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Need help on chat between two computers

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  • OriginalGriffO OriginalGriff

    Where do you get the error? Which line?

    Those who fail to learn history are doomed to repeat it. --- George Santayana (December 16, 1863 – September 26, 1952) Those who fail to clear history are doomed to explain it. --- OriginalGriff (February 24, 1959 – ∞)

    L Offline
    L Offline
    larsp777
    wrote on last edited by
    #7

    Ok... The other guy whose thread I can´t se now wrote: I'm guessing that's the line that's causing the problem. The callback method will be called on a background thread; you will need to use InvokeRequired and Invoke to get back to the UI thread when you want to access the form's controls. Invoke((Action<object>)listMessage.Items.Add, "Friend: " + receivedMessage); I Think he was right about the line. Tried to do change the line accordingly but got an error:

    int System.Windows.Forms.ListBox.ObjectCollection.Add(object)' has the wrong return type

    Richard DeemingR 1 Reply Last reply
    0
    • OriginalGriffO OriginalGriff

      Where do you get the error? Which line?

      Those who fail to learn history are doomed to repeat it. --- George Santayana (December 16, 1863 – September 26, 1952) Those who fail to clear history are doomed to explain it. --- OriginalGriff (February 24, 1959 – ∞)

      L Offline
      L Offline
      larsp777
      wrote on last edited by
      #8

      The error occurs when I try to send a message. It occurs on both computers. When I send from one computer the error shows on the other.

      1 Reply Last reply
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      • L larsp777

        Ok... The other guy whose thread I can´t se now wrote: I'm guessing that's the line that's causing the problem. The callback method will be called on a background thread; you will need to use InvokeRequired and Invoke to get back to the UI thread when you want to access the form's controls. Invoke((Action<object>)listMessage.Items.Add, "Friend: " + receivedMessage); I Think he was right about the line. Tried to do change the line accordingly but got an error:

        int System.Windows.Forms.ListBox.ObjectCollection.Add(object)' has the wrong return type

        Richard DeemingR Offline
        Richard DeemingR Offline
        Richard Deeming
        wrote on last edited by
        #9

        larsp777 wrote:

        int System.Windows.Forms.ListBox.ObjectCollection.Add(object)' has the wrong return type

        Whoops - didn't notice that the method returned an int. The delegate type will need to be a Func<object, int> instead of an Action<object>.

        Invoke((Func<object, int>)listMessage.Items.Add, "Friend: " + receivedMessage);


        "These people looked deep within my soul and assigned me a number based on the order in which I joined." - Homer

        "These people looked deep within my soul and assigned me a number based on the order in which I joined" - Homer

        OriginalGriffO L 3 Replies Last reply
        0
        • Richard DeemingR Richard Deeming

          larsp777 wrote:

          int System.Windows.Forms.ListBox.ObjectCollection.Add(object)' has the wrong return type

          Whoops - didn't notice that the method returned an int. The delegate type will need to be a Func<object, int> instead of an Action<object>.

          Invoke((Func<object, int>)listMessage.Items.Add, "Friend: " + receivedMessage);


          "These people looked deep within my soul and assigned me a number based on the order in which I joined." - Homer

          OriginalGriffO Offline
          OriginalGriffO Offline
          OriginalGriff
          wrote on last edited by
          #10

          :thumbsup:

          Those who fail to learn history are doomed to repeat it. --- George Santayana (December 16, 1863 – September 26, 1952) Those who fail to clear history are doomed to explain it. --- OriginalGriff (February 24, 1959 – ∞)

          "I have no idea what I did, but I'm taking full credit for it." - ThisOldTony
          "Common sense is so rare these days, it should be classified as a super power" - Random T-shirt

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          • Richard DeemingR Richard Deeming

            larsp777 wrote:

            int System.Windows.Forms.ListBox.ObjectCollection.Add(object)' has the wrong return type

            Whoops - didn't notice that the method returned an int. The delegate type will need to be a Func<object, int> instead of an Action<object>.

            Invoke((Func<object, int>)listMessage.Items.Add, "Friend: " + receivedMessage);


            "These people looked deep within my soul and assigned me a number based on the order in which I joined." - Homer

            L Offline
            L Offline
            larsp777
            wrote on last edited by
            #11

            Thanks, Richard, it worked! Well, thank you both for helping me out!

            1 Reply Last reply
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            • L larsp777

              I have used this tutorial to make a chat: http://www.youtube.com/watch?v=BDVfpPq3weo[^] It works on the same computer but not between two. The problem seem so be that I need more than one thread. I get Cross-thread operation not valid.

              L Offline
              L Offline
              larsp777
              wrote on last edited by
              #12

              Can you mark a question as solved. You really solved it Richard but Griffin also helped. I am working on a game for XNA and need both computers to have access to the same "board". Do you know anything about that?

