Fail to call Sub from Async method

[Mc_Topaz]

I need to call a method (returning void) in an async method. I have problem with the syntax of the Task.Run() in VB. I have a working example in C#. So it's just another: "Parse-this-line-from-C#-into-VB-and-it-should-work". VB-code

Module Module1

Sub Main()
    Console.WriteLine("Start of Run")
    Run()
    Console.WriteLine("End of Run")
    Console.ReadLine()
End Sub

Async Sub Run()
    Dim arg = "LEET 1337"
    Await Threading.Tasks.Task.Run(Function() Foo(arg)) ' This line fails...
End Sub

Sub Foo(ByVal asdf As String)
    Console.WriteLine("Start of Foo")
    Threading.Thread.Sleep(5000)
    Console.WriteLine(asdf)
    Console.WriteLine("End of Foo")
End Sub

End Module

C#-code

using System;
using System.Threading;
using System.Threading.Tasks;

namespace ConsoleApplication
{
class Program
{
static void Main(string[] args)
{
Console.WriteLine("Start Run");
Run();
Console.WriteLine("End of Run");
Console.ReadLine();
}

    static async void Run()
    {
        var arg = "LEET 1337";
        await Task.Run(() => Foo(arg)); // This line works.
    }

    static void Foo(string asdf)
    {
        Console.WriteLine("Start Foo");
        Thread.Sleep(5000);
        Console.WriteLine(asdf);
        Console.WriteLine("End of Foo");
    }
}

}

[Richard Deeming]

Try:

Await Threading.Tasks.Task.Run(Sub() Foo(arg))

Lambda Expressions - Visual Basic | Microsoft Docs[^]

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"These people looked deep within my soul and assigned me a number based on the order in which I joined." - Homer

[Mc_Topaz]

Of course I have to switch Function() to Sub() :doh: Thank you for the correction!