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  3. Friday Programming Quiz [modified]

Friday Programming Quiz [modified]

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  • J Jorgen Sigvardsson

    Boostified:

    std::string fn(std::string in)
    {
    std::string out;

    typedef boost::tokenizer<boost::char\_separator<char> > tokenizer;
    tokenizer foo(in, boost::char\_separator<char>(",");
    
    tokenizer::iterator it = foo.begin(), end = foo.end();
    while(it != end)
    {
        out += \*it++;
        if(it != end)
            out += ",";
    }
    return out; 
    

    }

    There's probably a boost function somewhere which allows one to join strings as well, but I didn't bother to look. :)

    -- Not based on the Novel by James Fenimore Cooper

    C Offline
    C Offline
    Chris Losinger
    wrote on last edited by
    #28

    someday i'll try to figure out how to use boost again. the last time i tried, it was a total installation, dependency, compiler configuration nightmare. definitely not the kind of thing i wanted to get into, just to use their regexp classes.

    image processing | blogging

    J 1 Reply Last reply
    0
    • C Chris Losinger

      someday i'll try to figure out how to use boost again. the last time i tried, it was a total installation, dependency, compiler configuration nightmare. definitely not the kind of thing i wanted to get into, just to use their regexp classes.

      image processing | blogging

      J Offline
      J Offline
      Jorgen Sigvardsson
      wrote on last edited by
      #29

      I've had no problems with the releases since 1.30. This has been with VS 2k3 - don't know what'll happen with VC6 or 2k5.

      -- -= Proudly Made on Earth =-

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      • J Jorgen Sigvardsson

        Boostified:

        std::string fn(std::string in)
        {
        std::string out;

        typedef boost::tokenizer<boost::char\_separator<char> > tokenizer;
        tokenizer foo(in, boost::char\_separator<char>(",");
        
        tokenizer::iterator it = foo.begin(), end = foo.end();
        while(it != end)
        {
            out += \*it++;
            if(it != end)
                out += ",";
        }
        return out; 
        

        }

        There's probably a boost function somewhere which allows one to join strings as well, but I didn't bother to look. :)

        -- Not based on the Novel by James Fenimore Cooper

        C Offline
        C Offline
        Chris Losinger
        wrote on last edited by
        #30

        Joergen Sigvardsson wrote:

        *it++; if(it != end)

        ah. nice touch.

        image processing | blogging

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        • P PIEBALDconsult

          Does it count if we write a class to implement a distinct StringCollection with an appropriate ToString() to do most of the work? Resultant function could be something like: string RemoveDuplicates(string csvString) { return ( (new DistinctStringCollection ( csvString.Split ( new char[] { ',' } ) )).ToString() ) ; }

          M Offline
          M Offline
          Marc 0
          wrote on last edited by
          #31

          Yeah piece of cake: return (new [UniqueStringList](http://www.codeproject.com/csharp/uniquestringlist.asp)[[^](http://www.codeproject.com/csharp/uniquestringlist.asp)](csvString.Split(new char[] {','})).ToString("", ",", ""); It is kind of cheating though ;P


          "..Commit yourself to quality from day one..it's better to do nothing at all than to do something badly.." -- Mark McCormick


          || Fold With Us! || Pensieve || VG.Net ||

          P 1 Reply Last reply
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          • A Andre xxxxxxx

            print RemoveDuplicates("a,b,b,c,b,c");

            sub RemoveDuplicates
            {
            foreach (split (/,/,$_[0])) { $_{$_} = $_; }
            join (",",keys %_);
            }

            J Offline
            J Offline
            Jorgen Sigvardsson
            wrote on last edited by
            #32

            Ah.. Perl syntax. Gives me the shiver every time. ;)

            -- Now with chucklelin

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            • M Marc 0

              Yeah piece of cake: return (new [UniqueStringList](http://www.codeproject.com/csharp/uniquestringlist.asp)[[^](http://www.codeproject.com/csharp/uniquestringlist.asp)](csvString.Split(new char[] {','})).ToString("", ",", ""); It is kind of cheating though ;P


