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  4. How to check if extensions follows up in a list?

How to check if extensions follows up in a list?

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  • D dan sh

    Do you mean this? If file 1 and 2 are jpg, then 3 and 4 must be tif. That is: 2-2 if 5 is jpg, then 6 must be tif. That is 1-1. In short, number of consecutive jpf files must be equal to number of consecutive tif files. And these must be together. And if the order is not like the one above, then show error.

    Happy Holi[^] जय हिंद

    M Offline
    M Offline
    Matjaz xyz
    wrote on last edited by
    #7

    Yes. That's right.

    Regards, Matjaž

    D L 2 Replies Last reply
    0
    • X Xmen Real

      If its about Windows Explorer than I think its not possible. The sorting is simple as its string... Why error occur, if you check the extension...or I might not get your question

      TVMU^P[[IGIOQHG^JSH`A#@`RFJ\c^JPL>;"[,*/|+&WLEZGc`AFXc!L %^]*IRXD#@GKCQ`R\^SF_WcHbORY87֦ʻ6ϣN8ȤBcRAV\Z^&SU~%CSWQ@#2 W_AD`EPABIKRDFVS)EVLQK)JKSQXUFYK[M`UKs*$GwU#(QDXBER@CBN% Rs0~53%eYrd8mt^7Z6]iTF+(EWfJ9zaK-i’TV.C\y<pŠjxsg-b$f4ia> -------------------------------------------------------- 128 bit encrypted signature, crack if you can

      M Offline
      M Offline
      Matjaz xyz
      wrote on last edited by
      #8

      It doesnt concern explorer. Basicly, the intention of this application would be to check if JPG files have their duplicate TIF files. If it would be just 1-1, then i could do it... but i cant figure this one out. And what i ment by an error was to put as an output - in which folder the files dont match.

      Regards, Matjaž

      X 1 Reply Last reply
      0
      • M Matjaz xyz

        Yes. That's right.

        Regards, Matjaž

        D Offline
        D Offline
        dan sh
        wrote on last edited by
        #9

        AFAIK you just need to set up some loops wisely. Here is a bit of quick and dirty approach I could think of:

        List s = new List ();
        s.Add("jpg");
        s.Add("tif");
        s.Add("jpg");
        s.Add("tif");
        s.Add("jpg");
        s.Add("jpg");
        s.Add("tif");
        s.Add("tif");
        s.Add("jpg");
        s.Add("tif");

            bool breakFor = false;
            int togetherCount = 1;
            for (int i = 1;i < s.Count -1;i++) {
              
              if (s\[i\] == s\[i - 1\]) {
                togetherCount++;
                continue;
              }
              else {
                int count = 0;
                while (count < togetherCount) {
                  if (!(s\[i + 1\] == s\[i + count\])) {
                    if (togetherCount > 1) {
                      MessageBox.Show("error");
                      breakFor = true;
                      break;
                    }
                  }
                  count++;
                }
                if (breakFor) {
                  break;
                }
                else {
                  i = i + togetherCount;
                  togetherCount = 1;
                }
              }
            }
        

        It might not be correct but good to start off I guess.

        Happy Holi[^] जय हिंद

        M 2 Replies Last reply
        0
        • M Matjaz xyz

          It doesnt concern explorer. Basicly, the intention of this application would be to check if JPG files have their duplicate TIF files. If it would be just 1-1, then i could do it... but i cant figure this one out. And what i ment by an error was to put as an output - in which folder the files dont match.

          Regards, Matjaž

          X Offline
          X Offline
          Xmen Real
          wrote on last edited by
          #10

          its simple then... try this

              bool Test(string dirPath)
              {
                  string\[\] filePaths = Directory.GetFiles(dirPath, "\*.jpg");
                  for (int a = 0; a < filePaths.Length; a++)
                  {
                      if (!File.Exists(Path.Combine(dirPath, Path.GetFileNameWithoutExtension(filePaths\[a\]) + ".tif")))
                          return false;
                  }
                  return true;
              }
          

          TVMU^P[[IGIOQHG^JSH`A#@`RFJ\c^JPL>;"[,*/|+&WLEZGc`AFXc!L %^]*IRXD#@GKCQ`R\^SF_WcHbORY87֦ʻ6ϣN8ȤBcRAV\Z^&SU~%CSWQ@#2 W_AD`EPABIKRDFVS)EVLQK)JKSQXUFYK[M`UKs*$GwU#(QDXBER@CBN% Rs0~53%eYrd8mt^7Z6]iTF+(EWfJ9zaK-i’TV.C\y<pŠjxsg-b$f4ia> -------------------------------------------------------- 128 bit encrypted signature, crack if you can

