How to check if extensions follows up in a list?

[Matjaz xyz]

ummm not incrementing. let me rewrite... (ps: sorry for my bad english) i select a folder. get files from that folder to and arraylist. go with "for" loop through items in that arralist and check extensions (Path.GetExtension). Well... i would go like that. The filenames are incremental... (8 digits type - 00000001 etc) but i really dont have an idea how to put everything in the code. Was trying with this but... One of the ideas was to get extension. if its "tif" then increment int TIFS and if its an JPG, stop counting tifs and add +1 to jpg - then check if the Integer TIFS and JPGS match.. bah... i'm so lost.

Regards, Matjaž

[dan sh]

Do you mean this? If file 1 and 2 are jpg, then 3 and 4 must be tif. That is: 2-2 if 5 is jpg, then 6 must be tif. That is 1-1. In short, number of consecutive jpf files must be equal to number of consecutive tif files. And these must be together. And if the order is not like the one above, then show error.

Happy Holi[^] जय हिंद

[Xmen Real]

If its about Windows Explorer than I think its not possible. The sorting is simple as its string... Why error occur, if you check the extension...or I might not get your question

TVMU^P[[IGIOQHG^JSH`A#@`RFJ\c^JPL>;"[,*/|+&WLEZGc`AFXc!L %^]*IRXD#@GKCQ`R\^SF_WcHbORY87֦ʻ6ϣN8ȤBcRAV\Z^&SU~%CSWQ@#2 W_AD`EPABIKRDFVS)EVLQK)JKSQXUFYK[M`UKs*$GwU#(QDXBER@CBN% Rs0~53%eYrd8mt^7Z6]iTF+(EWfJ9zaK-i’TV.C\y<pŠjxsg-b$f4ia> -------------------------------------------------------- 128 bit encrypted signature, crack if you can

[Matjaz xyz]

Yes. That's right.

Regards, Matjaž

[Matjaz xyz]

It doesnt concern explorer. Basicly, the intention of this application would be to check if JPG files have their duplicate TIF files. If it would be just 1-1, then i could do it... but i cant figure this one out. And what i ment by an error was to put as an output - in which folder the files dont match.

Regards, Matjaž

[dan sh]

AFAIK you just need to set up some loops wisely. Here is a bit of quick and dirty approach I could think of:

List s = new List ();
s.Add("jpg");
s.Add("tif");
s.Add("jpg");
s.Add("tif");
s.Add("jpg");
s.Add("jpg");
s.Add("tif");
s.Add("tif");
s.Add("jpg");
s.Add("tif");

    bool breakFor = false;
    int togetherCount = 1;
    for (int i = 1;i < s.Count -1;i++) {
      
      if (s\[i\] == s\[i - 1\]) {
        togetherCount++;
        continue;
      }
      else {
        int count = 0;
        while (count < togetherCount) {
          if (!(s\[i + 1\] == s\[i + count\])) {
            if (togetherCount > 1) {
              MessageBox.Show("error");
              breakFor = true;
              break;
            }
          }
          count++;
        }
        if (breakFor) {
          break;
        }
        else {
          i = i + togetherCount;
          togetherCount = 1;
        }
      }
    }

It might not be correct but good to start off I guess.

Happy Holi[^] जय हिंद

[Xmen Real]

its simple then... try this

    bool Test(string dirPath)
    {
        string\[\] filePaths = Directory.GetFiles(dirPath, "\*.jpg");
        for (int a = 0; a < filePaths.Length; a++)
        {
            if (!File.Exists(Path.Combine(dirPath, Path.GetFileNameWithoutExtension(filePaths\[a\]) + ".tif")))
                return false;
        }
        return true;
    }

TVMU^P[[IGIOQHG^JSH`A#@`RFJ\c^JPL>;"[,*/|+&WLEZGc`AFXc!L %^]*IRXD#@GKCQ`R\^SF_WcHbORY87֦ʻ6ϣN8ȤBcRAV\Z^&SU~%CSWQ@#2 W_AD`EPABIKRDFVS)EVLQK)JKSQXUFYK[M`UKs*$GwU#(QDXBER@CBN% Rs0~53%eYrd8mt^7Z6]iTF+(EWfJ9zaK-i’TV.C\y<pŠjxsg-b$f4ia> -------------------------------------------------------- 128 bit encrypted signature, crack if you can

[Matjaz xyz]

Umm not duplicates :/ sorry... just... the follow up files. 1.jpg has his own tif, but with a different name. example... 3.tif, because there is another 2.jpg before.