              "..Commit yourself to quality from day one..it's better to do nothing at all than to do something badly.." -- Mark McCormick


              || Fold With Us! || Pensieve || VG.Net ||

              P Offline
              P Offline
              PIEBALDconsult
              wrote on last edited by
              #33

              Ah, very good, I'll have to take a deeper look at UniqueStringList. Here's what I just whipped up: public partial class DistinctStringCollection : System.Collections.Specialized.StringCollection { public static DistinctStringCollection FromCSV ( string CSV ) { DistinctStringCollection result = new DistinctStringCollection() ; foreach ( string temp in CSV.Trim ( new char[] { ',' } ).Split ( new char[] { ',' } ) ) { if ( !result.Contains ( temp ) ) { result.Add ( temp ) ; } } return ( result ) ; } public string ToCSV ( ) { System.Text.StringBuilder result = new System.Text.StringBuilder() ; foreach ( string temp in this ) { result.Append ( temp ) ; result.Append ( "," ) ; } return ( result.Remove ( result.Length-1 , 1 ).ToString() ) ; } } And then... public static string RemoveDuplicates ( string Subject ) { return ( DistinctStringCollection.FromCSV ( Subject ).ToCSV() ) ; }

              P 1 Reply Last reply
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              • R Rama Krishna Vavilala

                In a language of your choice (no PE), implement the following:

                string RemoveDuplicates(string csvString) {

                }

                The function should remove all duplicate values form a string containing comma separated values. RemoveDuplicates("a,b,c,a") => "a,b,c" RemoveDuplicates("a,b,c,a,c,b,c") => "a,b,c" RemoveDuplicates("a,b,c") => "a,b,c" RemoveDuplicates("cat,dog,dog") => "cat,dog" The ideal implementation should have just 1 line of code.


                Debugging is twice as hard as writing the code in the first place. Therefore, if you write the code as cleverly as possible, you are, by definition, not smart enough to debug it. -Brian Kernighan

                M Offline
                M Offline
                Michael Dunn
                wrote on last edited by
                #34

                Perl (not tested, may or may not work) ;) print join ( grep { ++$tokens{$_} == 1 } split(/,/), ',' )

                --Mike-- Visual C++ MVP :cool: LINKS~! Ericahist | PimpFish | CP SearchBar v3.0 | C++ Forum FAQ

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                • A Andre xxxxxxx

                  print RemoveDuplicates("a,b,b,c,b,c");

                  sub RemoveDuplicates
                  {
                  foreach (split (/,/,$_[0])) { $_{$_} = $_; }
                  join (",",keys %_);
                  }

                  M Offline
                  M Offline
                  Michael Dunn
                  wrote on last edited by
                  #35

                  Does keys return the keys in the same order as they were inserted? When I did my solution below, I consciously kept the order of the words the same in the output.

                  --Mike-- Visual C++ MVP :cool: LINKS~! Ericahist | PimpFish | CP SearchBar v3.0 | C++ Forum FAQ

                  A 1 Reply Last reply
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                  • R Rama Krishna Vavilala

                    In a language of your choice (no PE), implement the following:

                    string RemoveDuplicates(string csvString) {

                    }

                    The function should remove all duplicate values form a string containing comma separated values. RemoveDuplicates("a,b,c,a") => "a,b,c" RemoveDuplicates("a,b,c,a,c,b,c") => "a,b,c" RemoveDuplicates("a,b,c") => "a,b,c" RemoveDuplicates("cat,dog,dog") => "cat,dog" The ideal implementation should have just 1 line of code.


                    Debugging is twice as hard as writing the code in the first place. Therefore, if you write the code as cleverly as possible, you are, by definition, not smart enough to debug it. -Brian Kernighan

                    E Offline
                    E Offline
                    Eytukan
                    wrote on last edited by
                    #36

                    It's a becoming a bit of addiction to wait for friday programming post... :) hmm but I'm simply watching it now. I'll start posting my version soon :). Very nice Rama :).. in particular everytime I look for Nish to responding with his code :-D...that;s cool. Also at the end you can post your own answer right?


