TWCP OTD - 2nd of March, 2017
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How is turning on the flashlight in my cell phone complicated? I can do that in about five seconds :-D Or are you suggesting just opening the door? Because you never said it was light OUTSIDE the room.
Proud to have finally moved to the A-Ark. Which one are you in?
Author of the Guardians Saga (Sci-Fi/Fantasy novels)After you turned on the flashlight, you still have to scan all the coins, that will take some time... See the comment from Nagy (he may had an extra gin) below...
Skipper: We'll fix it. Alex: Fix it? How you gonna fix this? Skipper: Grit, spit and a whole lotta duct tape.
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The two piles - together - should contains all the coins in the room...
Skipper: We'll fix it. Alex: Fix it? How you gonna fix this? Skipper: Grit, spit and a whole lotta duct tape.
I think I figured it out. My last guess (though it didn't account for all the coins) was on the right track. Take a simple example of TTTHHHHHHH (7 heads, 3 tails). If you take three coins you'll get either {TTT}, {TTH}, {THH}, or {HHH} leaving {HHHHHHH}, {THHHHHH}, {TTHHHHH}, or {TTTHHHH} respectively. Those don't match up, but if you notice, flipping what was taken yields equal tails (example: {TTH} -> {HHT}, {THHHHHHH} = 1T each). This flipping works by removing coins equal to the number of tails. By subsequently flipping the coins, this set now contains a number of a heads equal to the number of tails removed from the original set and a number of tails equal to the number of heads removed from the original set. This naturally balances out the number of tails in each set. An example: 10 tails {TTTTTTTTTT}. Let's remove 6 tails {TTTT}. Those 6 tails are now in the taken set {TTTTTT}. We need 10 total coins though, so we must have taken 4 heads as well {TTTTTTHHHH}. Because we removed the same number of total coins as the number of total tails, whatever amount left in the original set in tails must be represented as heads in the taken set. Thus after the flip we now have {HHHHHHTTTT} which has 4 Ts just like the original set {TTTT}. So for your question: Pick 14 coins, any coins, and flip them. Done.
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After you turned on the flashlight, you still have to scan all the coins, that will take some time... See the comment from Nagy (he may had an extra gin) below...
Skipper: We'll fix it. Alex: Fix it? How you gonna fix this? Skipper: Grit, spit and a whole lotta duct tape.
Damn, and I was only one step away from suggesting burning down the room so all the coins would be so scorched that none of them would be showing heads OR tails. And he had to go and post an actual answer... How's a guy supposed to troll in this kind of environment? :laugh:
Proud to have finally moved to the A-Ark. Which one are you in?
Author of the Guardians Saga (Sci-Fi/Fantasy novels) -
Turn 14 coins over in one pile and all the others go into the second pile. Whichever 14 you turn over, there will be the same number of tails on both piles.
veni bibi saltavi
That works, but my answers were more entertaining ;P
Proud to have finally moved to the A-Ark. Which one are you in?
Author of the Guardians Saga (Sci-Fi/Fantasy novels) -
I think I figured it out. My last guess (though it didn't account for all the coins) was on the right track. Take a simple example of TTTHHHHHHH (7 heads, 3 tails). If you take three coins you'll get either {TTT}, {TTH}, {THH}, or {HHH} leaving {HHHHHHH}, {THHHHHH}, {TTHHHHH}, or {TTTHHHH} respectively. Those don't match up, but if you notice, flipping what was taken yields equal tails (example: {TTH} -> {HHT}, {THHHHHHH} = 1T each). This flipping works by removing coins equal to the number of tails. By subsequently flipping the coins, this set now contains a number of a heads equal to the number of tails removed from the original set and a number of tails equal to the number of heads removed from the original set. This naturally balances out the number of tails in each set. An example: 10 tails {TTTTTTTTTT}. Let's remove 6 tails {TTTT}. Those 6 tails are now in the taken set {TTTTTT}. We need 10 total coins though, so we must have taken 4 heads as well {TTTTTTHHHH}. Because we removed the same number of total coins as the number of total tails, whatever amount left in the original set in tails must be represented as heads in the taken set. Thus after the flip we now have {HHHHHHTTTT} which has 4 Ts just like the original set {TTTT}. So for your question: Pick 14 coins, any coins, and flip them. Done.
Right answer. Over-complicated explanation... :-D
Skipper: We'll fix it. Alex: Fix it? How you gonna fix this? Skipper: Grit, spit and a whole lotta duct tape.
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Damn, and I was only one step away from suggesting burning down the room so all the coins would be so scorched that none of them would be showing heads OR tails. And he had to go and post an actual answer... How's a guy supposed to troll in this kind of environment? :laugh:
Proud to have finally moved to the A-Ark. Which one are you in?
