Hello, I think fatsest way would be a loop!
byte\[\] b1 = new byte\[5\];
b1\[0\]=1;
b1\[1\]=2;
b1\[2\]=3;
b1\[3\]=4;
b1\[4\]=5;
byte\[,\] b2 = new byte\[2, b1.Length\];
for(int x=0;x < b1.Length;x++)
{
b2\[0,x\]=b1\[x\];
}
All the best, Martin -- modified at 6:58 Wednesday 30th May, 2007