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  4. Okay, real C++ question - who makes use of the auto keyword?

Okay, real C++ question - who makes use of the auto keyword?

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  • C charlieg

    I'm trying to straighten out some pointer "arithmetic" in some existing code. The expressions themselves are overly ambiguous to say the least. In part of my readings, I've come across the "auto" keyword where the compiler deduces what type I need. At least that's what I got from all of the verbiage. This seems a) dangerous and b) adds another level of mental indirection to what you are trying to accomplish. To me, software needs to be very clear and explicit in what data you are working with and what you intend to do with it. A lot of the "here is how auto will help you" descriptions justify it by saving typing when trying to make use of other classes, templates and the like. It feels like the C++ committee came up with a feature A then added feature B to make using A easier. I'm now doing battle with lambda expressions - another story. So, in your code - do you make extensive use of auto, and how does it help you?

    Charlie Gilley “They who can give up essential liberty to obtain a little temporary safety deserve neither liberty nor safety.” BF, 1759 Has never been more appropriate.

    CPalliniC Offline
    CPalliniC Offline
    CPallini
    wrote on last edited by
    #5

    I use it. Suppose you have

    unordered_map um{ {"foo", 1}, {"goo", 2}, {"boo",42}};

    I find

    for (const auto & p : um)
    {
    cout << p.first << ", " << p.second << "\n";
    }

    'somewhat simpler' when compared to

    for (const pair & p : um)
    {
    cout << p.first << ", " << p.second << "\n";
    }

    Maybe I am used to it.

    "In testa che avete, Signor di Ceprano?" -- Rigoletto

    In testa che avete, signor di Ceprano?

    1 Reply Last reply
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    • C charlieg

      I'm trying to straighten out some pointer "arithmetic" in some existing code. The expressions themselves are overly ambiguous to say the least. In part of my readings, I've come across the "auto" keyword where the compiler deduces what type I need. At least that's what I got from all of the verbiage. This seems a) dangerous and b) adds another level of mental indirection to what you are trying to accomplish. To me, software needs to be very clear and explicit in what data you are working with and what you intend to do with it. A lot of the "here is how auto will help you" descriptions justify it by saving typing when trying to make use of other classes, templates and the like. It feels like the C++ committee came up with a feature A then added feature B to make using A easier. I'm now doing battle with lambda expressions - another story. So, in your code - do you make extensive use of auto, and how does it help you?

      Charlie Gilley “They who can give up essential liberty to obtain a little temporary safety deserve neither liberty nor safety.” BF, 1759 Has never been more appropriate.

      Greg UtasG Offline
      Greg UtasG Offline
      Greg Utas
      wrote on last edited by
      #6

      The only time I don't use auto is to override the type that the compiler would deduce. That's very rare, usually with the size of a numeric. auto is almost always a type returned by a function, or maybe the type of a class member, so there's nothing "dangerous" about it in those situations. Someone reading the code needs to be familiar with the functions and classes being used, or they're fooling themselves as to their level of understanding.

      Robust Services Core | Software Techniques for Lemmings | Articles
      The fox knows many things, but the hedgehog knows one big thing.

      <p><a href="https://github.com/GregUtas/robust-services-core/blob/master/README.md">Robust Services Core</a>
      <em>The fox knows many things, but the hedgehog knows one big thing.</em></p>

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      • C charlieg

        I'm trying to straighten out some pointer "arithmetic" in some existing code. The expressions themselves are overly ambiguous to say the least. In part of my readings, I've come across the "auto" keyword where the compiler deduces what type I need. At least that's what I got from all of the verbiage. This seems a) dangerous and b) adds another level of mental indirection to what you are trying to accomplish. To me, software needs to be very clear and explicit in what data you are working with and what you intend to do with it. A lot of the "here is how auto will help you" descriptions justify it by saving typing when trying to make use of other classes, templates and the like. It feels like the C++ committee came up with a feature A then added feature B to make using A easier. I'm now doing battle with lambda expressions - another story. So, in your code - do you make extensive use of auto, and how does it help you?

