To write a c program to maintain a log of football match b/w 2 teams and then compare the results of the log entered by user and announce the winner.

Tarun Jha

here is the code i have wrriten but when reaching the for()loop it just skips though the first loop of for( i.e. i=0 )and starts with i=1. What is wrong in the code.

#include
#include

int main()
{
int i, log, k, c1=0, c2=0, j=0;
char team_1[100], team_2[100], input[100], ch;

printf("Enter name of Team-1: \\n");
gets(team\_1);

printf("Enter the name of Team-2\\n");
gets(team\_2);

if(strcmp(team\_1, team\_2)==0)
{
    printf("Oops! both names are same. Please enter again: \\n");
    while(strcmp(team\_1, team\_2)==0)
    {
        printf("Enter name of Team-1: \\n");
        gets(team\_1);

        printf("Enter the name of Team-2\\n");
        gets(team\_2);
    }
}

printf("Enter the number of logs: \\n\\n");
scanf("%d", &log);

for(i=0; ic2)
	printf("Team-1 wins");
else
	printf("Team-2 wins");

return 0;

}

Victor Nijegorodov

Tarun Jha wrote:

when reaching the for()loop it just skips though the first loop of for( i.e. i=0 )and starts with i=1

How did you find out it? Did you debug your code? Then what are the values of i and log right before stepping in the loop?

Tarun Jha

This is the output i am getting. As you can see for i=0, it just skips through.

Quote:

Enter name of Team-1: rob Enter the name of Team-2 max Enter the number of logs: 5 Enter log-1 Invalid entry ! Enter log-2 max Enter log-3 max Enter log-4 rob Enter log-5 max Team-2 wins Process returned 0 (0x0) execution time : 23.573 s Press any key to continue.

Lost User

Why are you asking for both team names if they are equal? You already have team_1 name so you only need a different name for team_2. You do not need to clear the input array as it will get overwritten on the next gets call. And it skips the first loop because scanf leaves a newline character in the input buffer which then is consumed by the first call to gets. If you did as I have suggested elsewhere you could figure all these things out for yourself.

Tarun Jha

This is the output

Enter name of Team-1:
rob
Enter the name of Team-2
max
Enter the number of logs:
5

Enter log-1
Invalid entry !

Enter log-2
max

Enter log-3
max

Enter log-4
rob

Enter log-5
max

Team-2 wins
Process returned 0 (0x0) execution time : 23.573 s
Press any key to continue.

Tarun Jha

are you suggesting that i initialize input to zero before applying gets() as you told me to do in the previous question answered by you.

Victor Nijegorodov

Tarun Jha wrote:

Enter the number of logs: 5 Enter log-1

And there is your code:

for(i=0; i

So why do you think the loop skips when i is zero??? It works and prints the result
"Enter log-1"

Tarun Jha

no, it doen't take input for first loop, it just skips to the second one, does'nt matter from where i is initialized. Please run the code you will understand.

Lost User

No, I am telling you to go and get a proper study guide and learn the C language in complete detail.

Tarun Jha

ok

Tarun Jha

i will but befoer that can you show me how to correct the buffering problem of scanf() in order to remove newline charecter from gets().

Lost User

fflush(stdin) - Google Search[^]

Tarun Jha

And here is the working code :)

#include
#include

int main()
{
int i, log, j, c1=0, c2=0;
char team_1[100], team_2[100], input[100], ch;

printf("Enter name of Team-1: \\n");
gets(team\_1);

printf("Enter the name of Team-2\\n");
gets(team\_2);

if(strcmp(team\_1, team\_2)==0)
{
    printf("Oops! both names are same. Please enter again: \\n");
    while(strcmp(team\_1, team\_2)==0)
    {
        printf("Enter name of Team-1: \\n");
        gets(team\_1);

        printf("Enter the name of Team-2\\n");
        gets(team\_2);
    }
}

printf("Enter the number of logs: \\n");
scanf("%d%\*c", &log);

for(i=0; ic2)
	printf("\\nTeam-1 wins");
else if(c1

Tarun Jha

And here is the working code..

#include
#include

int main()
{
int i, log, j, c1=0, c2=0;
char team_1[100], team_2[100], input[100], ch;

printf("Enter name of Team-1: \\n");
gets(team\_1);

printf("Enter the name of Team-2\\n");
gets(team\_2);

if(strcmp(team\_1, team\_2)==0)
{
    printf("Oops! both names are same. Please enter again: \\n");
    while(strcmp(team\_1, team\_2)==0)
    {
        printf("Enter name of Team-1: \\n");
        gets(team\_1);

        printf("Enter the name of Team-2\\n");
        gets(team\_2);
    }
}

printf("Enter the number of logs: \\n");
scanf("%d%\*c", &log);

for(i=0; ic2)
	printf("\\nTeam-1 wins");
else if(c1

Vaclav_

You have identified "problem area " , so work on problem area first. No matter how many books you read , they will NEVER tell you that MAJORITY of errors are typos, and than you will have hidden SYNTAX errors. The last errors are programming - LOGICAL errors. Before you compare real INPUTS, you have to have correct program sequence working so emulating the actual inputs would be next step. You are starting Backward with analysis of logical / real input errors. PS You have a "numerical" application , so prefacing printed numbers with "minus" sign" seems little odd. for(i=0; i

Victor Nijegorodov

Dear Vaclav_, could you edit your post to properly format the code snippet? Otherwise it is very hard to read/understand.

Tarun Jha

it works too..

#include
#include
#include

int main()
{
int log, i, j, k, count1=1, count2=0, c;

printf("Enter the number of logs: \\n");
scanf("%d%\*c", &log);

char names\[log\]\[100\];

//Entering names.
printf("Enter names: \\n");
gets(names\[0\]);

//completing in a single loop.
for(i=1; icount2)
        {
        	puts(names\[0\]);
        	printf("Wins !");
		}
		else if(count2>count1)
		{
			puts(names\[k\]);
			printf("Wins !");
		}
		else if(count1==count2)
		{
			printf("It's a tie!!");
		}
        break;
	}
	count1++;
}
return 0;

}