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  4. SELECT ... GROUP BY Error

SELECT ... GROUP BY Error

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  • M MikeDhaan

    Thanks for the idea, but it's not enought because the values are diffrent. I receive in this case : MAX(TheDate), Type, Value 2011/08/11 , T1 , 10 2011/08/17 , T1 , 12 2011/09/25 , T1 , 11 2011/08/15 , T2 , 10 ... And I only need the last value for T1, T2, ... ! Mike

    J Offline
    J Offline
    Jorgen Andersson
    wrote on last edited by
    #4

    Then you need to remove the Value column from the query.

    SELECT MAX(TheDate), Type
    FROM MyTable
    GROUP BY TYPE

    But then you don't get the value. So join the result from this query with the original table.

    WITH maxdate AS (
    SELECT MAX(TheDate) TheDate, Type
    FROM MyTable
    GROUP BY Type
    )
    SELECT t.TheDate, t.Type, t.Value
    FROM MyTable t join maxdate d
    ON t.TheDate = d.TheDate
    AND t.Type = d.Type

    Light moves faster than sound. That is why some people appear bright, until you hear them speak. List of common misconceptions

    M 1 Reply Last reply
    0
    • M MikeDhaan

      I have as table like TheDate Type Value I need to retreive the last value for each type. I try a SQL command like SELECT MAX(TheDate), Type, Value from MyTable GROUP BY Type But I receive an error : Erreur SQL : ORA-00979: not a GROUP BY expression 00979. 00000 - "not a GROUP BY expression" Do you have any idea ?

      C Offline
      C Offline
      Chris Meech
      wrote on last edited by
      #5

      You first need to find the MAX(TheDate) and then use that to find the Value(s). :)

      select Value
      ,Type
      from TABLE
      where TheDate in ( select MAX(TheDate)
      from Table
      group by Type
      )
      ;

      That's off the top of my head, but should be close. :)

      Chris Meech I am Canadian. [heard in a local bar] In theory there is no difference between theory and practice. In practice there is. [Yogi Berra] posting about Crystal Reports here is like discussing gay marriage on a catholic church’s website.[Nishant Sivakumar]

      M 1 Reply Last reply
      0
      • C Chris Meech

        You first need to find the MAX(TheDate) and then use that to find the Value(s). :)

        select Value
        ,Type
        from TABLE
        where TheDate in ( select MAX(TheDate)
        from Table
        group by Type
        )
        ;

        That's off the top of my head, but should be close. :)

        Chris Meech I am Canadian. [heard in a local bar] In theory there is no difference between theory and practice. In practice there is. [Yogi Berra] posting about Crystal Reports here is like discussing gay marriage on a catholic church’s website.[Nishant Sivakumar]

        M Offline
        M Offline
        MikeDhaan
        wrote on last edited by
        #6

        OK, but you select the max date and not the max date per type I have several types and I shearch the last value for each type and not the max date per type

        C 1 Reply Last reply
        0
        • M MikeDhaan

          OK, but you select the max date and not the max date per type I have several types and I shearch the last value for each type and not the max date per type

          C Offline
          C Offline
          Chris Meech
          wrote on last edited by
          #7

          MikeDhaan wrote:

          and not the max date per type

          The inner select has a group by type which should produce a list of MAX(dates). :)

          Chris Meech I am Canadian. [heard in a local bar] In theory there is no difference between theory and practice. In practice there is. [Yogi Berra] posting about Crystal Reports here is like discussing gay marriage on a catholic church’s website.[Nishant Sivakumar]

          M 1 Reply Last reply
          0
          • C Chris Meech

            MikeDhaan wrote:

            and not the max date per type

            The inner select has a group by type which should produce a list of MAX(dates). :)

            Chris Meech I am Canadian. [heard in a local bar] In theory there is no difference between theory and practice. In practice there is. [Yogi Berra] posting about Crystal Reports here is like discussing gay marriage on a catholic church’s website.[Nishant Sivakumar]

            M Offline
            M Offline
            MikeDhaan
            wrote on last edited by
            #8

            Correct but the result with the extract below is not correct. MAX(TheDate), Type, Value 2011/08/11 , T1 , 10 2011/08/17 , T1 , 12 2011/09/25 , T1 , 11 2011/08/11 , T2 , 15 2011/10/10 , T3 , 15 ... The result is : MAX(TheDate), Type, Value 2011/08/11 , T1 , 10 :confused: 2011/09/25 , T1 , 11 2011/08/11 , T2 , 15 2011/08/15 , T2 , 10 ... Because select MAX(TheDate) from Table group by Type return 2011/09/25 (for T1) 2011/08/11 (for T2) 2011/10/10 (for T3)

