Getting invalid IP address.............

[3bood ghzawi]

Hi all... As calling an 'ipAddress' from class 'Sockaddr' to find the local IP address of my PC, it always return an IP address 255.255.255.255 for IPv4, and ffff.ffff.ffff.ffff for IPv6. the class 'Sockaddr' belongs to 'SharpPcap-2.1.1', the implementation of the class is as follwo: using System; using System.Runtime.InteropServices; using System.Net.NetworkInformation; namespace SharpPcap.Containers { public class Sockaddr { public enum Type { AF_INET_AF_INET6, HARDWARE, UNKNOWN } public Type type; static public System.Net.IPAddress ipAddress; // if type == AF_INET_AF_INET6 public PhysicalAddress hardwareAddress; // if type == HARDWARE private int _sa_family; public int sa_family { get { return _sa_family; } } public Sockaddr(PhysicalAddress hardwareAddress) { this.type = Type.HARDWARE; this.hardwareAddress = hardwareAddress; } public Sockaddr(IntPtr sockaddrPtr) { // A sockaddr struct. We use this to determine the address family PcapUnmanagedStructures.sockaddr saddr; // Marshal memory pointer into a struct saddr = (PcapUnmanagedStructures.sockaddr)Marshal.PtrToStructure(sockaddrPtr, typeof(PcapUnmanagedStructures.sockaddr)); // record the sa_family for informational purposes _sa_family = saddr.sa_family; byte[] addressBytes; if(saddr.sa_family == Pcap.AF_INET) { type = Type.AF_INET_AF_INET6; PcapUnmanagedStructures.sockaddr_in saddr_in = (PcapUnmanagedStructures.sockaddr_in)Marshal.PtrToStructure(sockaddrPtr, typeof(PcapUnmanagedStructures.sockaddr_in)); ipAddress = new System.Net.IPAddress(saddr_in.sin_addr.s_addr); } else if(saddr.sa_family == Pcap.AF_INET6) { type = Type.AF_INET_AF_INET6; addressBytes = new byte[16]; PcapUnmanagedStructures.sockaddr_in6 sin6 = (PcapUnmanagedStructures.sockaddr_in6)Marshal.PtrToStructure(sockaddrPtr, typeof(PcapUnmanagedStructures.sockaddr_in6));

[SeMartens]

Hi, your code seems a bit complicated. Did you know that there is some framework implementation to obtain the local ip-adress? Check out this article: How To Get IP Address Of A Machine[^] Hope this helps. Regards Sebastian

It's not a bug, it's a feature! Check out my CodeProject article Permission-by-aspect. Me in Softwareland.

[Luc Pattyn]

Hi Sebastian, such techniques return the local IP address, i.e. the address is valid on the LAN, but in general not on the internet. To get the "external" IP address, one really needs an external web service, and I happen to offer one here: http://www.perceler.com/tools1.php[^]. :)

Luc Pattyn [Forum Guidelines] [Why QA sucks] [My Articles]

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