A combination of masking and shifting will work. For example: ulong ulValue = 0xF345612347892019UL; ulong ulMask; int iBitValue; for ( int iBit = 0; iBit < 64; ++iBit ) { ulMask = 1UL << iBit; iBitValue = (int)((ulValue & ulMask) >> iBit); System.Console.WriteLine( "Bit {0}: {1}", iBit, iBitValue ); } Stability. What an interesting concept. -- Chris Maunder

Yes, call sp_who, then KILL all the processes attached to your database ( thanks to whoever provided this solution, I asked this question only last week :-) ) Actually, that solves the problem in SQL Server. MySQL is kind of crap ( it doesn't even have stored procedures ), and in addition, sp_who is SQL Server specific, you'd need to find the equivelant in MySQL. Christian I have drunk the cool-aid and found it wan and bitter. - Chris Maunder

well it appears that you are reloading from the database the same value again from the pageload method of the page objec.t you might want to check to see if you added in the pageload method a mechanism checking for postback. example ... PageLoad( .. ) { if( Page.IsPostBack ) { // save data from textboxs to database and load them into the // page controls } else { // load initial values of the controls on the page } } ... Danny!

Let us say you created web service with some web method called foo(). Now you create a web page in a new project from which you want to call this web service. The first thing you need to do is to add a web reference to the Reference node of your project. This opens up a wizard where you need to reference your .asmx or .wdl url reference. Once you do this, you have the localhost( your local website)with the web service ready. Add a button to your page. In the click event you need to create the following code. Before you write this code, at the top of the page, you need to add: imports localhost.service1 in the click event add the following code: dim mysvc as new service1 document.write(mysvc.foo()) ps;The service1 is having the method foo() when you created the web service. I will try to write a codewalk on this next time to the CodeProject. :)

I think you'll find it easier than you think, and if you have questions, come back and see us. Good luck. -Jeff here, bloggy bloggy