UPD large messages...
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Hi, Created software for electric switch (one directional) with UPD protocol. At first I created both sides with c#. Worked well but slow, had to restrain my "Transmitter" for the receiver to collect all relevant data. Now for better performance I program a native receiver. All is going well except the "recv" and the "recvfrom" methods only receive 517 bytes of the package size transmitted: (Maximal UDP)65507. How can I receive maximal upd package with a blocking socket?
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Hi, Created software for electric switch (one directional) with UPD protocol. At first I created both sides with c#. Worked well but slow, had to restrain my "Transmitter" for the receiver to collect all relevant data. Now for better performance I program a native receiver. All is going well except the "recv" and the "recvfrom" methods only receive 517 bytes of the package size transmitted: (Maximal UDP)65507. How can I receive maximal upd package with a blocking socket?
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Hi, Created software for electric switch (one directional) with UPD protocol. At first I created both sides with c#. Worked well but slow, had to restrain my "Transmitter" for the receiver to collect all relevant data. Now for better performance I program a native receiver. All is going well except the "recv" and the "recvfrom" methods only receive 517 bytes of the package size transmitted: (Maximal UDP)65507. How can I receive maximal upd package with a blocking socket?
This might have something to do that UDP Messages get broken up into different UDP Packets. For example, the message
"Hi, I am a UDP message and I maybe get transmitted as multiple UDP packets"
might be transmitted as
"Hi, I am a UDP mes"
"sage and I maybe get transmitted as multiple U"
"DP packets"Due to this you might need to read packets until you KNOW that the message has ended, e.g. by using a fixed message length or a defined control character marking the end of the message. To answer your question: Your socket will remain blocked until the whole message (= every data packet) is received, but you can avoid a block of your whole program by using a separate thread for your socket.
Veni, vidi, caecus | Everything summarizes to Assembly code
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This might have something to do that UDP Messages get broken up into different UDP Packets. For example, the message
"Hi, I am a UDP message and I maybe get transmitted as multiple UDP packets"
might be transmitted as
"Hi, I am a UDP mes"
"sage and I maybe get transmitted as multiple U"
"DP packets"Due to this you might need to read packets until you KNOW that the message has ended, e.g. by using a fixed message length or a defined control character marking the end of the message. To answer your question: Your socket will remain blocked until the whole message (= every data packet) is received, but you can avoid a block of your whole program by using a separate thread for your socket.
Veni, vidi, caecus | Everything summarizes to Assembly code
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That depends on which framework you will use. Are you using .Net? MFC? Native C++? Qt?
Veni, vidi, caecus | Everything summarizes to Assembly code
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You just need to create a loop that repeats the
recvcall untill there is no more data.Veni, vidi, abiit domum
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You need to keep receiving until there is no more data. TCP and UDP messages get broken up to send across the wire, so you will not always receive the complete message in one go.
Veni, vidi, abiit domum
UDP messages will not be broken up. But TCP will mostly (possibly except when Nagle is turned off).
Gisle V.
# rm -vf /bin/laden /bin/rm: success -
UDP messages will not be broken up. But TCP will mostly (possibly except when Nagle is turned off).
Gisle V.
# rm -vf /bin/laden /bin/rm: success -
UDP messages will not be broken up. But TCP will mostly (possibly except when Nagle is turned off).
Gisle V.
# rm -vf /bin/laden /bin/rm: successHi, This is incorrect if the packet is transmitted over IPv4. All packets are subject to fragmentation over IPv4 and governed by smallest MTU in the route. Note that if the DF bit is set the router will *not* fragment the packet and will instead send back an IMCP response containing the message "fragmentation needed and DF set". It would be correct to say that routers on an ipv6 network do not fragment and instead the MTU is honored at both receiving end points due to PMTUD. Best Wishes, -David Delaune