one equal to two ?
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tayoufabrice wrote:
1/9 = 0.111111111111111111111111...... is not really true ; we lost 0.000000000000000000000.......9
Wish I could agree, but I can't... read all about it[^] :-D Even google 0.999999999999999 = 1[^] if you're still unconvinced.
Ah là là :laugh: Mathematics !! (French laughing)
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Let read this :
1=1 a=a a²=a² a²-a²=a²-a² a(a-a)=(a+a)(a-a) a=a+a a(1)=a(1+1) 1=1+1 1=2Where is the error ?a(a-a) = (a+a)(a-a) // divide by (a-a), i.e. divide by 0 a = a+a Division by zero is a no-no because it can lead to "impossible" results like the above.
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a(a-a) = (a+a)(a-a) // divide by (a-a), i.e. divide by 0 a = a+a Division by zero is a no-no because it can lead to "impossible" results like the above.
I could fix the post as : Given a C ]--;0[ U ]0;++[ (meaning 0 excluded) Now ??
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I could fix the post as : Given a C ]--;0[ U ]0;++[ (meaning 0 excluded) Now ??
The value of a is irrelevant; a - a == 0, and factoring out a - a is division by 0, which is forbidden. I am not a mathematician, so I don't know if it is possible to create a self-consistent arithmetic in which division by 0 does not result in nonsensical results. All I know is that in the arithmetic I learnt in school it is forbidden.
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The value of a is irrelevant; a - a == 0, and factoring out a - a is division by 0, which is forbidden. I am not a mathematician, so I don't know if it is possible to create a self-consistent arithmetic in which division by 0 does not result in nonsensical results. All I know is that in the arithmetic I learnt in school it is forbidden.
Sure ! :laugh: number can never be divided by zero 0 ; even 0/0 :confused: It is the real error of my process