Insert <br> for every 10 characters of asp label in C#.net</br> [modified]

[getaccessyr]

Hi All, I need to add "
" i.e. break for every 10characters of text in label which we are binding data from Database.so that the after every 10th character remaining characters will come in next line. i wrote a code but if we have to enter characters as multiples of 10 else it gives error my code is: public static string WrappableText(string source) { //string nwln = Environment.NewLine; //return source.Replace(nwln, "<br />"); ArrayList StringList = new ArrayList(); int a=0; for (int i = 1; i <= 10; i++) { StringList.Add(source.Substring(a, 10)); a += 10; } System.Text.StringBuilder newstring = new System.Text.StringBuilder(); while (StringList.Count>0) { newstring.Append(StringList[0].ToString() + "<br>"); StringList.RemoveAt(0); } return newstring.ToString(); } Is it possible to do? Can any one help me? Thanks In Advance yamuna

modified on Thursday, October 8, 2009 10:46 AM

[Christian Graus]

Well, you should have told us what the error was. This code is terrible.

yamunarani wrote:

ArrayList

Why use an arraylist ? Is this ASP.NET 1.0 ?

yamunarani wrote:

StringList.Add(source.Substring(a, 10));

Here is your problem. You assume there's 10 characters. Of course you'll get an error if there is not. Work out the string length in code instead.

Christian Graus Driven to the arms of OSX by Vista. Read my blog to find out how I've worked around bugs in Microsoft tools and frameworks.

[getaccessyr]

Hi, I know that the problem is with the code i used StringList.Add(source.Substring(a, 10)); i tried in other way too,but i dint get the required solution it is failing in other way if any one knows the exact solution plz reply me thanks in advance yamuna

[Imran Khan Pathan]

TRY THIS ONE. public string WrappedString(string Source) { int count = 0; System.Text.StringBuilder sb = new System.Text.StringBuilder(); foreach (char c in Source) { count++; sb.Append(c); if (count == 10) { count = 0; sb.Append("< br >"); } } return sb.ToString(); }

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