no, i really need a help on this problem, but just because quite hard to describe here, as it is a Genetic algorithm problem...,in the format i type, i try to make yours understand, but look like quite hard to do so, so no choice, i have to give up le..
sinbear
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How to solve this question??? -
How to solve this question???111100001 1 1100000 111100010 00000000111 00000000111 00000000111 ok, now i change the - to 0, to try to explain this example more clear, this file will be print out in txt format, require the c++ to read from the txt file and also, it is the birnary format, and now can see that the void V is the whole among the group of 1, 1111 1 11 1111 the two exceptional 1 E is locate at: 00001 00000 00010 which consider at not inside the group of 1 and like this 111 111 111 will consider as a group of 1 and so S = (A-E)/(A+V) is this help to explain the problem? thanks sorry to have to post this question again?
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how to solve this problem(posted again)111100001 1 1100000 111100010 00000000111 00000000111 00000000111 ok, now i change the - to 0, to try to explain this example more clear, this file will be print out in txt format, require the c++ to read from the txt file and also, it is the birnary format, and now can see that the void V is the whole among the group of 1, 1111 1 11 1111 the two exceptional 1 E is locate at: 00001 00000 00010 which consider at not inside the group of 1 and like this 111 111 111 will consider as a group of 1 and so S = (A-E)/(A+V) is this help to explain the problem? thanks
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how to solve this problem(posted again)1111-----1 1 11------ 1111----1- --------111 --------111 --------111 hi, as the previous question may not so easy to see, so i post the question out again here.. this is just only a example, and using C++ to solve plenty of these similiar example. In this problem, you can ignore all the - simbol as they stand for the space only, and you can see that: the hole formed inside many 1 consider call void element=V; here v = 1 two 1 which is quite far away from others is call exceptional element=E,here E = 2; let the total number of 1 =A; here A = 22 i need to use the C++ to calculate the below result S = (A-E)/(A+V) for example this case s = (22-2)/(21+1)=0.91 So how to write a C++ program, to search for the void element V; the exception element E as well as the total number of 1 A and calculate the result?? i am so eager to know the knowledge about this, may anyone give me a hand??? Your great help will be appreciated!!, thank so much. please send to my email sinbearzc@hotmail.com if you can give me a help, thank..
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How to write a C++ program to find out these???sorry, the formation show out is not the same as i want to type, i have to choose another way, as below, thanks 1111 1 11 1111 1 1 111 111 111
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How to write a C++ program to find out these???1111 1 1 11 1 11 1 111 111 111 hi, experts,really need your helps, i have one project to do this using C++. this is just only a example, In this problem, you can see that the hole inside many 1 consider call void element=V, two 1 which is quite far away from others is call exceptional element=E, the total number of 1 is =A; i need to use the C++ to calculate the result S = (A-E)/(A+V), for example this case s = (21-2)/(21+1)=0.86. So how to write a C++ program, to search the void element, the exception element as well as the total number of 1 and calculate the result?? i am so eager to know the knowledge about this, may anyone give me a hand??? Your great help will be appreciated!!, thank so much. please send to my email sinbearzc@hotmail.com if you can give me a help, thank..
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machine cell formation using genetic algorithmhi, experts, my project on solving the machine cell formation problem using genetic algorithm has encounter problems, the requirment for this project is to arrange the machines into different cells that can get the optimize timing and most efficiency, i don't know how to use the C++ to solve this problem, can anyone give me a hand!!!, this is my FYP, if i can't do it, i can't graduate, so any suggestion or need more detail about this project please contact me at sinbearzc@Hotmail.com, thank you so much!!! ;)