Author of the Guardians Saga (Sci-Fi/Fantasy novels)That's the gin. No cure for it!
Skipper: We'll fix it. Alex: Fix it? How you gonna fix this? Skipper: Grit, spit and a whole lotta duct tape.
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Right answer. Over-complicated explanation... :-D
Skipper: We'll fix it. Alex: Fix it? How you gonna fix this? Skipper: Grit, spit and a whole lotta duct tape.
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Let see... After you separate 14 coins from the rest there is exactly n coins with tails in that pile... In the other pile there is 14 - n... Now flip the coins in the pile of 14, now it has 14 - n coins with tails, just as in the other pile...
Skipper: We'll fix it. Alex: Fix it? How you gonna fix this? Skipper: Grit, spit and a whole lotta duct tape.
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Let see... After you separate 14 coins from the rest there is exactly n coins with tails in that pile... In the other pile there is 14 - n... Now flip the coins in the pile of 14, now it has 14 - n coins with tails, just as in the other pile...
Skipper: We'll fix it. Alex: Fix it? How you gonna fix this? Skipper: Grit, spit and a whole lotta duct tape.
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Let see... After you separate 14 coins from the rest there is exactly n coins with tails in that pile... In the other pile there is 14 - n... Now flip the coins in the pile of 14, now it has 14 - n coins with tails, just as in the other pile...
Skipper: We'll fix it. Alex: Fix it? How you gonna fix this? Skipper: Grit, spit and a whole lotta duct tape.
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ALL ABOUT COUNTING RIGHT In a dark room (so you can't actually recognize the coins, but feel and mover them only) there are 284 coins scattered on the floor. It is known that only 14 hast their tail upward. Create two piles of coins - using all the coins in the room - with the same number of coins with their tails up...
Skipper: We'll fix it. Alex: Fix it? How you gonna fix this? Skipper: Grit, spit and a whole lotta duct tape.
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ALL ABOUT COUNTING RIGHT In a dark room (so you can't actually recognize the coins, but feel and mover them only) there are 284 coins scattered on the floor. It is known that only 14 hast their tail upward. Create two piles of coins - using all the coins in the room - with the same number of coins with their tails up...
Skipper: We'll fix it. Alex: Fix it? How you gonna fix this? Skipper: Grit, spit and a whole lotta duct tape.
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Turn 14 coins over in one pile and all the others go into the second pile. Whichever 14 you turn over, there will be the same number of tails on both piles.
veni bibi saltavi
Well spotted.
I wanna be a eunuchs developer! Pass me a bread knife!
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ALL ABOUT COUNTING RIGHT In a dark room (so you can't actually recognize the coins, but feel and mover them only) there are 284 coins scattered on the floor. It is known that only 14 hast their tail upward. Create two piles of coins - using all the coins in the room - with the same number of coins with their tails up...
Skipper: We'll fix it. Alex: Fix it? How you gonna fix this? Skipper: Grit, spit and a whole lotta duct tape.
Make a pile of all the coins. Take 14 from there to make the second pile. Turn all the coins in the second pile upside down. the pile: H:270 T:14 two piles: H:270-t T:t; H:t T:14-t (t is whatever number of tails in the big pile) upside down the small pile: H:270-t T:t; H:14-t T:t (Done). Ooh, ooh. (Anyone notice the error in my answer to the ant on the rope? - should have been exp(100)-1 seconds. I had stopped the ant at the starting point of the other post rather than where it had moved to. - So I now agree with the other responder except I think he used 364 days in a year??)
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Easy. Just say "Thank God we don't live in Medieaval times", and turn the light on.
I wanna be a eunuchs developer! Pass me a bread knife!
If we do not live in medieval times, why should we thank God? And al-Khwārizmī - who lived even before - was able to solve it without electricity...
Skipper: We'll fix it. Alex: Fix it? How you gonna fix this? Skipper: Grit, spit and a whole lotta duct tape.
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Make a pile of all the coins. Take 14 from there to make the second pile. Turn all the coins in the second pile upside down. the pile: H:270 T:14 two piles: H:270-t T:t; H:t T:14-t (t is whatever number of tails in the big pile) upside down the small pile: H:270-t T:t; H:14-t T:t (Done). Ooh, ooh. (Anyone notice the error in my answer to the ant on the rope? - should have been exp(100)-1 seconds. I had stopped the ant at the starting point of the other post rather than where it had moved to. - So I now agree with the other responder except I think he used 364 days in a year??)
Member 12255252 wrote:
Anyone notice the error in my answer to the ant on the rope?
Yes, we all noticed. That's why we don't believe anything you say, any more.
I wanna be a eunuchs developer! Pass me a bread knife!
