java.net.SocketException: Software caused connection abort: socket write error

Django_Untaken

Hello there. I am trying to send images (byte[] data) to web browser using java. I am doing this in a while(true) loop. My ClientThread sends one image only. After that, it starts producing this exception. Here is what I have tried so far

Overview

1- MainThread starts ServerThread
2- ServerThread start ClientThread
3- ClientThread has a loop. In this loop, I read next image and pass it to MovieWriter (which writes it to DataOutputStream of clientSocket) with a delay of 50ms

class ClientThread extends Thread
{
@Overrie
public void run()
{
OutputStream outStream = clientSocket.getOutputStream(); // clientSocket = class variable
DataOutputStream dataOutStream = new DataOutputStream(outStream);

MovieWriter mv = new MovieWriter(dataOutStream);
mv.WriterHttpHeader();
while(true)
{
  Thread.sleep(50);
  ByteArrayOutputStream image = ReadImage.GetNext(); // 'ReadImage' is static class which returns the next image
  mv.WriteNextImage(image.toByteArray());
}

}
}

class MovieWriter
{
public MovieWriter(DataOutputStream)
{
// set class variable
}

public void WriterHttpHeader()
{
String header = "HTTP/1.1 200 OK \r\n Content-Type: multipart/x-mixed-replace; boundary=--boundary";
dataOutputStream.write(GetBytes(header)); // dataOutputStream = class variable; GetBytes() return bytes of header
}

public void WriteNextImage(byte[] data)
{
try
{
String response = "Content-Type: image/jpg \r\n" + "Content-Length: " + String.ValueOf(data.length);
dataOutputStream.write(GetBytes(response)); // first write response header
dataOutputStream.write(data); // then write image data
} catch(Exception ex) {
ex.printStackTrace();
}
}

}

Again, when the while loop in ClientThread runs, MovieWriter sends one image only. After that, it raises the said exception. What am I doing wrong? Thanks for anything you share :) NOTE: I cut this code short for better understanding. If you need more code, I can provide

Lost User

It seems to me that your logic is the wrong way round. A web browser is a client application that requests information form a web server. So your 'client' should be a server, which sends images based on requests from the browser, rather than trying to push them to a browser that is not expecting them.

Django_Untaken

Richard MacCutchan wrote:

So your 'client' should be a server .....

- I have a 'ServerThread' (one and only one server thread) - The piece of code that serves images, upon request, is known as 'ClientThread' - This 'ServerThread' can start N number of 'ClientThread', against N number of requests from web browser. And YES. Good naming conventions help understand better. 'ClientThread' could better be named as 'RequestThread'. But the problem still remains. My browser display ONE picture, sent from my server. After that ONE picture, it starts throwing said exception.

Lost User

Second attempt at adding this comment ... It seems to me that your logic is the wrong way round. Sending an image (or any HTML response) to a web browser, is usually the result of a request from the browser to the server. The way you have it, you are trying to push data to the browser when it may not be expecting it, so there will be no connection between the two.

Lost User

Well, as I suggested above, that is because the browser is not expecting it. Your server thread should only be sending an image when the browser sends it a request.

Django_Untaken

Richard MacCutchan wrote:

Well, as I suggested above, that is because the browser is not expecting it.

Perhaps I am having tough time understanding you. Please bear with me. To the best of my knowledge, I am sending only the images and nothing else. I also tried removing the header just before I transmit the image, even that does not help. :(

Lost User

At the risk of repeatedly repeating myself ... You cannot send unsolicited messages to a web browser, they do not work that way.