        Charlie Gilley “They who can give up essential liberty to obtain a little temporary safety deserve neither liberty nor safety.” BF, 1759 Has never been more appropriate.

        M Offline
        M Offline
        Maximilien
        wrote on last edited by
        #7

        I use auto as much as I can. I will still use types for POD. I also use variable names that makes sense so that I know what type the variable should be (obviously not hungarian reverse or not notation)

        CI/CD = Continuous Impediment/Continuous Despair

        C 1 Reply Last reply
        0
        • M Maximilien

          I use auto as much as I can. I will still use types for POD. I also use variable names that makes sense so that I know what type the variable should be (obviously not hungarian reverse or not notation)

          CI/CD = Continuous Impediment/Continuous Despair

          C Offline
          C Offline
          charlieg
          wrote on last edited by
          #8

          POD?

          Charlie Gilley “They who can give up essential liberty to obtain a little temporary safety deserve neither liberty nor safety.” BF, 1759 Has never been more appropriate.

          M 1 Reply Last reply
          0
          • C charlieg

            POD?

            Charlie Gilley “They who can give up essential liberty to obtain a little temporary safety deserve neither liberty nor safety.” BF, 1759 Has never been more appropriate.

            M Offline
            M Offline
            Maximilien
            wrote on last edited by
            #9

            Plain Old Data. usually simple types like int, char, float...

            CI/CD = Continuous Impediment/Continuous Despair

            T 1 Reply Last reply
            0
            • M Maximilien

              Plain Old Data. usually simple types like int, char, float...

              CI/CD = Continuous Impediment/Continuous Despair

              T Offline
              T Offline
              trønderen
              wrote on last edited by
              #10

              It appears to me that you may be doing much programming that doesn't really fit into a strong, static typing world. Maybe a dynamically typed language, with any variable having the type of its value (at any time) would suit your problems better. I love the strictness of strong static typing. It makes it possible for the compiler to give me far more detailed and to-the-point error messages and warnings. When reading the code, it provides more information, making it simpler to comprehend the code. There are situations where auto/var is required, e.g. in database operations; I am not objecting to using in in such cases. In most cases, you can extract the values to strongly typed variables. I do not leave them in untyped variables for long. Corollary, I try to avoid deep subclass nesting. Choosing between having to inspect 4-6 superclass definitions to find the definition of a field (hopefully with a comment explaining its use) or extending a superclass with a field that for some instances are left unused, I definitely prefer the latter. (I have many times seen subclasses created for adding a single field - even with several sibling classes adding the same single field!)

              Religious freedom is the freedom to say that two plus two make five.

              M C 2 Replies Last reply
              0
              • T trønderen

                It appears to me that you may be doing much programming that doesn't really fit into a strong, static typing world. Maybe a dynamically typed language, with any variable having the type of its value (at any time) would suit your problems better. I love the strictness of strong static typing. It makes it possible for the compiler to give me far more detailed and to-the-point error messages and warnings. When reading the code, it provides more information, making it simpler to comprehend the code. There are situations where auto/var is required, e.g. in database operations; I am not objecting to using in in such cases. In most cases, you can extract the values to strongly typed variables. I do not leave them in untyped variables for long. Corollary, I try to avoid deep subclass nesting. Choosing between having to inspect 4-6 superclass definitions to find the definition of a field (hopefully with a comment explaining its use) or extending a superclass with a field that for some instances are left unused, I definitely prefer the latter. (I have many times seen subclasses created for adding a single field - even with several sibling classes adding the same single field!)

                Religious freedom is the freedom to say that two plus two make five.

                M Offline
                M Offline
                Maximilien
                wrote on last edited by
                #11

                I think you're confusing things up. C++ is still strongly typed even when you use auto. when I declare a variable with auto, it will be typed accordingly and I cannot change the type.

