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Math quiz [solved]

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  • M Mustafa Ismail Mustafa

    OK, let's see if you guys can work this one out :) The numbers: 1, 2, 3, 4, 5 and the operations +, -, *, / can be used in any order (parenthesis are free to control the order of evaluation) All the preceding mentioned numbers and operations can be used in any order once and only once to provide the result of 28. Remember, each of the operations can be used once only and each of the numbers can be used once only. You have to use them all to achieve your goal. You may begin :) [solution] Credited to aspdotnetdev (4 - (1/2)) * (5 + 3) = 28. Points awarded. Would you like me to make this a feature? Sorta like the CCC but for us more Mathematically as opposed to being "constantly high on peyote in order to be able to answer the CCC"?

    If the post was helpful, please vote, eh! Current activities: Playing Star Craft II. Don't bother me, eh? Now and forever, defiant to the end. What is Multiple Sclerosis[^]?

    modified on Friday, October 15, 2010 2:52 PM

    C Offline
    C Offline
    Chris Meech
    wrote on last edited by
    #2

    (2+3)*5+4-1 = 28. My kids and I used to play this game all the time. :) [EDIT] Just saw your rule about using all operators and only once. Not familiar with that one. :doh: :doh: :doh:

    Chris Meech I am Canadian. [heard in a local bar] In theory there is no difference between theory and practice. In practice there is. [Yogi Berra]

    S A 2 Replies Last reply
    0
    • M Mustafa Ismail Mustafa

      OK, let's see if you guys can work this one out :) The numbers: 1, 2, 3, 4, 5 and the operations +, -, *, / can be used in any order (parenthesis are free to control the order of evaluation) All the preceding mentioned numbers and operations can be used in any order once and only once to provide the result of 28. Remember, each of the operations can be used once only and each of the numbers can be used once only. You have to use them all to achieve your goal. You may begin :) [solution] Credited to aspdotnetdev (4 - (1/2)) * (5 + 3) = 28. Points awarded. Would you like me to make this a feature? Sorta like the CCC but for us more Mathematically as opposed to being "constantly high on peyote in order to be able to answer the CCC"?

      If the post was helpful, please vote, eh! Current activities: Playing Star Craft II. Don't bother me, eh? Now and forever, defiant to the end. What is Multiple Sclerosis[^]?

      modified on Friday, October 15, 2010 2:52 PM

      R Offline
      R Offline
      Rajesh R Subramanian
      wrote on last edited by
      #3

      Math on a Friday night? Get stuffed man. I'm here after a heavy meal, and some ripe red bananas are on the table. After I savour on them, I'll to get some good rest. G'Nite. :)

      There are some really weird people on this planet - MIM.

      1 Reply Last reply
      0
      • C Chris Meech

        (2+3)*5+4-1 = 28. My kids and I used to play this game all the time. :) [EDIT] Just saw your rule about using all operators and only once. Not familiar with that one. :doh: :doh: :doh:

        Chris Meech I am Canadian. [heard in a local bar] In theory there is no difference between theory and practice. In practice there is. [Yogi Berra]

        S Offline
        S Offline
        SinghUlarity
        wrote on last edited by
        #4

        You used + twice ;P

        I are n00b.

        1 Reply Last reply
        0
        • M Mustafa Ismail Mustafa

          OK, let's see if you guys can work this one out :) The numbers: 1, 2, 3, 4, 5 and the operations +, -, *, / can be used in any order (parenthesis are free to control the order of evaluation) All the preceding mentioned numbers and operations can be used in any order once and only once to provide the result of 28. Remember, each of the operations can be used once only and each of the numbers can be used once only. You have to use them all to achieve your goal. You may begin :) [solution] Credited to aspdotnetdev (4 - (1/2)) * (5 + 3) = 28. Points awarded. Would you like me to make this a feature? Sorta like the CCC but for us more Mathematically as opposed to being "constantly high on peyote in order to be able to answer the CCC"?

          If the post was helpful, please vote, eh! Current activities: Playing Star Craft II. Don't bother me, eh? Now and forever, defiant to the end. What is Multiple Sclerosis[^]?

          modified on Friday, October 15, 2010 2:52 PM

          S Offline
          S Offline
          SinghUlarity
          wrote on last edited by
          #5

          (5-1) * (4 + (3 / (11%2))) you never said i couldn't introduce new numbers and operators ;P

          I are n00b.

          A 1 Reply Last reply
          0
          • S SinghUlarity

            (5-1) * (4 + (3 / (11%2))) you never said i couldn't introduce new numbers and operators ;P

            I are n00b.