Regards, Matjaž

[dan sh]

In that case, just get the count of files with JPG and count of files with TIF and they must be equal. Dump the code I had posted. Edit: There is a lot of misunderstanding going on in this post. :doh:

Happy Holi[^] जय हिंद

[Matjaz xyz]

I already thought of that - but it is definitly a no-go. Why? Well, maybe there are some files which dont have their tifs, but some tiffs dont have their jpgs - and the count may match.

Regards, Matjaž

[Xmen Real]

aha I got ya now. The thing you want called Stack. Last In Last Out.

TVMU^P[[IGIOQHG^JSH`A#@`RFJ\c^JPL>;"[,*/|+&WLEZGc`AFXc!L %^]*IRXD#@GKCQ`R\^SF_WcHbORY87֦ʻ6ϣN8ȤBcRAV\Z^&SU~%CSWQ@#2 W_AD`EPABIKRDFVS)EVLQK)JKSQXUFYK[M`UKs*$GwU#(QDXBER@CBN% Rs0~53%eYrd8mt^7Z6]iTF+(EWfJ9zaK-i’TV.C\y<pŠjxsg-b$f4ia> -------------------------------------------------------- 128 bit encrypted signature, crack if you can

[Matjaz xyz]

Hmm... it sure looks like it's in the right way. Thanks for taking the time. I'll try to implent something similar and report what happend. Thank you

Regards, Matjaž

[Matjaz xyz]

Somehow it seems i didnt implent this correctly... or it doesnt work right (like you said, it could and could not work)... aah :/

if (fbd1.ShowDialog() != DialogResult.Cancel)
{
if (checkBox1.Checked == true)
DIRI.Items.AddRange(Directory.GetDirectories(fbd1.SelectedPath, "*.*", SearchOption.AllDirectories));
else
DIRI.Items.AddRange(Directory.GetDirectories(fbd1.SelectedPath, "*.*", SearchOption.TopDirectoryOnly));

            for (int i = 0; i < DIRI.Items.Count; i++)
            {
                ArrayList DATOTEKE = new ArrayList();
                DATOTEKE.AddRange(Directory.GetFiles(DIRI.Items\[i\].ToString().ToLower()));

                ArrayList KONCNICE = new ArrayList();

                for (int bo = 0; bo < DATOTEKE.Count; bo++)
                {
                    KONCNICE.Add(Path.GetExtension(DATOTEKE\[i\].ToString()));
                }



                bool breakFor = false;
                int togetherCount = 1;
                for (int j = 1; j < KONCNICE.Count - 1; i++)
                {
                    if (KONCNICE\[j\] == KONCNICE\[j - 1\])
                    {
                        togetherCount++;
                        continue;
                    }
                    else
                    {
                        int count = 0;
                        while (count < togetherCount)
                        {
                            if (!(KONCNICE\[j + 1\] == KONCNICE\[j + count\]))
                            {
                                if (togetherCount > 1)
                                {
                                    //if (listBox1.FindStringExact(DIRI.Items\[i\].ToString()) > 0)
                                        listBox1.Items.Add(DIRI.Items\[i\].ToString());
                                    breakFor = true;
                                    break;
                                }
                            }
                            count++;
                        }
                        if (breakFor)
                        {
                            break;
                        }
                        else
                        {
                            j = j + togetherCount;

[dan sh]

I would say, debug the code and find where you are wrong. Get hold of the logic and you will be done.

Matjaž Grahek wrote:

if (!(KONCNICE[j + 1] == KONCNICE[j + count]))

One thing I can figure out is you need to remoe this + 1. I have not debugged the code just read it so I may go wrong.

Happy Holi[^] जय हिंद

[Luc Pattyn]

In today's pseudo-language that would be:

filelist=getAllFilenames()
filelist.Sort
diff=0
foreach(file in filelist) {
if (jpg) diff++
else diff--
if (diff<-1 or diff>1) error
}

Two remarks: 1. to get a natural sort order for the file names, same as Windows Explorer does, you would need to use Explorer's code, i.e. use P/Invoke and the prototype:

	\[DllImport("shlwapi.dll", CharSet=CharSet.Unicode, ExactSpelling=true)\]
	private static extern int StrCmpLogicalW(string s1, string s2);

Of course if the name part is just a number, you could use int.Parse and sort based on the outcome. 2. I cannot imagine where and how your requirement could ever have a useful application. :)

Luc Pattyn [Forum Guidelines] [My Articles]

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[Luc Pattyn]

Matjaž Grahek wrote:

1.jpg has his own tif, but with a different name

that is plain stupid. Extensions exist so files that belong together can share the name part of a filename. Use it to your advantage rather than strugging with some code to fix the mistake. :)

Luc Pattyn [Forum Guidelines] [My Articles]

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