                CI/CD = Continuous Impediment/Continuous Despair

                J 1 Reply Last reply
                0
                • T trønderen

                  It appears to me that you may be doing much programming that doesn't really fit into a strong, static typing world. Maybe a dynamically typed language, with any variable having the type of its value (at any time) would suit your problems better. I love the strictness of strong static typing. It makes it possible for the compiler to give me far more detailed and to-the-point error messages and warnings. When reading the code, it provides more information, making it simpler to comprehend the code. There are situations where auto/var is required, e.g. in database operations; I am not objecting to using in in such cases. In most cases, you can extract the values to strongly typed variables. I do not leave them in untyped variables for long. Corollary, I try to avoid deep subclass nesting. Choosing between having to inspect 4-6 superclass definitions to find the definition of a field (hopefully with a comment explaining its use) or extending a superclass with a field that for some instances are left unused, I definitely prefer the latter. (I have many times seen subclasses created for adding a single field - even with several sibling classes adding the same single field!)

                  Religious freedom is the freedom to say that two plus two make five.

                  C Offline
                  C Offline
                  charlieg
                  wrote on last edited by
                  #12

                  In my world - close to hardware - it's important to know and understand the type. Sure, if I'm using a modern IDE with Intellisense (only one comes to mind) auto might help. But, because of the proximity to hardware, we really don't use complex C++ types. Shoot, the last time I tried to use a C++ map, it was 10x slower than a simple linear search loop. I did not believe it at first... But getting back to using auto with it's intellisense interaction, intellisense does it's thing for plain and complex types as well. I'm not sure what the point it (other than reduced typing).

                  Charlie Gilley “They who can give up essential liberty to obtain a little temporary safety deserve neither liberty nor safety.” BF, 1759 Has never been more appropriate.

                  1 Reply Last reply
                  0
                  • M Maximilien

                    I think you're confusing things up. C++ is still strongly typed even when you use auto. when I declare a variable with auto, it will be typed accordingly and I cannot change the type.

                    CI/CD = Continuous Impediment/Continuous Despair

                    J Offline
                    J Offline
                    jschell
                    wrote on last edited by
                    #13

                    Maximilien wrote:

                    when I declare a variable with auto, it will be typed accordingly and I cannot change the type.

                    Err...in C++? Rather certain you can in fact change the type. Not generally a good idea but one can certainly do it. char* s = ....; int* p = (int*)s; I have seen very limited situations where it provided value.

                    CPalliniC L 2 Replies Last reply
                    0
                    • J jschell

                      Maximilien wrote:

                      when I declare a variable with auto, it will be typed accordingly and I cannot change the type.

                      Err...in C++? Rather certain you can in fact change the type. Not generally a good idea but one can certainly do it. char* s = ....; int* p = (int*)s; I have seen very limited situations where it provided value.

                      CPalliniC Offline
                      CPalliniC Offline
                      CPallini
                      wrote on last edited by
                      #14

                      That's a C-like dirty hack. Useful at times. There are also unions and variants. Nonetheless C++ remains a strong typed programming language.

                      "In testa che avete, Signor di Ceprano?" -- Rigoletto

                      In testa che avete, signor di Ceprano?

                      1 Reply Last reply
                      0
                      • C charlieg

                        I'm trying to straighten out some pointer "arithmetic" in some existing code. The expressions themselves are overly ambiguous to say the least. In part of my readings, I've come across the "auto" keyword where the compiler deduces what type I need. At least that's what I got from all of the verbiage. This seems a) dangerous and b) adds another level of mental indirection to what you are trying to accomplish. To me, software needs to be very clear and explicit in what data you are working with and what you intend to do with it. A lot of the "here is how auto will help you" descriptions justify it by saving typing when trying to make use of other classes, templates and the like. It feels like the C++ committee came up with a feature A then added feature B to make using A easier. I'm now doing battle with lambda expressions - another story. So, in your code - do you make extensive use of auto, and how does it help you?

