How to check if extensions follows up in a list?

[Xmen Real]

If its about Windows Explorer than I think its not possible. The sorting is simple as its string... Why error occur, if you check the extension...or I might not get your question

TVMU^P[[IGIOQHG^JSH`A#@`RFJ\c^JPL>;"[,*/|+&WLEZGc`AFXc!L %^]*IRXD#@GKCQ`R\^SF_WcHbORY87֦ʻ6ϣN8ȤBcRAV\Z^&SU~%CSWQ@#2 W_AD`EPABIKRDFVS)EVLQK)JKSQXUFYK[M`UKs*$GwU#(QDXBER@CBN% Rs0~53%eYrd8mt^7Z6]iTF+(EWfJ9zaK-i’TV.C\y<pŠjxsg-b$f4ia> -------------------------------------------------------- 128 bit encrypted signature, crack if you can

[Matjaz xyz]

Yes. That's right.

Regards, Matjaž

[Matjaz xyz]

It doesnt concern explorer. Basicly, the intention of this application would be to check if JPG files have their duplicate TIF files. If it would be just 1-1, then i could do it... but i cant figure this one out. And what i ment by an error was to put as an output - in which folder the files dont match.

Regards, Matjaž

[dan sh]

AFAIK you just need to set up some loops wisely. Here is a bit of quick and dirty approach I could think of:

List s = new List ();
s.Add("jpg");
s.Add("tif");
s.Add("jpg");
s.Add("tif");
s.Add("jpg");
s.Add("jpg");
s.Add("tif");
s.Add("tif");
s.Add("jpg");
s.Add("tif");

    bool breakFor = false;
    int togetherCount = 1;
    for (int i = 1;i < s.Count -1;i++) {
      
      if (s\[i\] == s\[i - 1\]) {
        togetherCount++;
        continue;
      }
      else {
        int count = 0;
        while (count < togetherCount) {
          if (!(s\[i + 1\] == s\[i + count\])) {
            if (togetherCount > 1) {
              MessageBox.Show("error");
              breakFor = true;
              break;
            }
          }
          count++;
        }
        if (breakFor) {
          break;
        }
        else {
          i = i + togetherCount;
          togetherCount = 1;
        }
      }
    }

It might not be correct but good to start off I guess.

Happy Holi[^] जय हिंद

[Xmen Real]

its simple then... try this

    bool Test(string dirPath)
    {
        string\[\] filePaths = Directory.GetFiles(dirPath, "\*.jpg");
        for (int a = 0; a < filePaths.Length; a++)
        {
            if (!File.Exists(Path.Combine(dirPath, Path.GetFileNameWithoutExtension(filePaths\[a\]) + ".tif")))
                return false;
        }
        return true;
    }

TVMU^P[[IGIOQHG^JSH`A#@`RFJ\c^JPL>;"[,*/|+&WLEZGc`AFXc!L %^]*IRXD#@GKCQ`R\^SF_WcHbORY87֦ʻ6ϣN8ȤBcRAV\Z^&SU~%CSWQ@#2 W_AD`EPABIKRDFVS)EVLQK)JKSQXUFYK[M`UKs*$GwU#(QDXBER@CBN% Rs0~53%eYrd8mt^7Z6]iTF+(EWfJ9zaK-i’TV.C\y<pŠjxsg-b$f4ia> -------------------------------------------------------- 128 bit encrypted signature, crack if you can

[Matjaz xyz]

Umm not duplicates :/ sorry... just... the follow up files. 1.jpg has his own tif, but with a different name. example... 3.tif, because there is another 2.jpg before.

Regards, Matjaž

[dan sh]

In that case, just get the count of files with JPG and count of files with TIF and they must be equal. Dump the code I had posted. Edit: There is a lot of misunderstanding going on in this post. :doh:

Happy Holi[^] जय हिंद

[Matjaz xyz]

I already thought of that - but it is definitly a no-go. Why? Well, maybe there are some files which dont have their tifs, but some tiffs dont have their jpgs - and the count may match.

Regards, Matjaž

[Xmen Real]

aha I got ya now. The thing you want called Stack. Last In Last Out.