            M C 2 Replies Last reply
            0
            • M MikeDhaan

              Thanks for the idea, but it's not enought because the values are diffrent. I receive in this case : MAX(TheDate), Type, Value 2011/08/11 , T1 , 10 2011/08/17 , T1 , 12 2011/09/25 , T1 , 11 2011/08/15 , T2 , 10 ... And I only need the last value for T1, T2, ... ! Mike

              B Offline
              B Offline
              Blue_Boy
              wrote on last edited by
              #9

              Try this query

              select distinct
              (select top 1 t2.thedate from MyTable as t2 where t2.[type]=t1.[type] order by t2.thedate desc) as thedate
              , t1.[type]
              ,(select top 1 t2.value from MyTable as t2 where t2.[type]=t1.[type] order by t2.thedate desc) as [Value]
              from MyTable as t1
              order by t1.[type]


              I Love T-SQL "VB.NET is developed with C#.NET" If my post helps you kindly save my time by voting my post.

              1 Reply Last reply
              0
              • M MikeDhaan

                Correct but the result with the extract below is not correct. MAX(TheDate), Type, Value 2011/08/11 , T1 , 10 2011/08/17 , T1 , 12 2011/09/25 , T1 , 11 2011/08/11 , T2 , 15 2011/10/10 , T3 , 15 ... The result is : MAX(TheDate), Type, Value 2011/08/11 , T1 , 10 :confused: 2011/09/25 , T1 , 11 2011/08/11 , T2 , 15 2011/08/15 , T2 , 10 ... Because select MAX(TheDate) from Table group by Type return 2011/09/25 (for T1) 2011/08/11 (for T2) 2011/10/10 (for T3)

                M Offline
                M Offline
                Mycroft Holmes
                wrote on last edited by
                #10

                Do a little research on Row_Number, Partition and Ranking. Using these you can set up an inner query that ranks the records by date partitioned over type. The outer query would then join by date and type where the rank = 1.

                Never underestimate the power of human stupidity RAH

                1 Reply Last reply
                0
                • J Jorgen Andersson

                  Then you need to remove the Value column from the query.

                  SELECT MAX(TheDate), Type
                  FROM MyTable
                  GROUP BY TYPE

                  But then you don't get the value. So join the result from this query with the original table.

                  WITH maxdate AS (
                  SELECT MAX(TheDate) TheDate, Type
                  FROM MyTable
                  GROUP BY Type
                  )
                  SELECT t.TheDate, t.Type, t.Value
                  FROM MyTable t join maxdate d
                  ON t.TheDate = d.TheDate
                  AND t.Type = d.Type

                  Light moves faster than sound. That is why some people appear bright, until you hear them speak. List of common misconceptions

                  M Offline
                  M Offline
                  MikeDhaan
                  wrote on last edited by
                  #11

                  :thumbsup: Super, It's working ;) Thanks

                  J 2 Replies Last reply
                  0
                  • M MikeDhaan

                    Correct but the result with the extract below is not correct. MAX(TheDate), Type, Value 2011/08/11 , T1 , 10 2011/08/17 , T1 , 12 2011/09/25 , T1 , 11 2011/08/11 , T2 , 15 2011/10/10 , T3 , 15 ... The result is : MAX(TheDate), Type, Value 2011/08/11 , T1 , 10 :confused: 2011/09/25 , T1 , 11 2011/08/11 , T2 , 15 2011/08/15 , T2 , 10 ... Because select MAX(TheDate) from Table group by Type return 2011/09/25 (for T1) 2011/08/11 (for T2) 2011/10/10 (for T3)

                    C Offline
                    C Offline
                    Chris Meech
                    wrote on last edited by
                    #12

                    Since there are multiple values the same in TheDate column it can not be used as a key and that is why you are getting those results. Another, more complicated way, is to use the date and type as a key. Try this

                    select date
                    ,type
                    ,value
                    from table t
                    , ( select max(date) max_date
                    ,type type
                    from Table
                    group by type
                    ) tg
                    where t.date = tg.max_date
                    and t.type = tg.type
                    order by type
                    ;

