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index & 0x01 It is a test on last bit of the index variable: it is 1 when index is odd (0 when index is even).

You are not rebuilding the array to match what it would look like after all the rotations. You are looking at a single index in the array. The logic applies to what is the effect of a rotation to that index alone - not the whole array. Socialism is the Axe Body Spray of political ideologies: It never does what it claims to do, but people too young to know better keep buying it anyway. (Glenn Reynolds)

thank you

You are welcome.

thank you !

You are welcome.

Since you know at compile time the array size, why don't you allocate it on the stack? #include #include using namespace std; constexpr size_t SIZE = 3; class Vector { array x{}; public: Vector (const array & a) { for (size_t n=0; n x{1,2,3}; array y{6,3,9}; Vector v1{x}; Vector v2{y}; cout << "v1 " << v1 << endl; cout << "v2 " << v2 << endl; cout << "v1*v2 = " << (v1*v2) << endl; }

may be you can find the solution here : Is there is any alternative to kbhit() for Linux? - Quora[^]

cin.get() does not read individual keystrokes -- the input is buffered by the terminal until you hit Enter, then all of the input is sent to the program at once. To read individual keystrokes, you'll have to rely on a third-party tool like GNU's ncurses library.

To me you are sort of asking a strange question well outside the literal string part, so lets just check you understand some basics First a string is class or if you want an object it has constructors, destructor and methods it isn't just an array of characters. string - C++ Reference[^] You can't remotely equate those two lines as anything similar, do you understand that? So with a string class when you declare it as a const (like your commented out) what are you expecting it will do? So you are clear you are asking for a constant pointer to an object and trying to set some literal string to that object. This may also help understand Victors response and David deals with the literal part. The point here is you can only create a string when it matches one of the constructor types of the class. What constructor functions exist controls how you can create it. Here is the examples of showing the seven standard constructor methods for the class string::string - C++ Reference[^] The situation with just a character array is very different const char *ptr = "tarun"; We have a simple array of characters that can never be changed AKA they are constant Everything from a C to a C++ compiler understands the later because it's very trivial. In vino veritas

i am currently following "C++ The complete reference by : Herbert Schildt"

Welcome to C++. :-D I mean: constructors are the very basics of an OOP language (you must be sure to grasp them before even attempting to code). accessing an otherwise unaccessible member is the very purpose of the friend declaration.

You are welcome.

ok... thanks for the advice

ok

As Victor Nijegorodov noted, your code violates the rule of three[^]: you have to define the assignment operator.

friend istream & operator >> (istream &, vector &); That is just for telling the computer the extraction operator (>>) is friend of the vector class. The reference (&) is part of the extraction operator signature, e.g. istream & operator >> (istream & is, vector & v); Because such a operator takes a reference to istream and a reference to a vector as arguments. returns a reference to a istream. Incidentally this the magic underneath the extraction operator chaining, for instance: cin >> v >> i; -> (cin >> v) >> i; -> cin >> i; -> cin;

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