            A Offline
            A Offline
            AspDotNetDev
            wrote on last edited by
            #6

            SinghUlarity... wrote:

            introduce new numbers

            28 = 28 ;)

            [Forum Guidelines]

            1 Reply Last reply
            0
            • M Mustafa Ismail Mustafa

              OK, let's see if you guys can work this one out :) The numbers: 1, 2, 3, 4, 5 and the operations +, -, *, / can be used in any order (parenthesis are free to control the order of evaluation) All the preceding mentioned numbers and operations can be used in any order once and only once to provide the result of 28. Remember, each of the operations can be used once only and each of the numbers can be used once only. You have to use them all to achieve your goal. You may begin :) [solution] Credited to aspdotnetdev (4 - (1/2)) * (5 + 3) = 28. Points awarded. Would you like me to make this a feature? Sorta like the CCC but for us more Mathematically as opposed to being "constantly high on peyote in order to be able to answer the CCC"?

              If the post was helpful, please vote, eh! Current activities: Playing Star Craft II. Don't bother me, eh? Now and forever, defiant to the end. What is Multiple Sclerosis[^]?

              modified on Friday, October 15, 2010 2:52 PM

              L Offline
              L Offline
              leppie
              wrote on last edited by
              #7

              ((1 + 3) * 2) + (4 * 5)

              Took 4 seconds. How I got there: Started with biggest number first.

              xacc.ide
              IronScheme - 1.0 RC 1 - out now!
              ((λ (x) `(,x ',x)) '(λ (x) `(,x ',x))) The Scheme Programming Language – Fourth Edition

              S 1 Reply Last reply
              0
              • L leppie

                ((1 + 3) * 2) + (4 * 5)

                Took 4 seconds. How I got there: Started with biggest number first.

                xacc.ide
                IronScheme - 1.0 RC 1 - out now!
                ((λ (x) `(,x ',x)) '(λ (x) `(,x ',x))) The Scheme Programming Language – Fourth Edition

                S Offline
                S Offline
                SinghUlarity
                wrote on last edited by
                #8

                To be wrong :-D

                I are n00b.

                L 1 Reply Last reply
                0
                • S SinghUlarity

                  To be wrong :-D

                  I are n00b.

                  L Offline
                  L Offline
                  leppie
                  wrote on last edited by
                  #9

                  SinghUlarity... wrote:

                  To be wrong

                  FFS, I missed reading one word! :doh: Damnit, now it is a lot harder!

                  xacc.ide
                  IronScheme - 1.0 RC 1 - out now!
                  ((λ (x) `(,x ',x)) '(λ (x) `(,x ',x))) The Scheme Programming Language – Fourth Edition

                  S 1 Reply Last reply
                  0
                  • M Mustafa Ismail Mustafa

                    OK, let's see if you guys can work this one out :) The numbers: 1, 2, 3, 4, 5 and the operations +, -, *, / can be used in any order (parenthesis are free to control the order of evaluation) All the preceding mentioned numbers and operations can be used in any order once and only once to provide the result of 28. Remember, each of the operations can be used once only and each of the numbers can be used once only. You have to use them all to achieve your goal. You may begin :) [solution] Credited to aspdotnetdev (4 - (1/2)) * (5 + 3) = 28. Points awarded. Would you like me to make this a feature? Sorta like the CCC but for us more Mathematically as opposed to being "constantly high on peyote in order to be able to answer the CCC"?

                    If the post was helpful, please vote, eh! Current activities: Playing Star Craft II. Don't bother me, eh? Now and forever, defiant to the end. What is Multiple Sclerosis[^]?

                    modified on Friday, October 15, 2010 2:52 PM

                    A Offline
                    A Offline
                    AspDotNetDev
                    wrote on last edited by
                    #10

                    4 * (5 + 2)

                    [Forum Guidelines]

                    L S 2 Replies Last reply
                    0
                    • A AspDotNetDev

                      4 * (5 + 2)

                      [Forum Guidelines]

                      L Offline
                      L Offline
                      leppie
                      wrote on last edited by
                      #11

                      Very sneaky! Finding the loophole. The OP should have used must instead of can :)

                      xacc.ide
                      IronScheme - 1.0 RC 1 - out now!
                      ((λ (x) `(,x ',x)) '(λ (x) `(,x ',x))) The Scheme Programming Language – Fourth Edition

                      A H 2 Replies Last reply
                      0
                      • C Chris Meech

                        (2+3)*5+4-1 = 28. My kids and I used to play this game all the time. :) [EDIT] Just saw your rule about using all operators and only once. Not familiar with that one. :doh: :doh: :doh:

                        Chris Meech I am Canadian. [heard in a local bar] In theory there is no difference between theory and practice. In practice there is. [Yogi Berra]

                        A Offline
                        A Offline
                        AspDotNetDev
                        wrote on last edited by
                        #12

                        Hint: 4 * 7 = 28 :)

                        [Forum Guidelines]

                        1 Reply Last reply
                        0
                        • L leppie

                          SinghUlarity... wrote:

                          To be wrong

                          FFS, I missed reading one word! :doh: Damnit, now it is a lot harder!

