Frogger Math [modified]
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Right on my man! It's amazing how many people don't get it. This was a question that I dug out of an old college math book. (Your hired!) :)
The mind is like a parachute. It doesn’t work unless it’s open.
Richard Blythe wrote:
Your hired
Hey spelling cop! It's "you're hired". ;) hehehe Don't go writing up a grammar checker, okay? hehe
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Frogger is an infinate number of jumps from the wall, because, given enough decimal places, any positive finate number divided by 2 will always produce a value greater that zero.
Steve Jowett ------------------------- Real Programmers don't need comments -- the code is obvious.
all he has to do is get close and then lean over a bit. or, get a bit closer and let one of the electrons in one of the cells in his skin bump into one of the electrons in the silica in the wall. you can't get infinitely-close-but-not-touching in the real world.
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Richard Blythe wrote:
Your hired
Hey spelling cop! It's "you're hired". ;) hehehe Don't go writing up a grammar checker, okay? hehe
I'm hit! :laugh:
The mind is like a parachute. It doesn’t work unless it’s open.
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Well thats a long tongue :laugh:
Even the fly would stick around for one that long :laugh: especially if it was a female :-O
Steve _________________ I C(++) therefore I am
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Right on my man! It's amazing how many people don't get it. This was a question that I dug out of an old college math book. (Your hired!) :)
The mind is like a parachute. It doesn’t work unless it’s open.
Richard Blythe wrote:
I dug out of an old college math book.
old... no foolin. like 490 BC[^] old.
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modified on Tuesday, July 20, 2010 1:10 PM
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Richard Blythe wrote:
Question: How many jumps will it take for Frogger to reach the wall?
He'll never get there.
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Correct. After his first jump, the fly is out of there and the Frogger is no longer interested in nearing the wall. :)
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Richard Blythe wrote:
I dug out of an old college math book.
old... no foolin. like 490 BC[^] old.
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modified on Tuesday, July 20, 2010 1:10 PM
The bearing of a child takes nine months, no matter how many women are assigned.
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The bearing of a child takes nine months, no matter how many women are assigned.
that's where my link was supposed to go... yeah :-O
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Frogger sits twenty feet from a wall. He has just eaten two (slow roasted) flies. ;P Now he sees another fly at the base of the wall! On his first jump, he has the energy to jump half the distance to the wall. (ten feet) :doh: All subsequent jumping power is also cut in half. :(( Question: How many jumps will it take for Frogger to reach the wall? (This is a DISTANCE question, not a "eat the fly" question)
The mind is like a parachute. It doesn’t work unless it’s open.
modified on Tuesday, July 20, 2010 11:33 AM
Lucky frog that made only one jump and then it started walking...
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Frogger sits twenty feet from a wall. He has just eaten two (slow roasted) flies. ;P Now he sees another fly at the base of the wall! On his first jump, he has the energy to jump half the distance to the wall. (ten feet) :doh: All subsequent jumping power is also cut in half. :(( Question: How many jumps will it take for Frogger to reach the wall? (This is a DISTANCE question, not a "eat the fly" question)
The mind is like a parachute. It doesn’t work unless it’s open.
modified on Tuesday, July 20, 2010 11:33 AM
3 hops. Because the first jump is 10 feet and the last two are 5. You didn't say it was halved each time. ;-) If you did though, you're talking about an age old math teaser. I believe it was an arrow travels half the remaining distance in a second. How long will it take to arrive at its target? Answer: Never. It will always be some faction of distance away from the target.
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Frogger sits twenty feet from a wall. He has just eaten two (slow roasted) flies. ;P Now he sees another fly at the base of the wall! On his first jump, he has the energy to jump half the distance to the wall. (ten feet) :doh: All subsequent jumping power is also cut in half. :(( Question: How many jumps will it take for Frogger to reach the wall? (This is a DISTANCE question, not a "eat the fly" question)
The mind is like a parachute. It doesn’t work unless it’s open.
modified on Tuesday, July 20, 2010 11:33 AM
Richard Blythe wrote:
How many jumps will it take for Frogger to reach the wall?
