If you think regex is already difficult...

[code-witch]

...you won't like the following problem.

The object: Eliminating lazy matches from a regular expression by replacing them with the equivalent greedy expression:
C block comment:
lazy:

/\*(.|\n)*?\*/

vs greedy equivalent:

/\*([^\*]|\*+[^*/])*\*+/

lazy:

f(u|o)*?bar

vs greedy equivalent:

f([^uob]|(u|o)+[^b]|(u|o)*b[^a]|(u|o)*ba[^r])*bar

The thing that will cost me sleep is I can almost see the pattern enough to implement it. Almost doesn't really count though, and that's the frustrating part. May as well be the moon.

[Richard Andrew x64]

Here's the way I read regex expressions:

}{$*(**#&^$%@

[code-witch]

@Richard-Andrew-x64 accurate