Thanx man, I'll do it.

OK man, thanx. that's my answer.

Hi I'll develop a website that people will post something formatted with HTML with some pictures. Which way is better to save these content (long HTML with several pictures)? Save them in db or save them on disk? Why? Thanks a lot.

Hi there I'm developing a website that is multi language. Which is the best way (fastest and easiest) to design site? for example Make several site in different langs or bind controls to db and read the values from db or ... . What do you suggest and why? Thanks a lot

Hi Dears I traveled from VS2005 To VS2008 team system. It's so good, but i got a problem! In VS2005, we can change the "Default Css Positioning" and set it to Absolute, but in VS2008 i can't find this option. Please Help me. Thank you for your help in anticipation.

The easier way is using a dataset n update it. Good Luck.:rose:

You can use this, it's simple: dataSet11.DataTable1.AddDataTable1Row(File.ReadAllBytes("C:\\File.ext")); sqlDataAdapter1.Update(dataSet11.DataTable1); Just u must using System.IO. Dataset1.DataTable1 have 1 column, it's datatype is binary. and File.ReadAllBytes("FilePath") raturn a byte[] datatype (equal binary). Good Luck.:rose:

Hello to Nana you must use this code in FormLoad event for fill dataset: prodadapter.fill(productitemdataset); and use this code for add a new row to db: ProductItemdataset.(TableName).AddNew(TableName)Row(field1,...); ProdAdapter.Update(ProductItemDataset); Good Luck. Editali (Alireza Loghmani):)

hello to khoramdin you can use this code for load a picture to a picturebox from a datagridview cell: in CellContentClick event you can type this code: pictureBox1.Image = Image.FromFile(dataGridView1.CurrentCell.Value.ToString()); Good Luck. Editali (Alireza Loghmani)

you can use this code: toolStripTextBox1.Focus(); toolStripTextBox1.SelectAll(); Good Luck. Alireza Loghmani

hello to khoramdin you can use this code for load a picture to a picturebox from a datagridview cell: in CellContentClick event you can type this code: pictureBox1.Image = Image.FromFile(dataGridView1.CurrentCell.Value.ToString()); Good Luck.:-D Editali (Alireza Loghmani)

you must use this code Form2 frm = new Form2(); frm.MDIParrent = this; frm.Show();;) note: Your MDI Form must larger than child Form.