                        Charlie Gilley “They who can give up essential liberty to obtain a little temporary safety deserve neither liberty nor safety.” BF, 1759 Has never been more appropriate.

                        1 Offline
                        1 Offline
                        11917640 Member
                        wrote on last edited by
                        #15

                        As already mentioned in several answers, auto keyword doesn't make C++ code less strong-typed or type-safe. So, using auto is individual preference. In some cases (such as templates, lambda) there is no other choice. When auto is optional, I always use it for complicated types, like container iterators. I also like auto in container enumeration code:

                        for(const auto& x: my_container)
                        {
                        // ...
                        }

                        As for local variables, it depends. Sometimes we want the variable to have another type. If the variable must have the same type, as expression, auto can help, when the code is changed:

                        std::vector v;
                        // ...
                        short n = v[0];

                        Consider the situation, when we change the container type to int:

                        std::vector v;
                        // ...
                        short n1 = v[0]; // oops, variable type should be changed as well
                        auto n2 = v[0]; // this is OK
                        decltype(v)::value_type n3 = v[0]; // this is also OK, though I don't like it

                        I find myself using auto more and more. Sometimes, when I want to see exactly, what I am doing, I prefer to use an explicit type.

                        C 1 Reply Last reply
                        0
                        • J jschell

                          Maximilien wrote:

                          when I declare a variable with auto, it will be typed accordingly and I cannot change the type.

                          Err...in C++? Rather certain you can in fact change the type. Not generally a good idea but one can certainly do it. char* s = ....; int* p = (int*)s; I have seen very limited situations where it provided value.

                          L Offline
                          L Offline
                          Lost User
                          wrote on last edited by
                          #16

                          That does not change anything, it's a cast. It merely tells the compiler "even though s is a char*, for this statement only, pretend it points to an int.

                          J 1 Reply Last reply
                          0
                          • 1 11917640 Member

                            As already mentioned in several answers, auto keyword doesn't make C++ code less strong-typed or type-safe. So, using auto is individual preference. In some cases (such as templates, lambda) there is no other choice. When auto is optional, I always use it for complicated types, like container iterators. I also like auto in container enumeration code:

                            for(const auto& x: my_container)
                            {
                            // ...
                            }

                            As for local variables, it depends. Sometimes we want the variable to have another type. If the variable must have the same type, as expression, auto can help, when the code is changed:

                            std::vector v;
                            // ...
                            short n = v[0];

                            Consider the situation, when we change the container type to int:

                            std::vector v;
                            // ...
                            short n1 = v[0]; // oops, variable type should be changed as well
                            auto n2 = v[0]; // this is OK
                            decltype(v)::value_type n3 = v[0]; // this is also OK, though I don't like it

                            I find myself using auto more and more. Sometimes, when I want to see exactly, what I am doing, I prefer to use an explicit type.

                            C Offline
                            C Offline
                            charlieg
                            wrote on last edited by
                            #17

                            I clearly have a limited understanding of C++. I admittedly come from a C background, and I have embraced the general concepts of C++ (most of the 4 pillars). But I'm going to be honest here :) It seems to me that auto is fixing or making easier to use some of the more spurious features of C++. Just a general thought, but it gets back to my original post/question. For example, your comment: "decltype(v)::value_type n3 = v[0];" means absolutely nothing to me. I'm at the level of wtf? So, I went out to the internet and read: "Inspects the declared type of an entity or the type and value category of an expression." for decltype. I still don't know what that means. Are we off in the top 0.01% land of coding? It's okay, I found my niche long ago, but seriously, it feels like so many special features have been added that only apply to the religious fanatics of code land.

                            Charlie Gilley “They who can give up essential liberty to obtain a little temporary safety deserve neither liberty nor safety.” BF, 1759 Has never been more appropriate.