                          xacc.ide
                          IronScheme - 1.0 RC 1 - out now!
                          ((λ (x) `(,x ',x)) '(λ (x) `(,x ',x))) The Scheme Programming Language – Fourth Edition

                          S Offline
                          S Offline
                          SinghUlarity
                          wrote on last edited by
                          #13

                          And that's how the clients end up with a Monkey when they order a Giraffe :laugh:

                          I are n00b.

                          1 Reply Last reply
                          0
                          • L leppie

                            Very sneaky! Finding the loophole. The OP should have used must instead of can :)

                            xacc.ide
                            IronScheme - 1.0 RC 1 - out now!
                            ((λ (x) `(,x ',x)) '(λ (x) `(,x ',x))) The Scheme Programming Language – Fourth Edition

                            A Offline
                            A Offline
                            AspDotNetDev
                            wrote on last edited by
                            #14

                            Just saw this bit: "You have to use them all to achieve your goal." :((

                            [Forum Guidelines]

                            1 Reply Last reply
                            0
                            • A AspDotNetDev

                              4 * (5 + 2)

                              [Forum Guidelines]

                              S Offline
                              S Offline
                              SinghUlarity
                              wrote on last edited by
                              #15

                              You have to use them all to achieve your goal. :rolleyes:

                              I are n00b.

                              1 Reply Last reply
                              0
                              • L leppie

                                Very sneaky! Finding the loophole. The OP should have used must instead of can :)

                                xacc.ide
                                IronScheme - 1.0 RC 1 - out now!
                                ((λ (x) `(,x ',x)) '(λ (x) `(,x ',x))) The Scheme Programming Language – Fourth Edition

                                H Offline
                                H Offline
                                Henry Minute
                                wrote on last edited by
                                #16

                                Mustafa did say "You have to use them all". Last sentence.

                                Henry Minute Do not read medical books! You could die of a misprint. - Mark Twain Girl: (staring) "Why do you need an icy cucumber?" “I want to report a fraud. The government is lying to us all.”

                                A 1 Reply Last reply
                                0
                                • H Henry Minute

                                  Mustafa did say "You have to use them all". Last sentence.

                                  Henry Minute Do not read medical books! You could die of a misprint. - Mark Twain Girl: (staring) "Why do you need an icy cucumber?" “I want to report a fraud. The government is lying to us all.”

                                  A Offline
                                  A Offline
                                  AspDotNetDev
                                  wrote on last edited by
                                  #17

                                  Perhaps the OP was mistaken. ;P

                                  [Forum Guidelines]

                                  M 1 Reply Last reply
                                  0
                                  • A AspDotNetDev

                                    Perhaps the OP was mistaken. ;P

                                    [Forum Guidelines]

                                    M Offline
                                    M Offline
                                    Mustafa Ismail Mustafa
                                    wrote on last edited by
                                    #18

                                    Nope, not mistaken :)

                                    If the post was helpful, please vote, eh! Current activities: Playing Star Craft II. Don't bother me, eh? Now and forever, defiant to the end. What is Multiple Sclerosis[^]?

                                    1 Reply Last reply
                                    0
                                    • M Mustafa Ismail Mustafa

                                      OK, let's see if you guys can work this one out :) The numbers: 1, 2, 3, 4, 5 and the operations +, -, *, / can be used in any order (parenthesis are free to control the order of evaluation) All the preceding mentioned numbers and operations can be used in any order once and only once to provide the result of 28. Remember, each of the operations can be used once only and each of the numbers can be used once only. You have to use them all to achieve your goal. You may begin :) [solution] Credited to aspdotnetdev (4 - (1/2)) * (5 + 3) = 28. Points awarded. Would you like me to make this a feature? Sorta like the CCC but for us more Mathematically as opposed to being "constantly high on peyote in order to be able to answer the CCC"?

                                      If the post was helpful, please vote, eh! Current activities: Playing Star Craft II. Don't bother me, eh? Now and forever, defiant to the end. What is Multiple Sclerosis[^]?

