working out a triangle hypotenuse
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I am looking for my C# class to firstly work out distance between two coordinate points on the x plane and then work out the distance between the same coordinated points on the y plane. There are potentially several ways of doing this. I was thinking: Firstly calculate distance on the x plane (x1->x2): in Excel form:
if (x2 > x1, x2 - x1, x1 - x2)
(then) (else)Then calculate the distance for the y plane (y1->y2):
if (x2 > x1, x2 - x1, x1 - x2)
if we then think of a triangle (with right angle) we have A(squared) + B(squared) = C(squared) We would have the length A and B and therefore would be able to calculate C. Is there an easy way of doing this in C# or is it best to code out the equations? Any advise appreciated.
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I am looking for my C# class to firstly work out distance between two coordinate points on the x plane and then work out the distance between the same coordinated points on the y plane. There are potentially several ways of doing this. I was thinking: Firstly calculate distance on the x plane (x1->x2): in Excel form:
if (x2 > x1, x2 - x1, x1 - x2)
(then) (else)Then calculate the distance for the y plane (y1->y2):
if (x2 > x1, x2 - x1, x1 - x2)
if we then think of a triangle (with right angle) we have A(squared) + B(squared) = C(squared) We would have the length A and B and therefore would be able to calculate C. Is there an easy way of doing this in C# or is it best to code out the equations? Any advise appreciated.
Feels like you need to find out the distance between 2 points on a 2D plane. Point A (x1,y1) Point B (x2,y2) Distance between them would be=[((x1-x2)^2)+((y1-y2)^2)]^(1/2) Use Math.Abs method to get the absolute value of the distance regardless of x1>x2 or x1
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Feels like you need to find out the distance between 2 points on a 2D plane. Point A (x1,y1) Point B (x2,y2) Distance between them would be=[((x1-x2)^2)+((y1-y2)^2)]^(1/2) Use Math.Abs method to get the absolute value of the distance regardless of x1>x2 or x1
This looks like a good approach. I am really new to C# (after 10 years away), do you have a coded example?
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This looks like a good approach. I am really new to C# (after 10 years away), do you have a coded example?
Its basic maths buddy.. :) Let me try to write a simple app for you. Distance between points (5,5) and the origin (0,0) should be: public CalculateDistance() { double D; int x1=5; int x2=0; int y1=5; int y2=0; D=Math.Abs(((x1-x2)^2)+((y1-y2)^2))^(1/2); Console.WriteLine(D); Console.ReadKey(); } The above should do good. -Anurag
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I am looking for my C# class to firstly work out distance between two coordinate points on the x plane and then work out the distance between the same coordinated points on the y plane. There are potentially several ways of doing this. I was thinking: Firstly calculate distance on the x plane (x1->x2): in Excel form:
if (x2 > x1, x2 - x1, x1 - x2)
(then) (else)Then calculate the distance for the y plane (y1->y2):
if (x2 > x1, x2 - x1, x1 - x2)
if we then think of a triangle (with right angle) we have A(squared) + B(squared) = C(squared) We would have the length A and B and therefore would be able to calculate C. Is there an easy way of doing this in C# or is it best to code out the equations? Any advise appreciated.
Your question states that what you want is the size of the distance between two x co-ordinates, and the size of the distance between two y co-ordinates, but your code suggests that what you really want is the length of a line between the two points: which is the hypotenuse of a right triangle. Assuming it's obvious to you how to get the distances on x, and y, and since you already know how to calculate a hypotenuse, then the answer to your question is: no, C# does not contain a built-in function to calculate a hypotenuse. Yes, you have to code it. And, the real answer to your question is that you need to focus on mastery of the basic mathematics operators in C#, and you need to examine the functions available in the Math library, and get familiar with what it offers, and what it does not offer. A small effort on your part now to learn the basic mathematics operators, and commonly used functions in the Math library, will enable you to express any equation. It's a good idea to think carefully about what you are asking, before you post a question.
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