Regular Expressions

Regex can do the job. But running five+ separate regex operations on a string just to replace a few letters with their unaccented alternatives is overkill. The other option, which is even nastier and less obvious, is to use Unicode normalization: static string RemoveDiacritics(string stIn) { string stFormD = stIn.Normalize(NormalizationForm.FormD); StringBuilder sb = new StringBuilder(); for(int ich = 0; ich < stFormD.Length; ich++) { UnicodeCategory uc = CharUnicodeInfo.GetUnicodeCategory(stFormD\[ich\]); if (uc != UnicodeCategory.NonSpacingMark) { sb.Append(stFormD\[ich\]); } } return sb.ToString().Normalize(NormalizationForm.FormC); } string input = "Príliš žlutoucký kun úpel dábelské ódy."; string result = RemoveDiacritics(input); // "Prilis zlutoucky kun upel dabelske ody." Source[^] "These people looked deep within my soul and assigned me a number based on the order in which I joined." - Homer

Assuming you want to extract three strings: \abc\rvr\sad\dqwdwq \rfdqwdvr\rtgevr\rgwvrr\23rvrv \rffewvr\rfewvr\rvfewrr\rvrwefewv Try: ([\\][A-Za-z0-9]+)+ Regexper[^] "These people looked deep within my soul and assigned me a number based on the order in which I joined." - Homer

Without full samples relating to your posted question, Im really afraid nobody is going to help you. This site shows how my regex matches what you said needs to matched. https://regex101.com/r/cH4Jrg/1 Feel free to experiment with it, if that's easier than trying to describe what should be matched.

Thank you for your help :)

To prevent (Capturing|Groups), you can spec them as (**?:**Non|Capturing|Groups)

Jukec wrote: "[node=\\d+]" No idea what language that is in. But all of the major ones use the same regex semantics for the most part. The square brackets should not be there. Presumably the rest of the code is actually going to 'capture' what is matched. That is a specific term for regex. If so it will look like 'node=16700222031' which means you would need to parse it again to get the number out.

With the sample text-strings you've provided, its impossible for any expression to match by 'internal' domain. If your application has a %variable% to represent the domain being searched, you would have to provide this. Regex simply matches text, it cant determine if that text is "the domain being searched" by your application. I've seen apps that support variables like %domain% in their match-expressions, but they're specific to that application. So if your app supports this, you'd have to look up the variable-name in the documentation, to provide a working example. Short of that, you would need to either hard-code the domains per site being searched, like in the example provided. Or include a larger snippet of the html, but only if the html offered another way to verify 'internal' (highly unlikely). Sorry for the news, but regex wont solve this without 'internal' being defined, whether by a previous match, or by some variable. Some apps even let you customize variables, so maybe thats another option? Sorry, but I know nothing of this "Screaming Frog". Either way, I do wish you luck!

Greetings Dumitru, Im not expert because there seems to be many different flavors, so Im just guessing on this. But it does seem like each "semicolon-comma pair" could be represented by something like ... (\d{1,2}(?:[-:]\d{1,2}[a-z]?)?; )(\d{1,2}:\d{1,2}(?:[a-z]|-\d\d)?, ) So depending on your flavor, since the sample has 4-1/2 pairs, you might have to type a VERY long string like... ^([\w]+\. )(\d{1,2}(?:[-:]\d{1,2}[a-z]?)?; )(\d{1,2}:\d{1,2}(?:[a-z]|-\d\d)?, )(\d{1,2}(?:[-:]\d{1,2}[a-z]?)?; )(\d{1,2}:\d{1,2}(?:[a-z]|-\d\d)?, )(\d{1,2}(?:[-:]\d{1,2}[a-z]?)?; )(\d{1,2}:\d{1,2}(?:[a-z]|-\d\d)?, )(\d{1,2}(?:[-:]\d{1,2}[a-z]?)?; )(\d{1,2}:\d{1,2}(?:[a-z]|-\d\d)?, \d{1,2}(?:[-:]\d{1,2}[a-z]?)?;)$ With a replacement like... \1\2\1\3\4\1\5\6\1\7\8\1\9

If this matches to much, I would need more samples to know what 'should' and 'should not' be matched... ^\d{1,2}[-,A-Z\d]{0,5}$

Needed to turn on the global flag... Thank you!

Ok Richard, thaks a lot ;)

The \s+ in that regex will only match a single string of one or more consecutive whitespace characters, not "all spaces" So your regex would match "This test" or "This      test" but not "This is testing" There are lots of online regex builders and analysers, which I suggest you seek out. Software rusts. Simon Stephenson, ca 1994. So does this signature. me, 2012

The commonest way that people solve this for browsers that don't support this is to think in reverse. In other words, you reverse the string and the regular expression so that all you end up testing is the negative regular expression, rather than a lookbehind. This[^] is a great resource. Advanced TypeScript Programming Projects

Following should do it in perl, java and C#. ^[0-9]{5}$

Jason Hotchkiss 2021 wrote: Is it possible to capture the remained words into a single group? How about /(C\w+=|[[\]])/g ?

Great, that was exactly what i was looking for, thank you so much, Richard! So, to solve the problem from my original posting, that is to match all spaces after the first "v" in the string "I want to solve this problem", this Regex works: /(?<=v.*) /g

Can you explain more what you're trying to do? Also, what tools/language are you using?