          M 1 Reply Last reply
          0
          • X Xmen Real

            its simple then... try this

                bool Test(string dirPath)
                {
                    string\[\] filePaths = Directory.GetFiles(dirPath, "\*.jpg");
                    for (int a = 0; a < filePaths.Length; a++)
                    {
                        if (!File.Exists(Path.Combine(dirPath, Path.GetFileNameWithoutExtension(filePaths\[a\]) + ".tif")))
                            return false;
                    }
                    return true;
                }
            

            TVMU^P[[IGIOQHG^JSH`A#@`RFJ\c^JPL>;"[,*/|+&WLEZGc`AFXc!L %^]*IRXD#@GKCQ`R\^SF_WcHbORY87֦ʻ6ϣN8ȤBcRAV\Z^&SU~%CSWQ@#2 W_AD`EPABIKRDFVS)EVLQK)JKSQXUFYK[M`UKs*$GwU#(QDXBER@CBN% Rs0~53%eYrd8mt^7Z6]iTF+(EWfJ9zaK-i’TV.C\y<pŠjxsg-b$f4ia> -------------------------------------------------------- 128 bit encrypted signature, crack if you can

            M Offline
            M Offline
            Matjaz xyz
            wrote on last edited by
            #11

            Umm not duplicates :/ sorry... just... the follow up files. 1.jpg has his own tif, but with a different name. example... 3.tif, because there is another 2.jpg before.

            Regards, Matjaž

            D X L 3 Replies Last reply
            0
            • M Matjaz xyz

              Umm not duplicates :/ sorry... just... the follow up files. 1.jpg has his own tif, but with a different name. example... 3.tif, because there is another 2.jpg before.

              Regards, Matjaž

              D Offline
              D Offline
              dan sh
              wrote on last edited by
              #12

              In that case, just get the count of files with JPG and count of files with TIF and they must be equal. Dump the code I had posted. Edit: There is a lot of misunderstanding going on in this post. :doh:

              Happy Holi[^] जय हिंद

              M 1 Reply Last reply
              0
              • D dan sh

                In that case, just get the count of files with JPG and count of files with TIF and they must be equal. Dump the code I had posted. Edit: There is a lot of misunderstanding going on in this post. :doh:

                Happy Holi[^] जय हिंद

                M Offline
                M Offline
                Matjaz xyz
                wrote on last edited by
                #13

                I already thought of that - but it is definitly a no-go. Why? Well, maybe there are some files which dont have their tifs, but some tiffs dont have their jpgs - and the count may match.

                Regards, Matjaž

                1 Reply Last reply
                0
                • M Matjaz xyz

                  Umm not duplicates :/ sorry... just... the follow up files. 1.jpg has his own tif, but with a different name. example... 3.tif, because there is another 2.jpg before.

                  Regards, Matjaž

                  X Offline
                  X Offline
                  Xmen Real
                  wrote on last edited by
                  #14

                  aha I got ya now. The thing you want called Stack. Last In Last Out.

                  TVMU^P[[IGIOQHG^JSH`A#@`RFJ\c^JPL>;"[,*/|+&WLEZGc`AFXc!L %^]*IRXD#@GKCQ`R\^SF_WcHbORY87֦ʻ6ϣN8ȤBcRAV\Z^&SU~%CSWQ@#2 W_AD`EPABIKRDFVS)EVLQK)JKSQXUFYK[M`UKs*$GwU#(QDXBER@CBN% Rs0~53%eYrd8mt^7Z6]iTF+(EWfJ9zaK-i’TV.C\y<pŠjxsg-b$f4ia> -------------------------------------------------------- 128 bit encrypted signature, crack if you can

                  1 Reply Last reply
                  0
                  • D dan sh

                    AFAIK you just need to set up some loops wisely. Here is a bit of quick and dirty approach I could think of:

                    List s = new List ();
                    s.Add("jpg");
                    s.Add("tif");
                    s.Add("jpg");
                    s.Add("tif");
                    s.Add("jpg");
                    s.Add("jpg");
                    s.Add("tif");
                    s.Add("tif");
                    s.Add("jpg");
                    s.Add("tif");

                        bool breakFor = false;
                        int togetherCount = 1;
                        for (int i = 1;i < s.Count -1;i++) {
                          
                          if (s\[i\] == s\[i - 1\]) {
                            togetherCount++;
                            continue;
                          }
                          else {
                            int count = 0;
                            while (count < togetherCount) {
                              if (!(s\[i + 1\] == s\[i + count\])) {
                                if (togetherCount > 1) {
                                  MessageBox.Show("error");
                                  breakFor = true;
                                  break;
                                }
                              }
                              count++;
                            }
                            if (breakFor) {
                              break;
                            }
                            else {
                              i = i + togetherCount;
                              togetherCount = 1;
                            }
                          }
                        }
                    

                    It might not be correct but good to start off I guess.

