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Friday riddle...

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  • O Olli

    OK, i have another stupid riddle for friday.... Three guys are in a restaurant, and they think they should order something for three. Everybody gives 10$, and they call the waitress. The waitress takes the 30$ and goes to the kitchen to order a meal for 30$. Because the cook knows the three guys, he tells the waitress to give them 5$ back. She walks back to the table with the 5$, and because 5$ is not really good to divide by three, the guys tell her only to give 1$ back to each and keep 2$ as tip. And here's the riddle: Everybody has paid 10$ and got 1$ back, that makes 9$, right? 3x9$ is 27$, right? The waitress has 2$, right? 27$ + 2$ is 29$, right? :doh: ?????? Where is the missing DOLLAR ??????? :doh: :confused: Nice Weekend!!!

    Olli "Ooooooh, they have the internet on computers now!"
    Homer Simpson
    :beer: + :java: = NULL :=> X|

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    David Crow
    wrote on last edited by
    #12

    This is a different twist on an older riddle.


    "When I was born I was so surprised that I didn't talk for a year and a half." - Gracie Allen

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    • A Antony M Kancidrowski

      Since you started with a maths puzzle here is another. How can this be true? let a = x a+a = a+x [add a to both sides] 2a = a+x [a+a = 2a] 2a-2x = a+x-2x [subtract 2x from both sides] 2(a-x) = a+x-2x [2a-2x = 2(a-x)] 2(a-x) = a-x [x-2x = -x] 2 = 1 [divide both sides by a-x] There is a catch!! See if you can work it out. Ant. I'm hard, yet soft.
      I'm coloured, yet clear.
      I'm fruity and sweet.
      I'm jelly, what am I? Muse on it further, I shall return!
      - David Williams (Little Britain)

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      Johan Rosengren
      wrote on last edited by
      #13

      Antony M Kancidrowski wrote: 2 = 1 [divide both sides by a-x] a = x a - x = 0 division by zero...

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      • J Johan Rosengren

        Antony M Kancidrowski wrote: 2 = 1 [divide both sides by a-x] a = x a - x = 0 division by zero...

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        Antony M Kancidrowski
        wrote on last edited by
        #14

        Quite. It is an oldie but I like it :-D Ant. I'm hard, yet soft.
        I'm coloured, yet clear.
        I'm fruity and sweet.
        I'm jelly, what am I? Muse on it further, I shall return!
        - David Williams (Little Britain)

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        • A Antony M Kancidrowski

          Quite. It is an oldie but I like it :-D Ant. I'm hard, yet soft.
          I'm coloured, yet clear.
          I'm fruity and sweet.
          I'm jelly, what am I? Muse on it further, I shall return!
          - David Williams (Little Britain)

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          J Offline
          Johan Rosengren
          wrote on last edited by
          #15

          The universe would be a much more interesting place if division by zero was allowed :-)

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          • A Antony M Kancidrowski

            Since you started with a maths puzzle here is another. How can this be true? let a = x a+a = a+x [add a to both sides] 2a = a+x [a+a = 2a] 2a-2x = a+x-2x [subtract 2x from both sides] 2(a-x) = a+x-2x [2a-2x = 2(a-x)] 2(a-x) = a-x [x-2x = -x] 2 = 1 [divide both sides by a-x] There is a catch!! See if you can work it out. Ant. I'm hard, yet soft.
            I'm coloured, yet clear.
            I'm fruity and sweet.
            I'm jelly, what am I? Muse on it further, I shall return!
            - David Williams (Little Britain)

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            D Offline
            dacris
            wrote on last edited by
            #16

            You cannot divide both sides by a-x because a-x = a-a = 0. Can't divide by zero. Every programmer knows that. ;P I have a symbiotic relationship with my computer.

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            • O Olli

              OK, i have another stupid riddle for friday.... Three guys are in a restaurant, and they think they should order something for three. Everybody gives 10$, and they call the waitress. The waitress takes the 30$ and goes to the kitchen to order a meal for 30$. Because the cook knows the three guys, he tells the waitress to give them 5$ back. She walks back to the table with the 5$, and because 5$ is not really good to divide by three, the guys tell her only to give 1$ back to each and keep 2$ as tip. And here's the riddle: Everybody has paid 10$ and got 1$ back, that makes 9$, right? 3x9$ is 27$, right? The waitress has 2$, right? 27$ + 2$ is 29$, right? :doh: ?????? Where is the missing DOLLAR ??????? :doh: :confused: Nice Weekend!!!

