Puzzle

[srinivas vadepally]

11*11=4 22*22=16 ' ' ' 10*10=?

[thatraja]

0?

thatraja

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[JMK NI]

1? You're adding the numbers on each side of the operator together and multiplying them right?

[Agent__007]

1 And what happened? I thought you were visiting QA. :laugh:

Whether I think I can, or think I can't, I am always bloody right!

[Duncan Edwards Jones]

1

[Lost User]

Underspecified.

[Marc Clifton]

2 (1 + 0 + 1 + 0 ) * 1 = 2 Marc

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[Nicholas Marty]

1048576? :)

[OriginalGriff]

42

Those who fail to learn history are doomed to repeat it. --- George Santayana (December 16, 1863 – September 26, 1952) Those who fail to clear history are doomed to explain it. --- OriginalGriff (February 24, 1959 – ∞)

[Gupta Poonam]

1

[Argonia]

Overflow Exception

Microsoft ... the only place where VARIANT_TRUE != true

[Argonia]

Damn it, you beat me to it :)

Microsoft ... the only place where VARIANT_TRUE != true

[Dennis_E]

11*11 = 121 -> sum of digits = 4 22*22 = 484 -> sum of digits = 16 10*10 = 100 -> sum of digits = 1

[WuRunZhe]

1 Reason is like that? 11*11=4 means (1+1)*(1+1)=4 22*22=16 means (2+2)*(2+2)=16 so 10*10=(1+0)*(1+0)=1. :)

[Max Methot]

Smart thinking! I saw it differently, but I don't know if it would have applied for all cases: 11*11 -> (1+1)*(1+1) -> 2*2 = 4 22*22 -> (2+2)*(2+2) -> 4*4 = 16 10*10 -> (1+0)*(1+0) -> 1*1 = 1

[Lost User]

You've got the first two wrong and you want me to solve the third one for you?

[Lost User]

I'm sorry, my responses are limited. You must ask the right questions.

Peter Wasser "The whole problem with the world is that fools and fanatics are always so certain of themselves, and wiser people so full of doubts." - Bertrand Russell

[glennPattonWork3]

Quote:

10*10=(1+0)*(1+1)=1.

should that be (1+0)*(1+0) = 1, as I'm pretty sure (1+0)*(1+1) gives 1*2 = 2 or am I missing something?

[Lost User]

ok, where did you hide MH370?

[Lost User]

Which proves the problem is underspecified.

One day I aspire to having a signature.