                    Chris Meech I am Canadian. [heard in a local bar] In theory there is no difference between theory and practice. In practice there is. [Yogi Berra] posting about Crystal Reports here is like discussing gay marriage on a catholic church’s website.[Nishant Sivakumar]

                    M M 2 Replies Last reply
                    0
                    • C Chris Meech

                      Since there are multiple values the same in TheDate column it can not be used as a key and that is why you are getting those results. Another, more complicated way, is to use the date and type as a key. Try this

                      select date
                      ,type
                      ,value
                      from table t
                      , ( select max(date) max_date
                      ,type type
                      from Table
                      group by type
                      ) tg
                      where t.date = tg.max_date
                      and t.type = tg.type
                      order by type
                      ;

                      Chris Meech I am Canadian. [heard in a local bar] In theory there is no difference between theory and practice. In practice there is. [Yogi Berra] posting about Crystal Reports here is like discussing gay marriage on a catholic church’s website.[Nishant Sivakumar]

                      M Offline
                      M Offline
                      MikeDhaan
                      wrote on last edited by
                      #13

                      :thumbsup: Super, It's now in order ! ;) Thanks

                      1 Reply Last reply
                      0
                      • C Chris Meech

                        Since there are multiple values the same in TheDate column it can not be used as a key and that is why you are getting those results. Another, more complicated way, is to use the date and type as a key. Try this

                        select date
                        ,type
                        ,value
                        from table t
                        , ( select max(date) max_date
                        ,type type
                        from Table
                        group by type
                        ) tg
                        where t.date = tg.max_date
                        and t.type = tg.type
                        order by type
                        ;

                        Chris Meech I am Canadian. [heard in a local bar] In theory there is no difference between theory and practice. In practice there is. [Yogi Berra] posting about Crystal Reports here is like discussing gay marriage on a catholic church’s website.[Nishant Sivakumar]

                        M Offline
                        M Offline
                        Mycroft Holmes
                        wrote on last edited by
                        #14

                        I'm always reluctant to push the partition/rank solution as someone always seems to come up with a simpler answer.

                        Never underestimate the power of human stupidity RAH

                        J 1 Reply Last reply
                        0
                        • M MikeDhaan

                          :thumbsup: Super, It's working ;) Thanks

                          J Offline
                          J Offline
                          Jorgen Andersson
                          wrote on last edited by
                          #15

                          If you get performance issues on this query you will need a composite index on (Type,TheDate)

                          Light moves faster than sound. That is why some people appear bright, until you hear them speak. List of common misconceptions

                          1 Reply Last reply
                          0
                          • M Mycroft Holmes

                            I'm always reluctant to push the partition/rank solution as someone always seems to come up with a simpler answer.

                            Never underestimate the power of human stupidity RAH

                            J Offline
                            J Offline
                            Jorgen Andersson
                            wrote on last edited by
                            #16

                            A partition/rank solution wouldn't need the join and therefore probably performs better. The simplest answer isn't always the best.

                            Light moves faster than sound. That is why some people appear bright, until you hear them speak. List of common misconceptions

                            1 Reply Last reply
                            0
                            • M MikeDhaan

                              :thumbsup: Super, It's working ;) Thanks

                              J Offline
                              J Offline
                              Jorgen Andersson
                              wrote on last edited by
                              #17

                              Heres a query using Rank as suggested by Mycroft

                              SELECT TheDate, TYPE, Value
                              FROM (
                              SELECT TheDate, Type, Value, Rank( ) OVER (PARTITION BY Type ORDER BY TheDate DESC NULLS LAST) RN
                              FROM MyTable
                              )
                              WHERE RN = 1

                              Just a bit curious whether performance is better.

                              Light moves faster than sound. That is why some people appear bright, until you hear them speak. List of common misconceptions

                              1 Reply Last reply
                              0
                              • M MikeDhaan

                                I have as table like TheDate Type Value I need to retreive the last value for each type. I try a SQL command like SELECT MAX(TheDate), Type, Value from MyTable GROUP BY Type But I receive an error : Erreur SQL : ORA-00979: not a GROUP BY expression 00979. 00000 - "not a GROUP BY expression" Do you have any idea ?

                                P Offline
                                P Offline
                                purnananda behera
                                wrote on last edited by
                                #18

                                SELECT MAX(TheDate), Type, Value FROM MyTable GROUP BY Type, Value

                                1 Reply Last reply
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