Sombody?

Yes im trying some things do will say when it is owkring here. Now waiting for somebody else his help. Thanks!

II've used this code now all is working BUT!: Here is is coming: If i mouseenter and mouseleave it now it is changing the image and if i disable the Bring toFront it is working?

using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.Linq;
using System.Text;
using System.Windows.Forms;

namespace KVzoekscherm
{
public partial class runtimeobject : Form
{
Button button1;
Button button2;
Bitmap image1;
PictureBox pictureBox1;

    public runtimeobject()
    {
        InitializeComponent();
    }

    //Deze functie roept hij op wanneer hij over de (grote) picturebox gaat
    private void pbMaak\_Click(object sender, EventArgs e)
    {
        pictureBox1 = new PictureBox();
        pictureBox1.Name = "pictureBox1";
        pictureBox1.BringToFront();
        pictureBox1.SizeMode = PictureBoxSizeMode.StretchImage;
        pictureBox1.BorderStyle = BorderStyle.None;
        pictureBox1.ClientSize = new Size(15, 15);
        pictureBox1.Location = new System.Drawing.Point(50, 50);
        pictureBox1.Cursor = Cursors.Hand;
        pictureBox1.Anchor = AnchorStyles.Top | AnchorStyles.Right;
        pictureBox1.TabIndex = 28;

        image1 = new Bitmap(Properties.Resources.edit\_gray);
        pictureBox1.Image = (Image)image1;

        pictureBox1.Click += new EventHandler(editclick);
        pictureBox1.MouseLeave += new EventHandler(editleave);
        pictureBox1.MouseEnter += new EventHandler(editenter);
        this.Controls.Add(pictureBox1);
    }

    private void editenter(object sender, EventArgs e)
    {
        image1 = new Bitmap(Properties.Resources.edit\_color);
        pictureBox1.Image = (Image)image1;
    }

    private void editleave(object sender, EventArgs e)
    {
        image1 = new Bitmap(Properties.Resources.edit\_gray);
        pictureBox1.Image = (Image)image1;
    }

    private void editclick(object sender, EventArgs e)
    {
        MessageBox.Show("Clicked");
    }

    private void runtimeobject\_Load(object sender, EventArgs e)
    {

    }

    private void pbMaak\_Click\_1(object sender, EventArgs e)
    {

    }
}

}

But: pictureBox1.SendToBack(); I will need to send pictureBox1 to the front :P That option doesn't Exist. SendToFront :(

I've made a picturebox where I have a runtime code in. There i open a other Picturebox, but that picturebox I run runtime from the Design Picturebox is under the design picturebox and must be at the top. Hope somebody can help. Dennis,

using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.Linq;
using System.Text;
using System.Windows.Forms;

namespace KVzoekscherm
{
public partial class runtimeobject : Form
{
Button button1;
Button button2;
Bitmap image1;
PictureBox pictureBox1;

    public runtimeobject()
    {
        InitializeComponent();
    }

    //Deze functie roept hij op wanneer hij over de (grote) picturebox gaat
    private void pbMaak\_Click(object sender, EventArgs e)
    {
        pictureBox1 = new PictureBox();
        pictureBox1.SizeMode = PictureBoxSizeMode.StretchImage;
        pictureBox1.BorderStyle = BorderStyle.None;
        pictureBox1.ClientSize = new Size(15, 15);
        pictureBox1.Location = new System.Drawing.Point(50, 50);
        pictureBox1.Cursor = Cursors.Hand;
        pictureBox1.Anchor = AnchorStyles.Top | AnchorStyles.Right;
        pictureBox1.TabIndex = 28;

        image1 = new Bitmap(Properties.Resources.edit\_gray);
        pictureBox1.Image = (Image)image1;

        pictureBox1.Click += new EventHandler(editclick);
        pictureBox1.MouseLeave += new EventHandler(editleave);
        pictureBox1.MouseEnter += new EventHandler(editenter);
        this.Controls.Add(pictureBox1);
    }

    private void editenter(object sender, EventArgs e)
    {
        image1 = new Bitmap(Properties.Resources.edit\_color);
        pictureBox1.Image = (Image)image1;
    }

    private void editleave(object sender, EventArgs e)
    {
        image1 = new Bitmap(Properties.Resources.edit\_gray);
        pictureBox1.Image = (Image)image1;
    }

    private void editclick(object sender, EventArgs e)
    {
        MessageBox.Show("Clicked");
    }

    private void runtimeobject\_Load(object sender, EventArgs e)
    {

    }

    private void pbMaak\_Click\_1(object sender, EventArgs e)
    {

    }
}

}

Fixed the problem now. Thaks for the reply's!!

I've made this already: picBox1.MouseEnter += new EventHandler(EventHandlerName); picBox2.MouseEnter += new EventHandler(EventHandlerName); But I must declare in the eventhandler that it is changed the only the image the one where the mouse is hovering then, not all images. 1 eventhandler where he only works with the image where it's mouseentering and mouse leaving then. It's difficult to explain for me.

Im having 10 picturesboxes that im using as button. When im mouse over over now it is changed from image. and when i click on that button its openeing in every 10 buttons a different window. Have that now :) But all 10 picatureboxes must have the same mousenter and mouseleave event. SO i didnt't want to make 10 the same mouseenter and mouseleave events. Is it possible in 1?