                                      modified on Friday, October 15, 2010 2:52 PM

                                      A Offline
                                      A Offline
                                      AspDotNetDev
                                      wrote on last edited by
                                      #19

                                      I do not think a solution exists. The closest my computer could get was 27. :((

                                      using System.Collections.Generic;
                                      using System.Windows.Forms;

                                      namespace WindowsFormsApplication1
                                      {
                                      public partial class Form1 : Form
                                      {

                                          delegate double Op(double num1, double num2);
                                      
                                          public Form1()
                                          {
                                              InitializeComponent();
                                      
                                              List<Op> ops = new List<Op> { new Op(M), new Op(D), new Op(A), new Op(S) };
                                      
                                              List<int> opOrder = new List<int> { 0, 0, 0, 0 };
                                      
                                              List<double> results = new List<double>();
                                              for (int op1 = 0; op1 < 4; op1++)
                                              {
                                                  for (int op2 = 0; op2 < 4; op2++)
                                                  {
                                                      for (int op3 = 0; op3 < 4; op3++)
                                                      {
                                                          for (int op4 = 0; op4 < 4; op4++)
                                                          {
                                                              for (int n1 = 1; n1 <= 5; n1++)
                                                              {
                                                                  for (int n2 = 1; n2 <= 5; n2++)
                                                                  {
                                                                      for (int n3 = 1; n3 <= 5; n3++)
                                                                      {
                                                                          for (int n4 = 1; n4 <= 5; n4++)
                                                                          {
                                                                              for (int n5 = 1; n5 <= 5; n5++)
                                                                              {
                                                                                  bool valid = true;
                                                                                  List<int> opTest = new List<int> { op1, op2, op3, op4 };
                                                                                  List<int> numTest = new List<int> { n1, n2, n3, n4, n5 };
                                                                                  for (int i = 0; i < 4; i++)
                                                                                  {
                                                                                      for (int j = 0; j < 4; j++)
                                                                                      {
                                                                                          if (i != j)
                                                                                          {
                                                                                              if (opTest\[i\] == opTest\[j\])
                                                                                              {
                                                                                                  valid = false;
                                                                                              }
                                                                                          }
                                      
                                      I S 2 Replies Last reply
                                      0
                                      • A AspDotNetDev

                                        I do not think a solution exists. The closest my computer could get was 27. :((

                                        using System.Collections.Generic;
                                        using System.Windows.Forms;

                                        namespace WindowsFormsApplication1
                                        {
                                        public partial class Form1 : Form
                                        {

                                            delegate double Op(double num1, double num2);
                                        
                                            public Form1()
                                            {
                                                InitializeComponent();
                                        
                                                List<Op> ops = new List<Op> { new Op(M), new Op(D), new Op(A), new Op(S) };
                                        
                                                List<int> opOrder = new List<int> { 0, 0, 0, 0 };
                                        
                                                List<double> results = new List<double>();
                                                for (int op1 = 0; op1 < 4; op1++)
                                                {
                                                    for (int op2 = 0; op2 < 4; op2++)
                                                    {
                                                        for (int op3 = 0; op3 < 4; op3++)
                                                        {
                                                            for (int op4 = 0; op4 < 4; op4++)
                                                            {
                                                                for (int n1 = 1; n1 <= 5; n1++)
                                                                {
                                                                    for (int n2 = 1; n2 <= 5; n2++)
                                                                    {
                                                                        for (int n3 = 1; n3 <= 5; n3++)
                                                                        {
                                                                            for (int n4 = 1; n4 <= 5; n4++)
                                                                            {
                                                                                for (int n5 = 1; n5 <= 5; n5++)
                                                                                {
                                                                                    bool valid = true;
                                                                                    List<int> opTest = new List<int> { op1, op2, op3, op4 };
                                                                                    List<int> numTest = new List<int> { n1, n2, n3, n4, n5 };
                                                                                    for (int i = 0; i < 4; i++)
                                                                                    {
                                                                                        for (int j = 0; j < 4; j++)
                                                                                        {
                                                                                            if (i != j)
                                                                                            {
                                                                                                if (opTest\[i\] == opTest\[j\])
                                                                                                {
                                                                                                    valid = false;
                                                                                                }
                                                                                            }
                                        
                                        I Offline
                                        I Offline
                                        Ian Shlasko
                                        wrote on last edited by
                                        #20

                                        static void Main(string[] args)
                                        {
                                        int[] nums = new int[] { 1,1,1,1,1};

                                        while (true)
                                        {
                                            Signs\[\] signs = new Signs\[4\];
                                        