                            1 1 Reply Last reply
                            0
                            • C charlieg

                              I clearly have a limited understanding of C++. I admittedly come from a C background, and I have embraced the general concepts of C++ (most of the 4 pillars). But I'm going to be honest here :) It seems to me that auto is fixing or making easier to use some of the more spurious features of C++. Just a general thought, but it gets back to my original post/question. For example, your comment: "decltype(v)::value_type n3 = v[0];" means absolutely nothing to me. I'm at the level of wtf? So, I went out to the internet and read: "Inspects the declared type of an entity or the type and value category of an expression." for decltype. I still don't know what that means. Are we off in the top 0.01% land of coding? It's okay, I found my niche long ago, but seriously, it feels like so many special features have been added that only apply to the religious fanatics of code land.

                              Charlie Gilley “They who can give up essential liberty to obtain a little temporary safety deserve neither liberty nor safety.” BF, 1759 Has never been more appropriate.

                              1 Offline
                              1 Offline
                              11917640 Member
                              wrote on last edited by
                              #18

                              I also prefer C over C++, and decltype example was kind of joke. Bad joke, I guess. In any case: decltype(v) means: type of v variable, vector of int in this case. vector type has value_type typedef, defined as T, see here: std::vector - cppreference.com[^] So, this ridiculous (for anyone, except C++ snobs) line is translated by compiler to int, i.e. vector template parameter.

                              C 1 Reply Last reply
                              0
                              • 1 11917640 Member

                                I also prefer C over C++, and decltype example was kind of joke. Bad joke, I guess. In any case: decltype(v) means: type of v variable, vector of int in this case. vector type has value_type typedef, defined as T, see here: std::vector - cppreference.com[^] So, this ridiculous (for anyone, except C++ snobs) line is translated by compiler to int, i.e. vector template parameter.

                                C Offline
                                C Offline
                                charlieg
                                wrote on last edited by
                                #19

                                (for anyone, except C++ snobs) Now I need to clean my screen - just spit all over it laughing. honestly, I did make the comment that there are people out there that code at a level I cannot even comprehend. I've come to call them "code witches" <--- I'm waiting to see if anyone follows the reference ;) I read your description of what decltype does and I think, "hmm, I need to pass gas." It's almost like some of the new "features" and auto is not new - 2010 ish raise areas of C++ to a meta programming language on it's own. Macros on steroids or something.

                                Charlie Gilley “They who can give up essential liberty to obtain a little temporary safety deserve neither liberty nor safety.” BF, 1759 Has never been more appropriate.

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                                • L Lost User

                                  That does not change anything, it's a cast. It merely tells the compiler "even though s is a char*, for this statement only, pretend it points to an int.

                                  J Offline
                                  J Offline
                                  jschell
                                  wrote on last edited by
                                  #20

                                  I believe that in terms of the semantic functionality that the type is now changed. If you have a method that takes the second type, the compiler will complain if you pass the first but not the second. I have in fact used a char array as a integer before. At least in that case there was no definable difference between the two. So exactly, in terms of the language, how does the cast not make it into a different type?

                                  Richard Andrew x64R L 2 Replies Last reply
                                  0
                                  • J jschell

                                    I believe that in terms of the semantic functionality that the type is now changed. If you have a method that takes the second type, the compiler will complain if you pass the first but not the second. I have in fact used a char array as a integer before. At least in that case there was no definable difference between the two. So exactly, in terms of the language, how does the cast not make it into a different type?

                                    Richard Andrew x64R Offline
                                    Richard Andrew x64R Offline
                                    Richard Andrew x64
                                    wrote on last edited by
                                    #21

                                    Well, think of it this way: What is a type? What do we mean when we declare the type of a variable? We're declaring how we want the compiler to treat the data value. It's not an existential property of the variable, it's the way that we interpret the value. So:

                                    char* b = "ABCD"; // means treat b as a char pointer

                                    And:

                                    int* a = (int*)b; // means please treat b as a int pointer just this one time

                                    We're declaring an action, not a property of the variable.