              Olli "Ooooooh, they have the internet on computers now!"
              Homer Simpson
              :beer: + :java: = NULL :=> X|

              B Offline
              B Offline
              braber
              wrote on last edited by
              #17

              The other dollor went to tax!!!! :)

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              • O Olli

                OK, i have another stupid riddle for friday.... Three guys are in a restaurant, and they think they should order something for three. Everybody gives 10$, and they call the waitress. The waitress takes the 30$ and goes to the kitchen to order a meal for 30$. Because the cook knows the three guys, he tells the waitress to give them 5$ back. She walks back to the table with the 5$, and because 5$ is not really good to divide by three, the guys tell her only to give 1$ back to each and keep 2$ as tip. And here's the riddle: Everybody has paid 10$ and got 1$ back, that makes 9$, right? 3x9$ is 27$, right? The waitress has 2$, right? 27$ + 2$ is 29$, right? :doh: ?????? Where is the missing DOLLAR ??????? :doh: :confused: Nice Weekend!!!

                Olli "Ooooooh, they have the internet on computers now!"
                Homer Simpson
                :beer: + :java: = NULL :=> X|

                B Offline
                B Offline
                braber
                wrote on last edited by
                #18

                30$ total 25$ went to meal 5$ Back 2$ of the 5$ went to waitress... $28 was spent by the entire crew 28\3 $9.33 9.33x3+2 = $30 Sales tax would have been funnier!!! Heeler

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                • K KaRl

                  Olli wrote: ?????? Where is the missing DOLLAR ??????? I'm surprized nobody blamed taxes :rolleyes:


                  Собой остаться дольше...

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                  Arjan Einbu
                  wrote on last edited by
                  #19

                  KaЯl wrote: I'm surprized nobody blamed taxes With only 3% missing? Not here...


                  Have a look at my latest article about Object Prevalence with Bamboo Prevalence.

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                  • O Olli

                    OK, i have another stupid riddle for friday.... Three guys are in a restaurant, and they think they should order something for three. Everybody gives 10$, and they call the waitress. The waitress takes the 30$ and goes to the kitchen to order a meal for 30$. Because the cook knows the three guys, he tells the waitress to give them 5$ back. She walks back to the table with the 5$, and because 5$ is not really good to divide by three, the guys tell her only to give 1$ back to each and keep 2$ as tip. And here's the riddle: Everybody has paid 10$ and got 1$ back, that makes 9$, right? 3x9$ is 27$, right? The waitress has 2$, right? 27$ + 2$ is 29$, right? :doh: ?????? Where is the missing DOLLAR ??????? :doh: :confused: Nice Weekend!!!

                    Olli "Ooooooh, they have the internet on computers now!"
                    Homer Simpson
                    :beer: + :java: = NULL :=> X|

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                    M Offline
                    Marc Clifton
                    wrote on last edited by
                    #20

                    The logic flaw is in the very first statement. Olli wrote: Everybody has paid 10$ and got 1$ back, that makes 9$, right? Everyone paid $10 and got back 5/3 of a dollar (5 returned by the cook divided by the 3 people). They then each contributed 2/3 of a dollar to the tip (2/3 * 3 = $2) 5/3 - 2/3 = 3/3, leaving them with with a dollar each. Marc Microsoft MVP, Visual C# MyXaml MyXaml Blog Hunt The Wumpus RealDevs.Net

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                    • A Antony M Kancidrowski

                      Since you started with a maths puzzle here is another. How can this be true? let a = x a+a = a+x [add a to both sides] 2a = a+x [a+a = 2a] 2a-2x = a+x-2x [subtract 2x from both sides] 2(a-x) = a+x-2x [2a-2x = 2(a-x)] 2(a-x) = a-x [x-2x = -x] 2 = 1 [divide both sides by a-x] There is a catch!! See if you can work it out. Ant. I'm hard, yet soft.
                      I'm coloured, yet clear.
                      I'm fruity and sweet.
                      I'm jelly, what am I? Muse on it further, I shall return!
                      - David Williams (Little Britain)

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                      wrykyn
                      wrote on last edited by
                      #21

                      Dividing both sides by zero. I can use the same thing to prove that 1 hour is equal to one minute. See if you can do that ? :) "One of the Georges," said Psmith, "I forget which, once said that a certain number of hours' sleep a day--I cannot recall for the moment how many--made a man something, which for the time being has slipped my memory."

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                      • D dacris

                        You cannot divide both sides by a-x because a-x = a-a = 0. Can't divide by zero. Every programmer knows that. ;P I have a symbiotic relationship with my computer.

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                        Jerry Hammond
                        wrote on last edited by
                        #22

                        dacris wrote: You cannot divide both sides by a-x because a-x = a-a = 0. Can't divide by zero. Every programmer knows that. Duh! Wanna know why I'm still a hobbiest?

                        The only way of discovering the limits of the possible is to venture a little past them into the impossible.--Arthur C. Clark

                        Toasty0.com

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