how to change DataGrid specific column alignment to Center in C# programmatically

ven753

Hi i have created DataGrid and i need to align the specific column (4th column i.e index 3) to Center in C# programmatically. I tried as below dg1.Columns[3].ItemStyle.HorizontalAlign = HorizontalAlign.Center; but giving error as follows Index was out of range. Must be non-negative and less than the size of the collection. Parameter name: index even if i give index 0 also same error How to achieve this. If anybody knows reply me. Thanks in advance.

Lost User

ven753 wrote:

even if i give index 0 also same error

That means that your columns have not yet been created at that point.

Bastard Programmer from Hell :suss: If you can't read my code, try converting it here[^]

ven753

No i have dataset and i am adding datasource to datagrid and binding as follows. dg1.DataSource = ds1.Tables["tblanni"].DefaultView; dg1.DataBind(); in ds1 4 columns is there and after binding to datagrid same column i will get in datagrid. Then how to achieve this. Please reply me.

Lost User

Change the alignment AFTER binding - the datageridview does not have the columns at the point where you are accessing them. If it did, the index would not be out of range.

Bastard Programmer from Hell :suss: If you can't read my code, try converting it here[^]

ven753

I added after binding then also its giving same error. dg1.DataSource = ds1.Tables["tblanni"].DefaultView; dg1.DataBind(); dg1.Columns[3].ItemStyle.HorizontalAlign = HorizontalAlign.Center; What to do. Please reply me.

Lost User

Is this a WinForms datagrid (prolly not), an ASP.NET grid or a WPF-grid? In WinForms, life is simple;

namespace WindowsFormsApplication1
{
public partial class Form1 : Form
{
class Test
{
public string Item1 { get; set; }
public string Item2 { get; set; }
public string Item3 { get; set; }
}

    DataGridView grid;
    public Form1()
    {
        List data = new List();
        data.Add(new Test() { Item1 = "bla", Item2 = "foos", Item3 = "bar" });

        InitializeComponent();
        grid = new DataGridView() { Dock = DockStyle.Fill };

        grid.DataSource = data;

        Controls.Add(grid);

        MessageBox.Show(string.Format("There are {0} columns in this grid", grid.Columns.Count));
    }

    protected override void OnShown(EventArgs e)
    {
        base.OnShown(e);
        grid.Columns\[0\].DefaultCellStyle.Alignment = DataGridViewContentAlignment.MiddleCenter;
    }
}

}

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ven753

No i am creating in windows service application. There i am using datagrid through service cs file i am creating dataset DataGrid dg1 = new DataGrid(); dg1.ItemStyle.HorizontalAlign = HorizontalAlign.Center; this will work for all the column items and align will become center. but i need to do for particular column not working dg1.Columns[3].ItemStyle.HorizontalAlign = HorizontalAlign.Center; How to achieve this and it is nor datagridview only DataGrid. Please reply me.

Pete OHanlon

You're creating a UI element inside a Windows Service? Why? A service has no UI, so what are you trying to accomplish here?

ven753

We can use dataset and result is coming and displaying 4 columns. Only i need to do particular column alignment. But its not working.

Pete OHanlon

You haven't answered my question. Why are you trying to do this inside a service? A service should have no user interface.

Dave Kreskowiak

Ummm, you've got a HUGE problem. Windows Services cannot display a UI. Starting with Windows Vista, services that attempt to display a UI only show their interface on a separate desktop from the user that's logged in. The user gets a notification that a service has put up a UI window and asked if they want to switch desktops to see it. UI restrictions on services have now gotten to the point where a service cannot show a UI at all. This "transition" period comes from the days on Windows XP where a service could show a UI. This is a security risk so Microsoft has removed the ability to do this from Windows.

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Dave Kreskowiak

Lost User

Next to the "no UI" issue, there's also the point the a DataGrid[^] doesn't have a columns-property. Yes, it is faster in displaying data than a DataGridView, but it doesn't have as much features built in.

Bastard Programmer from Hell :suss: If you can't read my code, try converting it here[^]

ven753

Ya but i have created one html file and for that i am sending this dataset after rendering as StringWriter stringWriter1 = new StringWriter(); HtmlTextWriter htmlWrite1 = new HtmlTextWriter(stringWriter1); i am trying read html file and after reading just rendering the control as shown below dg1.RenderControl(htmlWrite1); i am getting html file result and that 4 column grid. Only i need to make particular column alignment. How to do this.

ven753

Ya but i have created one html file and for that i am sending this dataset after rendering as StringWriter stringWriter1 = new StringWriter(); HtmlTextWriter htmlWrite1 = new HtmlTextWriter(stringWriter1); i am trying read html file and after reading just rendering the control as shown below dg1.RenderControl(htmlWrite1); i am getting html file result and that 4 column grid. Only i need to make particular column alignment. How to do this.

ven753

But through coding if i type DataGrid.Columns[] Columns property it will show. But after adding below code it is not working dg1.Columns[3].ItemStyle.HorizontalAlign = HorizontalAlign.Center; What to do. Please reply me.

Pete OHanlon

If you're just trying to write out to a file as HTML, then why are you trying to write it out this way? A simpler method would be to save your DataSet out as XML and use a page that XPath to read and display the content.

Dave Kreskowiak

What does this have to do with writing a Windows Service application?

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How to debug small programs
Dave Kreskowiak

Lost User

ven753 wrote:

Columns property it will show.

Only if you're referencing a DataGridView, and that's a different control. Either you switch to the DataGridView, or you adjust the requirement of needing the alignment.

Bastard Programmer from Hell :suss: If you can't read my code, try converting it here[^]