Make a pile of all the coins. Take 14 from there to make the second pile. Turn all the coins in the second pile upside down. the pile: H:270 T:14 two piles: H:270-t T:t; H:t T:14-t (t is whatever number of tails in the big pile) upside down the small pile: H:270-t T:t; H:14-t T:t (Done). Ooh, ooh. (Anyone notice the error in my answer to the ant on the rope? - should have been exp(100)-1 seconds. I had stopped the ant at the starting point of the other post rather than where it had moved to. - So I now agree with the other responder except I think he used 364 days in a year??)

speed of rope at distance x from centre is x/(t+1) (ant starts at x=-50, t=0) speed of ant is x/(t+1)+1 = dx/dt x=c(t+1)+(t+1)log(t+1) so -50=c ant arrives: 50=-50(t+1)+(t+1)log(t+1) let u=t+1 50(u+1)=u log u if u=exp(50), u log u = 50.u which is near enough