On the checkbox click event assign the underlying datasource to have the value alternated and then Rebind or Refresh the datagrid. Need software developed? Offering C# development all over the United States, ERL GLOBAL, Inc is the only call you will have to make. Happiness in intelligent people is the rarest thing I know. -- Ernest Hemingway Most of this sig is for Google, not ego.

SelectedIndexChanged is an event, not a field. So if you're trying to get info about it using reflection, use GetEvents-method (or if you already know the event, GetEvent)instead of GetFields. The need to optimize rises from a bad design. My articles[^]

Hi Remember there is a Difference Between Web and Windows. Vuyiswa Maseko, Sorrow is Better than Laughter, it may Sadden your Face, but It sharpens your Understanding VB.NET/SQL7/2000/2005 http://vuyiswamb.007ihost.com http://Ecadre.007ihost.com vuyiswam@tshwane.gov.za

Ok Solved the problem. Just in case if anyone will run into the same thing. In command line navigate to C:\Windows\Microsoft.NET\Framework\v2.0.50727 and run: aspnet_regiis.exe -i :-)

If anyone else has the same question with regards to XML and XSL, the XslTransform class will do the job. Regards

A couple of posts down you were saying that you serialized an object. Did you read my response or you are just asking around without a clue? A couple of links for you: clickety[^]

First of because the Items property returns an array you should use the XmlArray attribute class: [XmlArray("Items")] public Item[] Items { // get, set } To specify a name for each item use the XmlAttribute class like this: public class Item { [XmlAttribute("name")] public string name; .... Work @ Network integrated solutions | Flickr | A practical use of the MVC pattern

Thank you. That is exactly what I had in mind.

Yeah i can read. But you give very few information about what you really want to do. And my opinion is that is is very important to know what your application should do to provide a good solution (and you asked for the best). So I could just say that you should go ahead and put all records into a DataTable and set it as the DataSource of the grid, call DataBind and wait for your browser rendering the page. Or I could say, no better use an ObjectDataSource or SqlDataSource that provides the data to the grid, because this way you could implement paging, sorting much simpler. But both ways are surely not the BEST ways to do it, but without knowing what you want to accomplish, I can not give you a better answer that the ones you already received. So, sorry I tried to help - won't happen again. -^-^-^-^-^- no risk no funk

Thanks. But ListView control already has a default behaviour for the key strokes. I was just wondering if I can use API SendMessage somehow to emulate this default behaviour.

Are you creating the controls individually and then adding them to the panel by calling panel.Controls.Add? You might want to create your controls and add them to an array or List<Control>. Once all of the controls have been created, add them to the panel by calling panel.Controls.AddRange. This should provide some noticeable speed improvements. Also, be sure to call SuspendLayout before you start adding controls and then ResumeLayout `when you are done. ----------------------------- In just two days, tomorrow will be yesterday.`

Thank you It works, the problem, you notice a bit of blinking withing the control. I guess it's due to myControl changing size.

Sorry, I meant an internal[^] style, not an inline style. /ravi This is your brain on Celcius Home | Music | Articles | Freeware | Trips ravib(at)ravib(dot)com

According to MSDN, "the ItemCheck event occurs when the check state of an item changes or when the CheckBoxes property is set to true". Perhaps the first instance of the event occurs when you set the list view's CheckBoxes property? /ravi This is your brain on Celcius Home | Music | Articles | Freeware | Trips ravib(at)ravib(dot)com

Whenever you add a node, get its full path and store it into node's name. TreeNode tn = this.treeView1.Nodes.Add("AAA"); tn.Name = tn.FullPath; When you want to expand the node having, let's say, "The_wanted_path" you use this: TreeNode [] tn = this.treeView1.Nodes.Find("The_wanted_path", true); if ( tn[0] != null ) { TreeNode Parent = tn[0].Parent; TreeNode FirstParent = Parent; while (Parent != null) { Parent = Parent.Parent; if (Parent != null) FirstParent = Parent; } tn[0].Expand(); if (FirstParent != null) FirstParent.Expand(); } SkyWalker

See this[^] article. /ravi This is your brain on Celcius Home | Music | Articles | Freeware | Trips ravib(at)ravib(dot)com