                    :Gong: 歡迎光臨 吐 西批 :Gong:

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                    • M Michael Dunn

                      Does keys return the keys in the same order as they were inserted? When I did my solution below, I consciously kept the order of the words the same in the output.

                      --Mike-- Visual C++ MVP :cool: LINKS~! Ericahist | PimpFish | CP SearchBar v3.0 | C++ Forum FAQ

                      A Offline
                      A Offline
                      Andre xxxxxxx
                      wrote on last edited by
                      #37

                      Michael Dunn wrote:

                      Does keys return the keys in the same order as they were inserted?

                      From the perldoc: "The keys are returned in an apparently random order. The actual random order is subject to change in future versions of perl. Since Perl 5.8.1 the ordering is different even between different runs of Perl for security reasons." But that was not an requirement ;P

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                      • R Rama Krishna Vavilala

                        Well, I should have stated that the values are strings not just single characters.


                        Debugging is twice as hard as writing the code in the first place. Therefore, if you write the code as cleverly as possible, you are, by definition, not smart enough to debug it. -Brian Kernighan

                        E Offline
                        E Offline
                        Eytukan
                        wrote on last edited by
                        #38

                        but your 4th example has already said that. ;)


                        :Gong: 歡迎光臨 吐 西批 :Gong:

                        1 Reply Last reply
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                        • P PIEBALDconsult

                          Ah, very good, I'll have to take a deeper look at UniqueStringList. Here's what I just whipped up: public partial class DistinctStringCollection : System.Collections.Specialized.StringCollection { public static DistinctStringCollection FromCSV ( string CSV ) { DistinctStringCollection result = new DistinctStringCollection() ; foreach ( string temp in CSV.Trim ( new char[] { ',' } ).Split ( new char[] { ',' } ) ) { if ( !result.Contains ( temp ) ) { result.Add ( temp ) ; } } return ( result ) ; } public string ToCSV ( ) { System.Text.StringBuilder result = new System.Text.StringBuilder() ; foreach ( string temp in this ) { result.Append ( temp ) ; result.Append ( "," ) ; } return ( result.Remove ( result.Length-1 , 1 ).ToString() ) ; } } And then... public static string RemoveDuplicates ( string Subject ) { return ( DistinctStringCollection.FromCSV ( Subject ).ToCSV() ) ; }

                          P Offline
                          P Offline
                          PIEBALDconsult
                          wrote on last edited by
                          #39

                          Well at least I had something about which to think over the weekend. I've decided that implementing a DistinctStringCollection (or UniqueStringList) isn't very worthwhile (to me). (Nor is writing a RemoveDuplicates that only works on strings.) Having a method to make a CSV from any IEnumerable is: public static string CSVify ( System.Collections.IEnumerable Subject ) { System.Text.StringBuilder result = new System.Text.StringBuilder() ; foreach ( object temp in Subject ) { if ( temp != null ) { result.Append ( temp.ToString() ) ; result.Append ( "," ) ; } } return ( result.Remove ( result.Length-1 , 1 ).ToString() ) ; } Having methods to remove duplicates from (nearly?) any array or IList is: public static T[] RemoveDuplicates ( T[] Subject ) { T[] result = new T [ Subject.Length ] ; foreach ( T temp in Subject ) { for ( int index = 0 ; index < result.Length ; index++ ) { if ( result [ index ] == null ) { result [ index ] = temp ; break ; } else { if ( temp.Equals ( result [ index ] ) ) { break ; } } } } return ( result ) ; } public static T RemoveDuplicates ( T Subject ) where T : System.Collections.IList , new() { T result = new T() ; foreach ( object temp in Subject ) { if ( !result.Contains ( temp ) ) { result.Add ( temp ) ; } } return ( result ) ; } A string-only RemoveDuplicates can then be written as: public static string RemoveDuplicates ( string Subject ) { return ( CSVify ( RemoveDuplicates ( Subject.Split ( new char[] {

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