                                            while (true)
                                            {
                                                if (nums.Sum() == 15)
                                                {
                                        
                                                    double x = nums\[0\];
                                                    for (int idx = 1; idx < 5; idx++)
                                                        switch (signs\[idx - 1\])
                                                        {
                                                            case Signs.Plus: x += nums\[idx\]; break;
                                                            case Signs.Minus: x -= nums\[idx\]; break;
                                                            case Signs.Div: x /= Convert.ToDouble(nums\[idx\]); break;
                                                            case Signs.Times: x \*= nums\[idx\]; break;
                                                        }
                                        
                                                    if (x == 28 && nums.Distinct().Count() != 5 && signs.Distinct().Count() == 4)
                                                    {
                                                        // Breakpoint here... What?  I'm lazy.
                                                    }
                                        
                                                }
                                        
                                                signs\[3\]++;
                                                for (int idx = 3; idx > 0; idx--)
                                                    if ((int)signs\[idx\] == 4)
                                                    {
                                                        signs\[idx\] = Signs.Plus;
                                                        signs\[idx - 1\]++;
                                                    }
                                                if ((int)signs\[0\] > 3) break;
                                        
                                                Console.Write('.');
                                            }
                                        
                                        
                                        
                                            nums\[4\]++;
                                            for (int idx = 4; idx > 0; idx--)
                                            {
                                                if (nums\[idx\] > 5)
                                                {
                                                    nums\[idx\] = 1;
                                                    nums\[idx - 1\]++;
                                                }
                                            }
                                            if (nums\[0\] > 5) break;
                                        }
                                        

                                        }

                                        private enum Signs : int
                                        {
                                        Plus = 0,
                                        Minus = 1,
                                        Times = 2,
                                        Div = 3
                                        }

                                        But this isn't inclusive... It wouldn't try something like (5+1)*(4-3)/2, because you can't do that sequentially.

                                        Proud to have finally moved to the A-Ark. Which one are you in?
                                        Author of the Guardians Saga (Sci-Fi/Fantasy novels)

                                        A 1 Reply Last reply
                                        0
                                        • I Ian Shlasko

                                          static void Main(string[] args)
                                          {
                                          int[] nums = new int[] { 1,1,1,1,1};

                                          while (true)
                                          {
                                              Signs\[\] signs = new Signs\[4\];
                                          
                                              while (true)
                                              {
                                                  if (nums.Sum() == 15)
                                                  {
                                          
                                                      double x = nums\[0\];
                                                      for (int idx = 1; idx < 5; idx++)
                                                          switch (signs\[idx - 1\])
                                                          {
                                                              case Signs.Plus: x += nums\[idx\]; break;
                                                              case Signs.Minus: x -= nums\[idx\]; break;
                                                              case Signs.Div: x /= Convert.ToDouble(nums\[idx\]); break;
                                                              case Signs.Times: x \*= nums\[idx\]; break;
                                                          }
                                          
                                                      if (x == 28 && nums.Distinct().Count() != 5 && signs.Distinct().Count() == 4)
                                                      {
                                                          // Breakpoint here... What?  I'm lazy.
                                                      }
                                          
                                                  }
                                          
                                                  signs\[3\]++;
                                                  for (int idx = 3; idx > 0; idx--)
                                                      if ((int)signs\[idx\] == 4)
                                                      {
                                                          signs\[idx\] = Signs.Plus;
                                                          signs\[idx - 1\]++;
                                                      }
                                                  if ((int)signs\[0\] > 3) break;
                                          
                                                  Console.Write('.');
                                              }
                                          
                                          
                                          
                                              nums\[4\]++;
                                              for (int idx = 4; idx > 0; idx--)
                                              {
                                                  if (nums\[idx\] > 5)
                                                  {
                                                      nums\[idx\] = 1;
                                                      nums\[idx - 1\]++;
                                                  }
                                              }
                                              if (nums\[0\] > 5) break;
                                          }
                                          

                                          }

                                          private enum Signs : int
                                          {
                                          Plus = 0,
                                          Minus = 1,
                                          Times = 2,
                                          Div = 3
                                          }

                                          But this isn't inclusive... It wouldn't try something like (5+1)*(4-3)/2, because you can't do that sequentially.

                                          Proud to have finally moved to the A-Ark. Which one are you in?
                                          Author of the Guardians Saga (Sci-Fi/Fantasy novels)

                                          A Offline
                                          A Offline
                                          AspDotNetDev
                                          wrote on last edited by
                                          #21

                                          Dang, I think you're right. I didn't account for parens. Will attempt to modify...

                                          [Forum Guidelines]

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