                                    The difficult we do right away... ...the impossible takes slightly longer.

                                    1 Reply Last reply
                                    0
                                    • J jschell

                                      I believe that in terms of the semantic functionality that the type is now changed. If you have a method that takes the second type, the compiler will complain if you pass the first but not the second. I have in fact used a char array as a integer before. At least in that case there was no definable difference between the two. So exactly, in terms of the language, how does the cast not make it into a different type?

                                      L Offline
                                      L Offline
                                      Lost User
                                      wrote on last edited by
                                      #22

                                      A char* is in reality just an index into a portion of memory. So at the machine level it has no type-ness, it can be used to address anything from a byte to a quadword. But as far as the language is concerned it only ever points to a character. When you use a cast the compiler does what can be done at machine level, but the object itself is still a char*, and any attempt to use it in any other way will raise a compiler error. If you have something like the following:

                                      int somefunction(int* pi, int count)
                                      {
                                      int sum = 0;
                                      for (int i = 0; i < count; ++i)
                                      {
                                      sum += *pi;
                                      }
                                      return sum;
                                      }

                                      // and you call it like this

                                      char* ci = "Foobar";
                                      int total = somefunction((int*)ci, strlen(ci));

                                      The type of ci does not change at all, it is just that its value is passed to somefunction, as the cast allows you to break or ignore the rules of the language. And the result of calling that function may, or may not, make sense.

                                      K J 2 Replies Last reply
                                      0
                                      • L Lost User

                                        A char* is in reality just an index into a portion of memory. So at the machine level it has no type-ness, it can be used to address anything from a byte to a quadword. But as far as the language is concerned it only ever points to a character. When you use a cast the compiler does what can be done at machine level, but the object itself is still a char*, and any attempt to use it in any other way will raise a compiler error. If you have something like the following:

                                        int somefunction(int* pi, int count)
                                        {
                                        int sum = 0;
                                        for (int i = 0; i < count; ++i)
                                        {
                                        sum += *pi;
                                        }
                                        return sum;
                                        }

                                        // and you call it like this

                                        char* ci = "Foobar";
                                        int total = somefunction((int*)ci, strlen(ci));

                                        The type of ci does not change at all, it is just that its value is passed to somefunction, as the cast allows you to break or ignore the rules of the language. And the result of calling that function may, or may not, make sense.

                                        K Offline
                                        K Offline
                                        k5054
                                        wrote on last edited by
                                        #23

                                        In your example, it should be noted that if the target CPU requires that an int have, for example, an even byte alignment, you may get an exception when trying to dereference the int pointer. I also wondered if you meant to increment the int pointer inside the loop, in which case, at some point you would invoke undefined behavior. Unless, of course, sizeof(int) == sizeof(char). Which isn't impossible, but I don't know of any system where that might be true. Maybe a 6502 or other 8bit system?

                                        "A little song, a little dance, a little seltzer down your pants" Chuckles the clown

                                        L 1 Reply Last reply
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                                        • K k5054

                                          In your example, it should be noted that if the target CPU requires that an int have, for example, an even byte alignment, you may get an exception when trying to dereference the int pointer. I also wondered if you meant to increment the int pointer inside the loop, in which case, at some point you would invoke undefined behavior. Unless, of course, sizeof(int) == sizeof(char). Which isn't impossible, but I don't know of any system where that might be true. Maybe a 6502 or other 8bit system?

                                          "A little song, a little dance, a little seltzer down your pants" Chuckles the clown

                                          L Offline
                                          L Offline
                                          Lost User
                                          wrote on last edited by
                                          #24

                                          k5054 wrote:

                                          if the target CPU ...

                                          True, but hardly relevant to the point I was trying to make. And yes, I should have incremented the integer pointer - writing (poor) code in a hurry. :doh:

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