Bit concatenation in C++
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if you looking for string value as i understand by double quote used by you, you can use sprintf or sprintf_s. now if you want to store the binary value resulting from you operation (as you mentioned they are only 3 bit coming), you can use char datatype (1 byte) and store the decimal equivalent of it there, internally it store its binary equivalent only, for say you got 101 which decimal equivalent is 5 and when you store same in char variable, it binary representation would be 00000100
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Manoj7390 wrote:
Suggest any other way to store bits in C/C++
This has nothing to do with C/C++, it's how computers work. If you will not use the shift operators to store the three bits together then you cannot store them.
Use the best guess
Richard MacCutchan wrote:
If you will not use the shift operators to store the three bits together then you cannot store them.
int Answer = u * 4 + p * 2 + q
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Can you please suggest me a program to convert a string into binary, that store in char data type.
char * p = "101";
char * pEnd;
int val = strtol(p, &pEnd, 2);
char charval = (char)val;this may fail if p is more than 7 bits long (since that could overflow a signed char).
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Richard MacCutchan wrote:
If you will not use the shift operators to store the three bits together then you cannot store them.
int Answer = u * 4 + p * 2 + q
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But i need to concatenate the bits which are in different variables. how to concatenate those.. Since i cannot use shift operator here because of binary.
Manoj7390 wrote:
i cannot use shift operator here because of binary.
What on earth are you talking about? I have shown you exactly how to concatenate these fields into a three bit value. If you really cannot understand that simple operation then I don't think you are going to get very far with this project.
Use the best guess
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Which the compiler will almost certainly optimise into shift operations.
Use the best guess
possibly. but that extends the definition of "you" quite a bit. int Answer = u + u + u + u + p + p + q;
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Hi. I have written the program for turbo encoder, for every single bit, it gives three bits as output and I am storing it as a integer. Now the problem is how to concatenate these bits in the integer form. for example... int u = 1; int p = 0; int q = 1; Answer = 101;
Something like:
int answer = (u*100) + (p*10) + q;
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possibly. but that extends the definition of "you" quite a bit. int Answer = u + u + u + u + p + p + q;
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Chris Losinger wrote:
that extends the definition of "you" quite a bit.
:confused:
Use the best guess
you originally wrote "If you will not use the shift operators to store the three bits together then you cannot store them." that's the "you". i think it's reasonable to differentiate between what the programmer writes and what the compiler does.
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you originally wrote "If you will not use the shift operators to store the three bits together then you cannot store them." that's the "you". i think it's reasonable to differentiate between what the programmer writes and what the compiler does.