                    Happy Holi[^] जय हिंद

                    M Offline
                    M Offline
                    Matjaz xyz
                    wrote on last edited by
                    #15

                    Hmm... it sure looks like it's in the right way. Thanks for taking the time. I'll try to implent something similar and report what happend. Thank you

                    Regards, Matjaž

                    1 Reply Last reply
                    0
                    • D dan sh

                      AFAIK you just need to set up some loops wisely. Here is a bit of quick and dirty approach I could think of:

                      List s = new List ();
                      s.Add("jpg");
                      s.Add("tif");
                      s.Add("jpg");
                      s.Add("tif");
                      s.Add("jpg");
                      s.Add("jpg");
                      s.Add("tif");
                      s.Add("tif");
                      s.Add("jpg");
                      s.Add("tif");

                          bool breakFor = false;
                          int togetherCount = 1;
                          for (int i = 1;i < s.Count -1;i++) {
                            
                            if (s\[i\] == s\[i - 1\]) {
                              togetherCount++;
                              continue;
                            }
                            else {
                              int count = 0;
                              while (count < togetherCount) {
                                if (!(s\[i + 1\] == s\[i + count\])) {
                                  if (togetherCount > 1) {
                                    MessageBox.Show("error");
                                    breakFor = true;
                                    break;
                                  }
                                }
                                count++;
                              }
                              if (breakFor) {
                                break;
                              }
                              else {
                                i = i + togetherCount;
                                togetherCount = 1;
                              }
                            }
                          }
                      

                      It might not be correct but good to start off I guess.

                      Happy Holi[^] जय हिंद

                      M Offline
                      M Offline
                      Matjaz xyz
                      wrote on last edited by
                      #16

                      Somehow it seems i didnt implent this correctly... or it doesnt work right (like you said, it could and could not work)... aah :/

                      if (fbd1.ShowDialog() != DialogResult.Cancel)
                      {
                      if (checkBox1.Checked == true)
                      DIRI.Items.AddRange(Directory.GetDirectories(fbd1.SelectedPath, "*.*", SearchOption.AllDirectories));
                      else
                      DIRI.Items.AddRange(Directory.GetDirectories(fbd1.SelectedPath, "*.*", SearchOption.TopDirectoryOnly));

                                  for (int i = 0; i < DIRI.Items.Count; i++)
                                  {
                                      ArrayList DATOTEKE = new ArrayList();
                                      DATOTEKE.AddRange(Directory.GetFiles(DIRI.Items\[i\].ToString().ToLower()));
                      
                                      ArrayList KONCNICE = new ArrayList();
                      
                                      for (int bo = 0; bo < DATOTEKE.Count; bo++)
                                      {
                                          KONCNICE.Add(Path.GetExtension(DATOTEKE\[i\].ToString()));
                                      }
                      
                      
                      
                                      bool breakFor = false;
                                      int togetherCount = 1;
                                      for (int j = 1; j < KONCNICE.Count - 1; i++)
                                      {
                                          if (KONCNICE\[j\] == KONCNICE\[j - 1\])
                                          {
                                              togetherCount++;
                                              continue;
                                          }
                                          else
                                          {
                                              int count = 0;
                                              while (count < togetherCount)
                                              {
                                                  if (!(KONCNICE\[j + 1\] == KONCNICE\[j + count\]))
                                                  {
                                                      if (togetherCount > 1)
                                                      {
                                                          //if (listBox1.FindStringExact(DIRI.Items\[i\].ToString()) > 0)
                                                              listBox1.Items.Add(DIRI.Items\[i\].ToString());
                                                          breakFor = true;
                                                          break;
                                                      }
                                                  }
                                                  count++;
                                              }
                                              if (breakFor)
                                              {
                                                  break;
                                              }
                                              else
                                              {
                                                  j = j + togetherCount;
                      
                      D 1 Reply Last reply
                      0
                      • M Matjaz xyz

                        Somehow it seems i didnt implent this correctly... or it doesnt work right (like you said, it could and could not work)... aah :/