First i had this:

private void pbEdit_OnMouseEnter(object sender, EventArgs e)
{
pbTextEdit.Image = Image.FromFile("C:/data/edit_color.gif");

} Now I wanna use 1 function for different pictureboxes: My code i was thinking of but didn't work :( this.Image = Image.FromFile("C:/data/edit_color.gif"); Dennis,

private void pbTextEdit_Click(object sender, EventArgs e)
{
Header header = new Header();
header.Show();

    }

    private void pbTextEdit\_MouseHover(object sender, EventArgs e)
    {
        pbTextEdit.Image = Image.FromFile("C:/data/edit\_color.gif");
    }

I'f im hovering it it ain't changing the image? What i wanna do is: Only when I'm moving with my mouse over the picturebox that it is changing from picture then. And when I leave it it is going back to the normal one in the properties. Dennis

But this isn't working at any computer?

Changed my code, can I make it easier? TO read and write? I don't know much about C#... :) using System; using System.Collections.Generic; using System.ComponentModel; using System.Data; using System.Drawing; using System.Linq; using System.Text; using System.Windows.Forms; namespace W1 { public partial class w1 : Form { public w1() { InitializeComponent(); } private void w1_Load(object sender, EventArgs e) { } private void exitToolStripMenuItem_Click(object sender, EventArgs e) { Application.Exit(); } private void btnDrop_Click(object sender, EventArgs e) { //Maakt een 2 maal 5 keer getallen aan Random random = new Random(); int randomNumber1C = random.Next(1, 7); int randomNumber2C = random.Next(1, 7); int randomNumber3C = random.Next(1, 7); int randomNumber4C = random.Next(1, 7); int randomNumber5C = random.Next(1, 7); int randomNumber1 = random.Next(1, 7); int randomNumber2 = random.Next(1, 7); int randomNumber3 = random.Next(1, 7); int randomNumber4 = random.Next(1, 7); int randomNumber5 = random.Next(1, 7); //Zet de 2 maal random 5 getallen in goede volgorde (speler) List<int> randomList = new List<int>(); randomList.Add(randomNumber1); randomList.Add(randomNumber2); randomList.Add(randomNumber3); randomList.Add(randomNumber4); randomList.Add(randomNumber5); randomList.Sort(); //berekening(speler) int last = 0; foreach (int itemInRandomList in randomList) { if (itemInRandomList == last || itemInRandomList - last != 1) { last = 0; break; } last = itemInRandomList; } //Resultaat of hij gewonnen of verloren heeft(speler) if (last == 0) { lblDropped.ForeColor = System.Drawing.Color.Red; lblDropped.Text = "LOST"; } else { lblDropped.ForeColor = System.Drawing.Color.Green; lblDropped.Text = "WON"; } //Zet de 2 maal random 5 getallen in

I'm making Yahtzee but I've 1 question: I've 5 stones which must be generated randomly between 1 and 6. If I've a 1,2,3,4 and 5 in this 5 stones it need's to display "GOOD" otherwise "LOST" SO 2,1,3,5,4 is "GOOD" SO 1,1,3,4,5 is "LOST" How can I do this can somebody help me please with it :^) So I can go further. I must work with array'sin my opinion but didn't have much knowledge of them :( Hope somebody can improve my code or say how I must do it. (I'm learning) My Code: using System; using System.Collections.Generic; using System.ComponentModel; using System.Data; using System.Drawing; using System.Linq; using System.Text; using System.Windows.Forms; namespace W1 { public partial class w1 : Form { public w1() { InitializeComponent(); } private void w1_Load(object sender, EventArgs e) { } private void exitToolStripMenuItem_Click(object sender, EventArgs e) { Application.Exit(); } private void btnDrop_Click(object sender, EventArgs e) { Random random = new Random(); int randomNumber1C = random.Next(1, 7); int randomNumber2C = random.Next(1, 7); int randomNumber3C = random.Next(1, 7); int randomNumber4C = random.Next(1, 7); int randomNumber5C = random.Next(1, 7); lblDice1C.Text = "Dropped: " + randomNumber1C.ToString(); lblDice2C.Text = "Dropped: " + randomNumber2C.ToString(); lblDice3C.Text = "Dropped: " + randomNumber3C.ToString(); lblDice4C.Text = "Dropped: " + randomNumber4C.ToString(); lblDice5C.Text = "Dropped: " + randomNumber5C.ToString(); if (randomNumber1C == 1 && randomNumber2C == 2 && randomNumber3C == 3 && randomNumber4C == 4 && randomNumber5C == 5 || randomNumber1C == 2 && randomNumber2C == 3 && randomNumber3C == 4 && randomNumber4C == 5 && randomNumber5C == 6) { lblDroppedC.ForeColor = System.Drawing.Color.Green; lblDroppedC.Text = "WON"; } else { lblDroppedC.ForeColor = System.Drawing.Color.Red; lblDroppedC.Text = "LOST"; } int randomNumber1 = random.Next(1, 7); int randomNumber2 = random.Next(1, 7); int randomNumber3 = random.Next(1, 7); int randomNumber4 = random.Next(1, 7);

I've a application running now with a database connection and wanna make a deployment of it I tried much things. So that's why I'm asking now is there a easy guide to follow where I can see what to do. My connection string is hard coded, after I deployed the application it's still hard coded what is the way to let the Data Source (Computer Name) change automaticly to the new computername where it is installed? (return @"Data Source=KONING-AF02EAF7\SQLEXPRESS;Initial Catalog=KringVrienden;Integrated Security=True";) SofwareI'm using: Visual Studio 2008. SQL Server 2005 SQL Management Server 2005 Please help me. Dennis,