Programming Question of the Week?
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Always too small...
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radius = circumference / (2*Pi), of course!
If you have an important point to make, don't try to be subtle or clever. Use a pile driver. Hit the point once. Then come back and hit it again. Then hit it a third time - a tremendous whack. --Winston Churchill
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radius = circumference / (2*Pi), of course!
If you have an important point to make, don't try to be subtle or clever. Use a pile driver. Hit the point once. Then come back and hit it again. Then hit it a third time - a tremendous whack. --Winston Churchill
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circumference = 2*Pi*radius Infinite Loop: see Infinite Loop :)
If you have an important point to make, don't try to be subtle or clever. Use a pile driver. Hit the point once. Then come back and hit it again. Then hit it a third time - a tremendous whack. --Winston Churchill
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circumference/Pie*R*Round -r (recursive)
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The same as the radius of a circular argument.
I'm gonna build a wall around my cubical and make Mexico pay for it!
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Infinite. ;) Marc
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The same as the radius of a circular argument.
I'm gonna build a wall around my cubical and make Mexico pay for it!
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circumference = 2*Pi*radius Infinite Loop: see Infinite Loop :)
If you have an important point to make, don't try to be subtle or clever. Use a pile driver. Hit the point once. Then come back and hit it again. Then hit it a third time - a tremendous whack. --Winston Churchill
This is how buffer overruns occur. If the radius is too little, the circumference won't have enough room for all the buffer elements.
Immanentize the Eschaton!
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radius = circumference / (2*Pi), of course!
If you have an important point to make, don't try to be subtle or clever. Use a pile driver. Hit the point once. Then come back and hit it again. Then hit it a third time - a tremendous whack. --Winston Churchill
r = c / (2 * π)Software Zen:
delete this;
