. But I figure, why take the chance." - Ronald Reagan That's what machines are for. Got a problem? Sleep on it.
:thumbsup:
Hakan cursed chats dealer :)
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:thumbsup:
Hakan cursed chats dealer :)
I used to ur method
var arrIns = [
"1","21","24","28","42","48",
"9","13","14","16","24","49",
"3","18","19","25","44","45"
];
var arr = [];
var AllLucky= [];
var ct = 0;
var n = 0;do{
for(var i=arrIns.length; i>0; --i)
{
arrIns[i] = arr[i];
for(var j=0; j<arrIns.lenght; j++)
{
if(!arrIns[arr[j]]) {
arrIns[arr[j]] = AllLucky[ct];
document.write(AllLucky[ct] + "<BR>");
ct++; n++;
}
}
}
}while(n<1);output is 24 must be ?
Hakan cursed chats dealer :)
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I used to ur method
var arrIns = [
"1","21","24","28","42","48",
"9","13","14","16","24","49",
"3","18","19","25","44","45"
];
var arr = [];
var AllLucky= [];
var ct = 0;
var n = 0;do{
for(var i=arrIns.length; i>0; --i)
{
arrIns[i] = arr[i];
for(var j=0; j<arrIns.lenght; j++)
{
if(!arrIns[arr[j]]) {
arrIns[arr[j]] = AllLucky[ct];
document.write(AllLucky[ct] + "<BR>");
ct++; n++;
}
}
}
}while(n<1);output is 24 must be ?
Hakan cursed chats dealer :)
I will take a look at today's messages later tonight. there is spelling mistake, length
for(var j=0; j
:)
Q. Are you trying to create a 2D table that indexes all of arrIns?
0, "1"
12, "3"
6, "9"
.
.
11, "49"the line below is deleting arrIns[i] items.
problem is arr[i] = undefined (empty like c++ void).
so, arrIns[i] = undefined.arrIns[i] = arr[i];
Not enough code to test it.
I need array AllLucky. ;)"It's true that hard work never killed anyone. But I figure, why take the chance." - Ronald Reagan
That's what machines are for.
Got a problem?
Sleep on it. -
I used to ur method
var arrIns = [
"1","21","24","28","42","48",
"9","13","14","16","24","49",
"3","18","19","25","44","45"
];
var arr = [];
var AllLucky= [];
var ct = 0;
var n = 0;do{
for(var i=arrIns.length; i>0; --i)
{
arrIns[i] = arr[i];
for(var j=0; j<arrIns.lenght; j++)
{
if(!arrIns[arr[j]]) {
arrIns[arr[j]] = AllLucky[ct];
document.write(AllLucky[ct] + "<BR>");
ct++; n++;
}
}
}
}while(n<1);output is 24 must be ?
Hakan cursed chats dealer :)
please explain your signature: Hakan cursed chats dealer :) If you are just messing people about, I will stop helping right now. :mad:
"It's true that hard work never killed anyone. But I figure, why take the chance." - Ronald Reagan That's what machines are for. Got a problem? Sleep on it.
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please explain your signature: Hakan cursed chats dealer :) If you are just messing people about, I will stop helping right now. :mad:
"It's true that hard work never killed anyone. But I figure, why take the chance." - Ronald Reagan That's what machines are for. Got a problem? Sleep on it.
Just kidding!! Please don't offense on you.
Hakan cursed chats dealer :)
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Just kidding!! Please don't offense on you.
Hakan cursed chats dealer :)
ok. :| post message explain the arrays, differences AllLucky arrIns arr :confused: Help me to see what each one will look like at the end of code.
"It's true that hard work never killed anyone. But I figure, why take the chance." - Ronald Reagan That's what machines are for. Got a problem? Sleep on it.
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ok. :| post message explain the arrays, differences AllLucky arrIns arr :confused: Help me to see what each one will look like at the end of code.
"It's true that hard work never killed anyone. But I figure, why take the chance." - Ronald Reagan That's what machines are for. Got a problem? Sleep on it.
if(!arrIns[arr[j]])
is 24 AllLucky[ 24 ] differencly
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if(!arrIns[arr[j]])
is 24 AllLucky[ 24 ] differencly
9 10 38 40 46 48
there is no pick number this week too :) lotto combination is uselessness
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9 10 38 40 46 48
there is no pick number this week too :) lotto combination is uselessness
Q1. is arr[] lucky numbers to add to existing ? Q2. So, you want to add new set of lucky numbers to arrIns, but only if they do not exist in arrIns. Yes? =============================================== from what you told me before I thought old lucky numbers would get replaced var arrIns = [ "1","21","24","28","42","48", // week-2 is removed "9","10","38","40","46","48" // this is new week-2 set "9","13","14","16","24","49", "3","18","19","25","44","45", ]; or var arrIns = [ "1","21","24","28","42","48", "9","13","14","16","24","49", "3","18","19","25","44","45", "9","10","38","40","46","48" // new week-2 ]
"It's true that hard work never killed anyone. But I figure, why take the chance." - Ronald Reagan That's what machines are for. Got a problem? Sleep on it.
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9 10 38 40 46 48
there is no pick number this week too :) lotto combination is uselessness
If you get Java SE JRE7 & also install this Rhino Shell You can experiment with Javascript and learn things better. Using a web browser is no good for learning. I will help you get it set up and how to use it. :)
"It's true that hard work never killed anyone. But I figure, why take the chance." - Ronald Reagan That's what machines are for. Got a problem? Sleep on it.
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Documentation The lucky numbers, I want to compare the values that are encountering the same. Anyone can help on this topic?
. . if(arrLot\[i\] == arrIns\[18\]) if(arrLot\[i\] == arrIns\[19\]){ lucky\[add++\] = arrLot\[i\]; if(lucky\[add++\] = arrLot\[i\]) { lucky\[add++\] = gb; } }}
var gb = getBNS();
function getBNS()
{
var mf = 0;
return Math.floor(mf+=1);
}do{
if(gb.mf > 1){
lucky[ct].sort(function(a,b){
return a-b}); // end sort
}
document.write(lucky[ct] + " : " + gb + "<BR>");
ct++;
}while(ct<17);mesela burada 18 adet sayı elemanlarını kendi aralarında karşılaştırdıktan sonra hangi sayının ne kadar karşılaştığını hesaplayan ve dökümanlayan bir kod yazmaya çalışıyorum. Tanımla problemi var. mesela şöyle bir çıktı veriyor:
<pre>
Undefined : 1 Undefined : 1 Undefined : 1 Undefined : 1
var arrIns = [
"1","21","24","28","42","48",
"9","13","14","16","24","49",
"3","18","19","25","44","45"
];Burada çıktı
24 : 2
1 : 1
21 : 1olmalı..
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If you get Java SE JRE7 & also install this Rhino Shell You can experiment with Javascript and learn things better. Using a web browser is no good for learning. I will help you get it set up and how to use it. :)
"It's true that hard work never killed anyone. But I figure, why take the chance." - Ronald Reagan That's what machines are for. Got a problem? Sleep on it.
Thanks for Java SDKs