you can make another funciton and call it on loading the page e.g. her is the javascript code, you can esily change it to vb script: (for easy access I'll suggest you to add ID to each radio button as and function showHide() { if(document.getElementById('rbYes').checked) show('hideable'); else if(document.getElementById('rbNo').checked) hide('hideable'); } and call this onload of body as ... -----

I would do something like this: window.onload = LoadDefaults(<% Session("rdaspiration") %>); function LoadDefaults(rdaspiration) { if (rdaspiration == "yes" ) { show("hideable1") } else {show("hideable2") } } I think something like that should work. I didn't try it in a browser so the syntax may not be correct but the general idea should work. "Half this game is ninety percent mental." - Yogi Berra

Converting a yes/no to a bit.... Enum MyBool YES = 0 NO = 1 End Enum dim bValue as byte bValue = Convert.ToByte(MyBool.YES) Or you could use this method I put together for converting strings Public Sub ConvertStringByte(ByVal stringVal As String) ' Convert the string to a char array Dim chArray() As Char chArray = stringVal.ToCharArray(0, stringVal.Length) 'Convert each char into a byte Dim i As Short Dim b As Byte Dim byArray(stringVal.Length) As Byte For i = 0 To chArray.Length - 1 b = System.Convert.ToByte(chArray(i)) byArray(i) = b Next 'Write each value out and the entire bytes For i = 0 To byArray.Length - 1 Console.Write(byArray(i).ToString() & ":") Next 'Reconstruct the string value and print it For i = 0 To byArray.Length - 1 Console.Write(Convert.ToChar(byArray(i))) Next End Sub

Loop through radio buttons and check which are ticked Sanjay Sansanwal www.sansanwal.com

If you're trying to bind the actual list, you need to need to fill the Items property manually. Binding the Text only binds the Text property. You should read about the DataBindings property and the BindingManagerBase class in the .NET Framework SDK. The code you're doing above needs to bind to the Text property of the control for which the Binding is added (i.e., lstFacilityType). The rest of your expressions won't work, however, because the Binding only works for PropertyManager, not to bind to an IListSource or IList, of which DataSet and DataTable are (respectively). When you bind to a data-bound control like a DataGrid, it nows how to use the DataSource and, optionally, the DataMember to enumerate the collection and bind a UI element to that row. Binding how you're doing it is not the same. The results you're getting are to be expected since you're binding against an object, not its value. This posting is provided "AS IS" with no warranties, and confers no rights. Software Design Engineer Developer Division Sustained Engineering Microsoft [My Articles]

Because .NET have added them to group in that order. Look into InitializeComponent method You would see something like // // groupBox1 // this.groupBox1.Controls.Add(this.checkedListBox4); this.groupBox1.Controls.Add(this.checkedListBox3); this.groupBox1.Controls.Add(this.checkedListBox2); this.groupBox1.Controls.Add(this.checkedListBox1); Sanjay Sansanwal www.sansanwal.com

Consider that you might have nested controls, that a CheckedListBox may not be a direct child of a GroupBox. Consider a generic recursive loop like so: void ClearSelected(ControlCollection controls) { if (controls == null || controls.Count == 0) return; // Quick foreach (Control control in controls) { if (control is CheckedListBox) ((CheckedListBox)control).ClearSelected(); ClearSelected(control.Controls); } } This will encounter any CheckedListBox at any depth in the parent/child hierarchy of controls. This posting is provided "AS IS" with no warranties, and confers no rights. Software Design Engineer Developer Division Sustained Engineering Microsoft [My Articles]

That really a fairly simple problem. You can get one or multiple values using ListBox.SelectedItems. Enumerate that property collection to get values. For each ListBox, you do this again. How you construct the query is up to you, but string concatenation, String.Concat, StringBuilder.Append, and many other ways can help you. Software Design Engineer Developer Division Sustained Engineering Microsoft [My Articles]

u can acess any column by this dr.getstring(x) where dr is datareader object getstring is data type column and x index of column which starts from 0 for the first column;P

That's is because you combo box's data source is set to ArrayList that is not updated when you add new user. The new user is added to the table without syncronizing the ArrayList. Try to replace all the values in the ArrrayList with the table when there is new user added. I am not expert. I am just a beginner. Learning .NET

Actually, that would throw a TypeLoadException since the types are not the same, but you apparently handled the exception and continued executing code, meaning that the object you were trying to instantiate of that type was still null, hence the NullReferenceException. You can avoid this problem in your multi-project solution by adding project reference instead of assembly reference. So, if project "B" depends on project "A", right-click on project "B", select Add Reference, then click the Projects tab. Double-click project "A" to add it. Now a build dependency is established. Any changes to project "A" will cause project "A" to be compiled when you compiled project "B", and if project "A" is recompile project "B" will grab the new copy when it's compiled. This also means that when you compile a release build of project "B", a release build is compiled for project "A", thus keeping your builds in sync as well. Microsoft MVP, Visual C# My Articles

If you have a question about a specific product, you should ask on their site (forums, contact emails, etc.). This is not specific to C#, nor should it be expected of this community to support a commercial or non-commercial product; we probably have never even used it. This is what company/organization support sites are for. Based on the exception, though, all I can tell you is that your not setting an instance to something, which should be evident from the error. Microsoft MVP, Visual C# My Articles

Create a key pair using sn.exe -k KeyFile.snk. When you generate an interop assembly, use the /keyfile:<filepath> switch to both tlbimp.exe and aximp.exe (if importing an ActiveX control to derive from AxHost as well). If you're doing this from within VS.NET, go to the project configuration and in there is a place you can either entire a file path (relative to the project root) or a key container name. I typically install my key into my machine store using sn.exe -i KeyFile.snk MyContainerName (obvious use a container name you want). I would delete the interop assemblies you've already created and regenerate them as I've mentioned here. Also be sure you use a key pair (possibly the same one - it helps identify your assemblies, though it's not verifiable like X.509 certificates). A strong name requires that the assembly be signed, which you seem to already know. A strongly named assembly can only use strongly named assemblies. Microsoft MVP, Visual C# My Articles