strong type in XML
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how to do the following using .NET I have the following XML document :
**3.14159**If I were using COM MSXML parser, I could get NodeTypedValue property to get "strongly-typed" value. b= XMLDocument.SelectSingleNode("//b"); variant value = b.NodeTypedValue; //now the variant contains double value. The question is: how to achieve the same using C# ? Value property of XMLNode object returns String type, wchich i have to convert to get desired type... How to do this without explicit conversion (by the means of XMLConvert class or similar...) Thanks Michal Januszczyk