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  4. I would like to convert int to char

I would like to convert int to char

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  • S Offline
    S Offline
    sacoskun
    wrote on last edited by
    #1

    Hi, I would like to convert int i = 7 to char, how can I do this? Regards, - When in doubt, push a pawn! -

    M S 2 Replies Last reply
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    • S sacoskun

      Hi, I would like to convert int i = 7 to char, how can I do this? Regards, - When in doubt, push a pawn! -

      M Offline
      M Offline
      Mad__
      wrote on last edited by
      #2

      Hy, That depend on what you need, char = 0x07 or char = '7' ;)

      S 1 Reply Last reply
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      • S sacoskun

        Hi, I would like to convert int i = 7 to char, how can I do this? Regards, - When in doubt, push a pawn! -

        S Offline
        S Offline
        Sujan Christo
        wrote on last edited by
        #3

        Hi, can use _itoa(..) function. Have a look @ msdn. it does have a sample too. Sujan

        1 Reply Last reply
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        • M Mad__

          Hy, That depend on what you need, char = 0x07 or char = '7' ;)

          S Offline
          S Offline
          sacoskun
          wrote on last edited by
          #4

          char = '7' - When in doubt, push a pawn! -

          M T 2 Replies Last reply
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          • S sacoskun

            char = '7' - When in doubt, push a pawn! -

            M Offline
            M Offline
            Mad__
            wrote on last edited by
            #5

            You can use on of : sprintf, itoa ... of this pseudo code int = nex_digit while(int) char = 0x30+int

            S 1 Reply Last reply
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            • M Mad__

              You can use on of : sprintf, itoa ... of this pseudo code int = nex_digit while(int) char = 0x30+int

              S Offline
              S Offline
              sacoskun
              wrote on last edited by
              #6

              I would like to run this function in my C++ code; void convertToBinary( int numberToConvert ) { if(!(( N / 2 ) < 1 )) { binaryRepresentation[counter] = ( N % 2 ); counter++; convertToBinary( N /= 2 ); } } but binaryRepresentation[counter] = ( N % 2 ); line of code does not work friend? - When in doubt, push a pawn! -

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              • S sacoskun

                char = '7' - When in doubt, push a pawn! -

                T Offline
                T Offline
                toxcct
                wrote on last edited by
                #7

                char c;
                sscanf("7", "%s %c", &c);


                TOXCCT >>> GEII power

                S 1 Reply Last reply
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                • T toxcct

                  char c;
                  sscanf("7", "%s %c", &c);


                  TOXCCT >>> GEII power

                  S Offline
                  S Offline
                  sacoskun
                  wrote on last edited by
                  #8

                  When I made sscanf( static_cast( N % 2 ) , "%s" , &binaryRepresentation[counter] ); Compiler gives an error like cannot convert parameter 1 from 'char' to 'const char * I'm a newbie in C++, Regards. - When in doubt, push a pawn! -

                  T B 2 Replies Last reply
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                  • S sacoskun

                    I would like to run this function in my C++ code; void convertToBinary( int numberToConvert ) { if(!(( N / 2 ) < 1 )) { binaryRepresentation[counter] = ( N % 2 ); counter++; convertToBinary( N /= 2 ); } } but binaryRepresentation[counter] = ( N % 2 ); line of code does not work friend? - When in doubt, push a pawn! -

                    M Offline
                    M Offline
                    Mad__
                    wrote on last edited by
                    #9

                    I don't understend what meen N in this code ;) For binare representation of value i use this function: char* BinPrintf(int value) { char tmp[256]; memset(tmp, 0, 256); int tpos = 0; while(value) { tmp[tpos++] = 0x30+value%2; value = value >> 1; } char *ret = new char[strlen(tmp)+1]; memset(ret, 0, strlen(tmp)+1); tpos = strlen(tmp)-1; value = 0; while(tpos > -1) ret[value++] = tmp[tpos--]; return ret; }

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                    • S sacoskun

                      When I made sscanf( static_cast( N % 2 ) , "%s" , &binaryRepresentation[counter] ); Compiler gives an error like cannot convert parameter 1 from 'char' to 'const char * I'm a newbie in C++, Regards. - When in doubt, push a pawn! -

                      T Offline
                      T Offline
                      toxcct
                      wrote on last edited by
                      #10

                      kromozom wrote: sscanf( static_cast( N % 2 ) , "%s" , &binaryRepresentation[counter] ); that's normal, you associate a char with %s do this :

                      sscanf( static_cast( N % 2 ) , "%c" , &binaryRepresentation[counter] );


