I would like to convert int to char

[sacoskun]

I would like to run this function in my C++ code; void convertToBinary( int numberToConvert ) { if(!(( N / 2 ) < 1 )) { binaryRepresentation[counter] = ( N % 2 ); counter++; convertToBinary( N /= 2 ); } } but binaryRepresentation[counter] = ( N % 2 ); line of code does not work friend? - When in doubt, push a pawn! -

[toxcct]

char c;
sscanf("7", "%s %c", &c);

---

TOXCCT >>> GEII power

[sacoskun]

When I made sscanf( static_cast( N % 2 ) , "%s" , &binaryRepresentation[counter] ); Compiler gives an error like cannot convert parameter 1 from 'char' to 'const char * I'm a newbie in C++, Regards. - When in doubt, push a pawn! -

[Mad__]

I don't understend what meen N in this code ;) For binare representation of value i use this function: char* BinPrintf(int value) { char tmp[256]; memset(tmp, 0, 256); int tpos = 0; while(value) { tmp[tpos++] = 0x30+value%2; value = value >> 1; } char *ret = new char[strlen(tmp)+1]; memset(ret, 0, strlen(tmp)+1); tpos = strlen(tmp)-1; value = 0; while(tpos > -1) ret[value++] = tmp[tpos--]; return ret; }

[toxcct]

kromozom wrote: sscanf( static_cast( N % 2 ) , "%s" , &binaryRepresentation[counter] ); that's normal, you associate a char with %s do this :

sscanf( static_cast( N % 2 ) , "%c" , &binaryRepresentation[counter] );

---

TOXCCT >>> GEII power

[sacoskun]

When I type; sscanf( static_cast( N % 2 ) , "%c" , &binaryRepresentation[counter] ); Same error occurs, cannot convert char to const char* Regards, - When in doubt, push a pawn! -

[Bob Stanneveld]

That is because static_cast( N % 2 ) is not a pointer to a char. I don't know what it is, because N is unknown to me... Take a look at the prototype of sscanf[^] and then start wondering how you should pass the parameters... Besides that, the solution that Mad__ gave you looks like what you want... :-D Multiply it by infinity and take it beyond eternity and you'll still have no idea about what I'm talking about.

[David Crow]

I assume binaryRepresentation is some sort of char array, and that N is actually numberToConvert. That being the case, what you have is working, but you are confusing 0 (ASCII 0) and '0' (ASCII 48). You simply need to change the statement to:

binaryRepresentation[counter] = (char) ((N % 2 ) + 48);

Now binaryRepresentation[counter] will contain '0' if N is an even number and '1' if N is an odd number. Of course, if you wanted to use a "built-in" solution, you could simply use itoa(numberToConvert, binaryRepresentation, 2).

---

"Opinions are neither right nor wrong. I cannot change your opinion of me. I can, however, change what influences your opinion." - David Crow

[David Crow]

Mad__ wrote: char *ret = new char[strlen(tmp)+1]; memset(ret, 0, strlen(tmp)+1); tpos = strlen(tmp)-1; value = 0; while(tpos > -1) ret[value++] = tmp[tpos--]; This code could simply be replaced with a call to strrev(tmp).

---

"Opinions are neither right nor wrong. I cannot change your opinion of me. I can, however, change what influences your opinion." - David Crow

[sacoskun]

Thanks all for help, I solved it... - When in doubt, push a pawn! -