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              • OriginalGriffO OriginalGriff

                No, the problem is the reverse of that: "Cross-thread operation not valid" means that you are executing code on one thread that can only be executed on a different thread: normally, this occurs when you try to update a control from a different thread to that from which it was created (which must be the UI thread), either in a BackgoundWorker, a Thread instance or in the handler of a communications class that uses threading to handle it's events (the SerialPort does this for example). Check your code: you may just have to start invoking the control instead of accessing it directly. For example:

                    private void AddNewTab(string tabName)
                        {
                        if (InvokeRequired)
                            {
                            Invoke(new MethodInvoker(delegate { AddNewTab(tabName); }));
                            }
                        else
                            {
                            TabPage tp = new TabPage(tabName);
                            myTabControl.TabPages.Add(tp);
                            }
                        }
                

                Those who fail to learn history are doomed to repeat it. --- George Santayana (December 16, 1863 – September 26, 1952) Those who fail to clear history are doomed to explain it. --- OriginalGriff (February 24, 1959 – ∞)

                R Offline
                R Offline
                Rahul VB
                wrote on last edited by
                #13

                hey OG, please enlighten me more on this.

                OriginalGriffO 1 Reply Last reply
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                • R Rahul VB

                  hey OG, please enlighten me more on this.

                  OriginalGriffO Offline
                  OriginalGriffO Offline
                  OriginalGriff
                  wrote on last edited by
                  #14

                  Sorry Rahul, but it's a huge subject - I couldn't begin to do it justice in a small text box! :laugh: There are some good tutorials out there which explain threading and the UI pretty well: http://stuff.seans.com/2009/05/21/net-basics-do-work-in-background-thread-to-keep-gui-responsive/[^] (Backgound and why to thread) http://www.dreamincode.net/forums/topic/246911-c%23-multi-threading-in-a-gui-environment/[^] (Fairly advanced) But basically when you start to use multiple threads you can't touch any controls, except from the thread that created them - which is called the UI thread (for User Interface) and is the original thread the form started on. If you try, you will get a "cross-threading" error telling you not to do that. The only way to get round it is to Invoke the control - which basically requests the UI thread to do the work for you. Have a look at the BackgroundWorker thread - it provides a way to update the display without invoking via the ProgressChanged event, which is executed on the original thread.

                  Those who fail to learn history are doomed to repeat it. --- George Santayana (December 16, 1863 – September 26, 1952) Those who fail to clear history are doomed to explain it. --- OriginalGriff (February 24, 1959 – ∞)

                  "I have no idea what I did, but I'm taking full credit for it." - ThisOldTony
                  "Common sense is so rare these days, it should be classified as a super power" - Random T-shirt

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                  • Richard DeemingR Richard Deeming

                    larsp777 wrote:

                    int System.Windows.Forms.ListBox.ObjectCollection.Add(object)' has the wrong return type

                    Whoops - didn't notice that the method returned an int. The delegate type will need to be a Func<object, int> instead of an Action<object>.

                    Invoke((Func<object, int>)listMessage.Items.Add, "Friend: " + receivedMessage);


                    "These people looked deep within my soul and assigned me a number based on the order in which I joined." - Homer

                    L Offline
                    L Offline
                    larsp777
                    wrote on last edited by
                    #15

                    Do you know if there is a simple way for a third person can listen in what the others are Writing. (only has to listen to the sender) I am making an application where you should be able to simulate someone eavesdropping the conversation.

                    Richard DeemingR 1 Reply Last reply
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                    • L larsp777

                      Do you know if there is a simple way for a third person can listen in what the others are Writing. (only has to listen to the sender) I am making an application where you should be able to simulate someone eavesdropping the conversation.

                      Richard DeemingR Offline
                      Richard DeemingR Offline
                      Richard Deeming
                      wrote on last edited by
                      #16

                      If all the computers are on the same LAN, you could use the broadcast address so that any computer can pick up the messages: Broadcasting Using Socket-Oriented Approach[^] If they're on different networks, or you don't want the overhead associated with broadcasting, then you'll need to use multicasting: IP Multicasting in C#[^]


                      "These people looked deep within my soul and assigned me a number based on the order in which I joined." - Homer

                      "These people looked deep within my soul and assigned me a number based on the order in which I joined" - Homer

                      L 1 Reply Last reply
                      0
                      • Richard DeemingR Richard Deeming

                        If all the computers are on the same LAN, you could use the broadcast address so that any computer can pick up the messages: Broadcasting Using Socket-Oriented Approach[^] If they're on different networks, or you don't want the overhead associated with broadcasting, then you'll need to use multicasting: IP Multicasting in C#[^]


                        "These people looked deep within my soul and assigned me a number based on the order in which I joined." - Homer

                        L Offline
                        L Offline
                        larsp777
                        wrote on last edited by
                        #17

                        Thanks! It will probebly be on the same LAN.

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