TVMU^P[[IGIOQHG^JSH`A#@`RFJ\c^JPL>;"[,*/|+&WLEZGc`AFXc!L %^]*IRXD#@GKCQ`R\^SF_WcHbORY87֦ʻ6ϣN8ȤBcRAV\Z^&SU~%CSWQ@#2 W_AD`EPABIKRDFVS)EVLQK)JKSQXUFYK[M`UKs*$GwU#(QDXBER@CBN% Rs0~53%eYrd8mt^7Z6]iTF+(EWfJ9zaK-i’TV.C\y<pŠjxsg-b$f4ia> -------------------------------------------------------- 128 bit encrypted signature, crack if you can

[Matjaz xyz]

Hmm... it sure looks like it's in the right way. Thanks for taking the time. I'll try to implent something similar and report what happend. Thank you

Regards, Matjaž

[Matjaz xyz]

Somehow it seems i didnt implent this correctly... or it doesnt work right (like you said, it could and could not work)... aah :/

if (fbd1.ShowDialog() != DialogResult.Cancel)
{
if (checkBox1.Checked == true)
DIRI.Items.AddRange(Directory.GetDirectories(fbd1.SelectedPath, "*.*", SearchOption.AllDirectories));
else
DIRI.Items.AddRange(Directory.GetDirectories(fbd1.SelectedPath, "*.*", SearchOption.TopDirectoryOnly));

            for (int i = 0; i < DIRI.Items.Count; i++)
            {
                ArrayList DATOTEKE = new ArrayList();
                DATOTEKE.AddRange(Directory.GetFiles(DIRI.Items\[i\].ToString().ToLower()));

                ArrayList KONCNICE = new ArrayList();

                for (int bo = 0; bo < DATOTEKE.Count; bo++)
                {
                    KONCNICE.Add(Path.GetExtension(DATOTEKE\[i\].ToString()));
                }



                bool breakFor = false;
                int togetherCount = 1;
                for (int j = 1; j < KONCNICE.Count - 1; i++)
                {
                    if (KONCNICE\[j\] == KONCNICE\[j - 1\])
                    {
                        togetherCount++;
                        continue;
                    }
                    else
                    {
                        int count = 0;
                        while (count < togetherCount)
                        {
                            if (!(KONCNICE\[j + 1\] == KONCNICE\[j + count\]))
                            {
                                if (togetherCount > 1)
                                {
                                    //if (listBox1.FindStringExact(DIRI.Items\[i\].ToString()) > 0)
                                        listBox1.Items.Add(DIRI.Items\[i\].ToString());
                                    breakFor = true;
                                    break;
                                }
                            }
                            count++;
                        }
                        if (breakFor)
                        {
                            break;
                        }
                        else
                        {
                            j = j + togetherCount;

[dan sh]

I would say, debug the code and find where you are wrong. Get hold of the logic and you will be done.

Matjaž Grahek wrote:

if (!(KONCNICE[j + 1] == KONCNICE[j + count]))

One thing I can figure out is you need to remoe this + 1. I have not debugged the code just read it so I may go wrong.

Happy Holi[^] जय हिंद

[Luc Pattyn]

In today's pseudo-language that would be:

filelist=getAllFilenames()
filelist.Sort
diff=0
foreach(file in filelist) {
if (jpg) diff++
else diff--
if (diff<-1 or diff>1) error
}

Two remarks: 1. to get a natural sort order for the file names, same as Windows Explorer does, you would need to use Explorer's code, i.e. use P/Invoke and the prototype:

	\[DllImport("shlwapi.dll", CharSet=CharSet.Unicode, ExactSpelling=true)\]
	private static extern int StrCmpLogicalW(string s1, string s2);

Of course if the name part is just a number, you could use int.Parse and sort based on the outcome. 2. I cannot imagine where and how your requirement could ever have a useful application. :)

Luc Pattyn [Forum Guidelines] [My Articles]

---

- before you ask a question here, search CodeProject, then Google - the quality and detail of your question reflects on the effectiveness of the help you are likely to get - use the code block button (PRE tags) to preserve formatting when showing multi-line code snippets

---

[Luc Pattyn]

Matjaž Grahek wrote:

1.jpg has his own tif, but with a different name

that is plain stupid. Extensions exist so files that belong together can share the name part of a filename. Use it to your advantage rather than strugging with some code to fix the mistake. :)

Luc Pattyn [Forum Guidelines] [My Articles]

---

- before you ask a question here, search CodeProject, then Google - the quality and detail of your question reflects on the effectiveness of the help you are likely to get - use the code block button (PRE tags) to preserve formatting when showing multi-line code snippets

---