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  3. How to get the last selected item from a multiple dropdownlist with javascript? [modified]

How to get the last selected item from a multiple dropdownlist with javascript? [modified]

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  • A Offline
    A Offline
    andylaw
    wrote on last edited by
    #1

    example:user select items like item1,item2,item5,item3, the last selected item is item3,how to get it with javascript?

    One is never too old to learn

    modified on Wednesday, February 20, 2008 8:56 PM

    M 1 Reply Last reply
    0
    • A andylaw

      example:user select items like item1,item2,item5,item3, the last selected item is item3,how to get it with javascript?

      One is never too old to learn

      modified on Wednesday, February 20, 2008 8:56 PM

      M Offline
      M Offline
      mgr_2k7
      wrote on last edited by
      #2

      --Find the object in the form var ddlObj = document.getElementById('ddlName'); --Find the selected Index alert(ddlObj.selectedIndex);

      A 1 Reply Last reply
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      • M mgr_2k7

        --Find the object in the form var ddlObj = document.getElementById('ddlName'); --Find the selected Index alert(ddlObj.selectedIndex);

        A Offline
        A Offline
        andylaw
        wrote on last edited by
        #3

        To:mgr_2k7 Maybe you can't understrand what i mean. Here is a multiple dropdownlist as below: <select id="sel_test" name="sel_test" size="5" multiple="multiple" onchange="javascript:checkSelectedCount(this);" width="100px"> <option value="item1">item_A</option> <option value="item2">item_B</option> <option value="item3">item_C</option> <option value="item4">item_D</option> <option value="item5">item_E</option> <option value="item6">item_F</option> <option value="item7">item_G</option> <option value="item8">item_H</option> <option value="item9">item_I</option> <option value="item10">item_J</option> <option value="item11">item_K</option> <option value="item12">item_L</option> <option value="item13">item_M</option> <option value="item14">item_N</option> <option value="item15">item_O</option> <option value="item16">item_P</option> </select> When user multiple selected as order: item1,item4,item2 -------------item2 is the last selected item When user multiple selected as order: item2,item3,item1 -------------item1 is the last selected item When user multiple selected as order: item4,item2,item3 -------------item3 is the last selected item ------------------Understrand???? So,how could i get the last selected item?

        One is never too old to learn

        modified on Wednesday, February 20, 2008 8:59 PM

        N 1 Reply Last reply
        0
        • A andylaw

          To:mgr_2k7 Maybe you can't understrand what i mean. Here is a multiple dropdownlist as below: <select id="sel_test" name="sel_test" size="5" multiple="multiple" onchange="javascript:checkSelectedCount(this);" width="100px"> <option value="item1">item_A</option> <option value="item2">item_B</option> <option value="item3">item_C</option> <option value="item4">item_D</option> <option value="item5">item_E</option> <option value="item6">item_F</option> <option value="item7">item_G</option> <option value="item8">item_H</option> <option value="item9">item_I</option> <option value="item10">item_J</option> <option value="item11">item_K</option> <option value="item12">item_L</option> <option value="item13">item_M</option> <option value="item14">item_N</option> <option value="item15">item_O</option> <option value="item16">item_P</option> </select> When user multiple selected as order: item1,item4,item2 -------------item2 is the last selected item When user multiple selected as order: item2,item3,item1 -------------item1 is the last selected item When user multiple selected as order: item4,item2,item3 -------------item3 is the last selected item ------------------Understrand???? So,how could i get the last selected item?

          One is never too old to learn

          modified on Wednesday, February 20, 2008 8:59 PM

          N Offline
          N Offline
          Nilesh Hapse
          wrote on last edited by
          #4

          I don't think you can find like this

          "Legacy code" often differs from its suggested alternative by actually working and scaling. —Bjarne Stroustrup

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