                      TOXCCT >>> GEII power

                      S 1 Reply Last reply
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                      • T toxcct

                        kromozom wrote: sscanf( static_cast( N % 2 ) , "%s" , &binaryRepresentation[counter] ); that's normal, you associate a char with %s do this :

                        sscanf( static_cast( N % 2 ) , "%c" , &binaryRepresentation[counter] );


                        TOXCCT >>> GEII power

                        S Offline
                        S Offline
                        sacoskun
                        wrote on last edited by
                        #11

                        When I type; sscanf( static_cast( N % 2 ) , "%c" , &binaryRepresentation[counter] ); Same error occurs, cannot convert char to const char* Regards, - When in doubt, push a pawn! -

                        1 Reply Last reply
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                        • S sacoskun

                          When I made sscanf( static_cast( N % 2 ) , "%s" , &binaryRepresentation[counter] ); Compiler gives an error like cannot convert parameter 1 from 'char' to 'const char * I'm a newbie in C++, Regards. - When in doubt, push a pawn! -

                          B Offline
                          B Offline
                          Bob Stanneveld
                          wrote on last edited by
                          #12

                          That is because static_cast( N % 2 ) is not a pointer to a char. I don't know what it is, because N is unknown to me... Take a look at the prototype of sscanf[^] and then start wondering how you should pass the parameters... Besides that, the solution that Mad__ gave you looks like what you want... :-D Multiply it by infinity and take it beyond eternity and you'll still have no idea about what I'm talking about.

                          1 Reply Last reply
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                          • S sacoskun

                            I would like to run this function in my C++ code; void convertToBinary( int numberToConvert ) { if(!(( N / 2 ) < 1 )) { binaryRepresentation[counter] = ( N % 2 ); counter++; convertToBinary( N /= 2 ); } } but binaryRepresentation[counter] = ( N % 2 ); line of code does not work friend? - When in doubt, push a pawn! -

                            D Offline
                            D Offline
                            David Crow
                            wrote on last edited by
                            #13

                            I assume binaryRepresentation is some sort of char array, and that N is actually numberToConvert. That being the case, what you have is working, but you are confusing 0 (ASCII 0) and '0' (ASCII 48). You simply need to change the statement to:

                            binaryRepresentation[counter] = (char) ((N % 2 ) + 48);

                            Now binaryRepresentation[counter] will contain '0' if N is an even number and '1' if N is an odd number. Of course, if you wanted to use a "built-in" solution, you could simply use itoa(numberToConvert, binaryRepresentation, 2).


                            "Opinions are neither right nor wrong. I cannot change your opinion of me. I can, however, change what influences your opinion." - David Crow

                            S 1 Reply Last reply
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                            • M Mad__

                              I don't understend what meen N in this code ;) For binare representation of value i use this function: char* BinPrintf(int value) { char tmp[256]; memset(tmp, 0, 256); int tpos = 0; while(value) { tmp[tpos++] = 0x30+value%2; value = value >> 1; } char *ret = new char[strlen(tmp)+1]; memset(ret, 0, strlen(tmp)+1); tpos = strlen(tmp)-1; value = 0; while(tpos > -1) ret[value++] = tmp[tpos--]; return ret; }

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                              David Crow
                              wrote on last edited by
                              #14

                              Mad__ wrote: char *ret = new char[strlen(tmp)+1]; memset(ret, 0, strlen(tmp)+1); tpos = strlen(tmp)-1; value = 0; while(tpos > -1) ret[value++] = tmp[tpos--]; This code could simply be replaced with a call to strrev(tmp).


                              "Opinions are neither right nor wrong. I cannot change your opinion of me. I can, however, change what influences your opinion." - David Crow

                              1 Reply Last reply
                              0
                              • D David Crow

                                I assume binaryRepresentation is some sort of char array, and that N is actually numberToConvert. That being the case, what you have is working, but you are confusing 0 (ASCII 0) and '0' (ASCII 48). You simply need to change the statement to:

                                binaryRepresentation[counter] = (char) ((N % 2 ) + 48);

                                Now binaryRepresentation[counter] will contain '0' if N is an even number and '1' if N is an odd number. Of course, if you wanted to use a "built-in" solution, you could simply use itoa(numberToConvert, binaryRepresentation, 2).


                                "Opinions are neither right nor wrong. I cannot change your opinion of me. I can, however, change what influences your opinion." - David Crow

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                                sacoskun
                                wrote on last edited by
                                #15

                                Thanks all for help, I solved it... - When in doubt, push a pawn! -

                                1 Reply Last reply
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