                        if (fbd1.ShowDialog() != DialogResult.Cancel)
                        {
                        if (checkBox1.Checked == true)
                        DIRI.Items.AddRange(Directory.GetDirectories(fbd1.SelectedPath, "*.*", SearchOption.AllDirectories));
                        else
                        DIRI.Items.AddRange(Directory.GetDirectories(fbd1.SelectedPath, "*.*", SearchOption.TopDirectoryOnly));

                                    for (int i = 0; i < DIRI.Items.Count; i++)
                                    {
                                        ArrayList DATOTEKE = new ArrayList();
                                        DATOTEKE.AddRange(Directory.GetFiles(DIRI.Items\[i\].ToString().ToLower()));
                        
                                        ArrayList KONCNICE = new ArrayList();
                        
                                        for (int bo = 0; bo < DATOTEKE.Count; bo++)
                                        {
                                            KONCNICE.Add(Path.GetExtension(DATOTEKE\[i\].ToString()));
                                        }
                        
                        
                        
                                        bool breakFor = false;
                                        int togetherCount = 1;
                                        for (int j = 1; j < KONCNICE.Count - 1; i++)
                                        {
                                            if (KONCNICE\[j\] == KONCNICE\[j - 1\])
                                            {
                                                togetherCount++;
                                                continue;
                                            }
                                            else
                                            {
                                                int count = 0;
                                                while (count < togetherCount)
                                                {
                                                    if (!(KONCNICE\[j + 1\] == KONCNICE\[j + count\]))
                                                    {
                                                        if (togetherCount > 1)
                                                        {
                                                            //if (listBox1.FindStringExact(DIRI.Items\[i\].ToString()) > 0)
                                                                listBox1.Items.Add(DIRI.Items\[i\].ToString());
                                                            breakFor = true;
                                                            break;
                                                        }
                                                    }
                                                    count++;
                                                }
                                                if (breakFor)
                                                {
                                                    break;
                                                }
                                                else
                                                {
                                                    j = j + togetherCount;
                        
                        D Offline
                        D Offline
                        dan sh
                        wrote on last edited by
                        #17

                        I would say, debug the code and find where you are wrong. Get hold of the logic and you will be done.

                        Matjaž Grahek wrote:

                        if (!(KONCNICE[j + 1] == KONCNICE[j + count]))

                        One thing I can figure out is you need to remoe this + 1. I have not debugged the code just read it so I may go wrong.

                        Happy Holi[^] जय हिंद

                        1 Reply Last reply
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                        • M Matjaz xyz

                          Yes. That's right.

                          Regards, Matjaž

                          L Offline
                          L Offline
                          Luc Pattyn
                          wrote on last edited by
                          #18

                          In today's pseudo-language that would be:

                          filelist=getAllFilenames()
                          filelist.Sort
                          diff=0
                          foreach(file in filelist) {
                          if (jpg) diff++
                          else diff--
                          if (diff<-1 or diff>1) error
                          }

                          Two remarks: 1. to get a natural sort order for the file names, same as Windows Explorer does, you would need to use Explorer's code, i.e. use P/Invoke and the prototype:

                          	\[DllImport("shlwapi.dll", CharSet=CharSet.Unicode, ExactSpelling=true)\]
                          	private static extern int StrCmpLogicalW(string s1, string s2);
                          

                          Of course if the name part is just a number, you could use int.Parse and sort based on the outcome. 2. I cannot imagine where and how your requirement could ever have a useful application. :)

                          Luc Pattyn [Forum Guidelines] [My Articles]


                          - before you ask a question here, search CodeProject, then Google - the quality and detail of your question reflects on the effectiveness of the help you are likely to get - use the code block button (PRE tags) to preserve formatting when showing multi-line code snippets


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                          • M Matjaz xyz

                            Umm not duplicates :/ sorry... just... the follow up files. 1.jpg has his own tif, but with a different name. example... 3.tif, because there is another 2.jpg before.

                            Regards, Matjaž

                            L Offline
                            L Offline
                            Luc Pattyn
                            wrote on last edited by
                            #19

                            Matjaž Grahek wrote:

                            1.jpg has his own tif, but with a different name

                            that is plain stupid. Extensions exist so files that belong together can share the name part of a filename. Use it to your advantage rather than strugging with some code to fix the mistake. :)

                            Luc Pattyn [Forum Guidelines] [My Articles]


                            - before you ask a question here, search CodeProject, then Google - the quality and detail of your question reflects on the effectiveness of the help you are likely to get - use the code block button (PRE tags) to preserve formatting when showing multi-line code snippets


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