How many licks does it take to get to the center of a tootsie pop (if each lick removes half the remaining tootsie pop)?
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You've never played Frogger?!! I thought everyone grew up playing Frogger. No wonder your warped. http://en.wikipedia.org/wiki/Frogger[^]
The mind is like a parachute. It doesn’t work unless it’s open.
Richard Blythe wrote:
You've never played Frogger?!! I thought everyone grew up playing Frogger. No wonder your warped.
I knew there should be some reason, but I thought it’s because of the incident with the cat and the TNT stick when I was a child. :sigh:
The narrow specialist in the broad sense of the word is a complete idiot in the narrow sense of the word. Advertise here – minimum three posts per day are guaranteed.
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Frogger sits twenty feet from a wall. He has just eaten two (slow roasted) flies. ;P Now he sees another fly at the base of the wall! On his first jump, he has the energy to jump half the distance to the wall. (ten feet) :doh: All subsequent jumping power is also cut in half. :(( Question: How many jumps will it take for Frogger to reach the wall? (This is a DISTANCE question, not a "eat the fly" question)
The mind is like a parachute. It doesn’t work unless it’s open.
modified on Tuesday, July 20, 2010 11:33 AM
Richard Blythe wrote:
How many jumps will it take for Frogger to reach the wall
Infinite. He is not going to get to the fly.
The funniest thing about this particular signature is that by the time you realise it doesn't say anything it's too late to stop reading it. My latest tip/trick - Silverlight *.XCP files
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Frogger sits twenty feet from a wall. He has just eaten two (slow roasted) flies. ;P Now he sees another fly at the base of the wall! On his first jump, he has the energy to jump half the distance to the wall. (ten feet) :doh: All subsequent jumping power is also cut in half. :(( Question: How many jumps will it take for Frogger to reach the wall? (This is a DISTANCE question, not a "eat the fly" question)
The mind is like a parachute. It doesn’t work unless it’s open.
modified on Tuesday, July 20, 2010 11:33 AM
Frogger lives in a discrete world, not a contiguous one, so the answer to the question depends on the minimal distance resolution and whether the jump algorithm rounds or truncates.
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3 hops. Because the first jump is 10 feet and the last two are 5. You didn't say it was halved each time. ;-) If you did though, you're talking about an age old math teaser. I believe it was an arrow travels half the remaining distance in a second. How long will it take to arrive at its target? Answer: Never. It will always be some faction of distance away from the target.
Andrew Rissing wrote:
If you did though, you're talking about an age old math teaser. I believe it was an arrow travels half the remaining distance in a second. How long will it take to arrive at its target? Answer: Never. It will always be some faction of distance away from the target.
That's incorrect on multiple fronts. First Zeno created it not to try and disprove motion or anything equally silly but to disprove infinitely divisible time/distance. He failed to do so because the problem he setup requires basic calculus to solve: Specifically Limit N->oo (1-(1/N)), or Sigma N=2 to oo (1/N); both of which are equal to 1.
3x12=36 2x12=24 1x12=12 0x12=18
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Andrew Rissing wrote:
If you did though, you're talking about an age old math teaser. I believe it was an arrow travels half the remaining distance in a second. How long will it take to arrive at its target? Answer: Never. It will always be some faction of distance away from the target.
That's incorrect on multiple fronts. First Zeno created it not to try and disprove motion or anything equally silly but to disprove infinitely divisible time/distance. He failed to do so because the problem he setup requires basic calculus to solve: Specifically Limit N->oo (1-(1/N)), or Sigma N=2 to oo (1/N); both of which are equal to 1.
3x12=36 2x12=24 1x12=12 0x12=18
In the context of when it was presented to me, it was shown as a math problem to say that the arrow would never 'theoretically' reach its target. In the real world, "1 / infinity" is zero, but it was in the context of theory only.