Skip to content
  • Categories
  • Recent
  • Tags
  • Popular
  • World
  • Users
  • Groups
Skins
  • Light
  • Cerulean
  • Cosmo
  • Flatly
  • Journal
  • Litera
  • Lumen
  • Lux
  • Materia
  • Minty
  • Morph
  • Pulse
  • Sandstone
  • Simplex
  • Sketchy
  • Spacelab
  • United
  • Yeti
  • Zephyr
  • Dark
  • Cyborg
  • Darkly
  • Quartz
  • Slate
  • Solar
  • Superhero
  • Vapor

  • Default (No Skin)
  • No Skin
Collapse
Code Project
  1. Home
  2. The Lounge
  3. Math quiz [solved]

Math quiz [solved]

Scheduled Pinned Locked Moved The Lounge
question
60 Posts 18 Posters 0 Views 1 Watching
  • Oldest to Newest
  • Newest to Oldest
  • Most Votes
Reply
  • Reply as topic
Log in to reply
This topic has been deleted. Only users with topic management privileges can see it.
  • M Mustafa Ismail Mustafa

    OK, let's see if you guys can work this one out :) The numbers: 1, 2, 3, 4, 5 and the operations +, -, *, / can be used in any order (parenthesis are free to control the order of evaluation) All the preceding mentioned numbers and operations can be used in any order once and only once to provide the result of 28. Remember, each of the operations can be used once only and each of the numbers can be used once only. You have to use them all to achieve your goal. You may begin :) [solution] Credited to aspdotnetdev (4 - (1/2)) * (5 + 3) = 28. Points awarded. Would you like me to make this a feature? Sorta like the CCC but for us more Mathematically as opposed to being "constantly high on peyote in order to be able to answer the CCC"?

    If the post was helpful, please vote, eh! Current activities: Playing Star Craft II. Don't bother me, eh? Now and forever, defiant to the end. What is Multiple Sclerosis[^]?

    modified on Friday, October 15, 2010 2:52 PM

    S Offline
    S Offline
    SinghUlarity
    wrote on last edited by
    #5

    (5-1) * (4 + (3 / (11%2))) you never said i couldn't introduce new numbers and operators ;P

    I are n00b.

    A 1 Reply Last reply
    0
    • S SinghUlarity

      (5-1) * (4 + (3 / (11%2))) you never said i couldn't introduce new numbers and operators ;P

      I are n00b.

      A Offline
      A Offline
      AspDotNetDev
      wrote on last edited by
      #6

      SinghUlarity... wrote:

      introduce new numbers

      28 = 28 ;)

      [Forum Guidelines]

      1 Reply Last reply
      0
      • M Mustafa Ismail Mustafa

        OK, let's see if you guys can work this one out :) The numbers: 1, 2, 3, 4, 5 and the operations +, -, *, / can be used in any order (parenthesis are free to control the order of evaluation) All the preceding mentioned numbers and operations can be used in any order once and only once to provide the result of 28. Remember, each of the operations can be used once only and each of the numbers can be used once only. You have to use them all to achieve your goal. You may begin :) [solution] Credited to aspdotnetdev (4 - (1/2)) * (5 + 3) = 28. Points awarded. Would you like me to make this a feature? Sorta like the CCC but for us more Mathematically as opposed to being "constantly high on peyote in order to be able to answer the CCC"?

        If the post was helpful, please vote, eh! Current activities: Playing Star Craft II. Don't bother me, eh? Now and forever, defiant to the end. What is Multiple Sclerosis[^]?

        modified on Friday, October 15, 2010 2:52 PM

        L Offline
        L Offline
        leppie
        wrote on last edited by
        #7

        ((1 + 3) * 2) + (4 * 5)

        Took 4 seconds. How I got there: Started with biggest number first.

        xacc.ide
        IronScheme - 1.0 RC 1 - out now!
        ((λ (x) `(,x ',x)) '(λ (x) `(,x ',x))) The Scheme Programming Language – Fourth Edition

        S 1 Reply Last reply
        0
        • L leppie

          ((1 + 3) * 2) + (4 * 5)

          Took 4 seconds. How I got there: Started with biggest number first.

          xacc.ide
          IronScheme - 1.0 RC 1 - out now!
          ((λ (x) `(,x ',x)) '(λ (x) `(,x ',x))) The Scheme Programming Language – Fourth Edition

          S Offline
          S Offline
          SinghUlarity
          wrote on last edited by
          #8

          To be wrong :-D

          I are n00b.

          L 1 Reply Last reply
          0
          • S SinghUlarity

            To be wrong :-D

            I are n00b.

            L Offline
            L Offline
            leppie
            wrote on last edited by
            #9

            SinghUlarity... wrote:

            To be wrong

            FFS, I missed reading one word! :doh: Damnit, now it is a lot harder!

            xacc.ide
            IronScheme - 1.0 RC 1 - out now!
            ((λ (x) `(,x ',x)) '(λ (x) `(,x ',x))) The Scheme Programming Language – Fourth Edition

            S 1 Reply Last reply
            0
            • M Mustafa Ismail Mustafa

              OK, let's see if you guys can work this one out :) The numbers: 1, 2, 3, 4, 5 and the operations +, -, *, / can be used in any order (parenthesis are free to control the order of evaluation) All the preceding mentioned numbers and operations can be used in any order once and only once to provide the result of 28. Remember, each of the operations can be used once only and each of the numbers can be used once only. You have to use them all to achieve your goal. You may begin :) [solution] Credited to aspdotnetdev (4 - (1/2)) * (5 + 3) = 28. Points awarded. Would you like me to make this a feature? Sorta like the CCC but for us more Mathematically as opposed to being "constantly high on peyote in order to be able to answer the CCC"?

              If the post was helpful, please vote, eh! Current activities: Playing Star Craft II. Don't bother me, eh? Now and forever, defiant to the end. What is Multiple Sclerosis[^]?

              modified on Friday, October 15, 2010 2:52 PM

              A Offline
              A Offline
              AspDotNetDev
              wrote on last edited by
              #10

              4 * (5 + 2)

              [Forum Guidelines]

              L S 2 Replies Last reply
              0
              • A AspDotNetDev

                4 * (5 + 2)

                [Forum Guidelines]

                L Offline
                L Offline
                leppie
                wrote on last edited by
                #11

                Very sneaky! Finding the loophole. The OP should have used must instead of can :)

                xacc.ide
                IronScheme - 1.0 RC 1 - out now!
                ((λ (x) `(,x ',x)) '(λ (x) `(,x ',x))) The Scheme Programming Language – Fourth Edition

                A H 2 Replies Last reply
                0
                • C Chris Meech

                  (2+3)*5+4-1 = 28. My kids and I used to play this game all the time. :) [EDIT] Just saw your rule about using all operators and only once. Not familiar with that one. :doh: :doh: :doh:

                  Chris Meech I am Canadian. [heard in a local bar] In theory there is no difference between theory and practice. In practice there is. [Yogi Berra]

                  A Offline
                  A Offline
                  AspDotNetDev
                  wrote on last edited by
                  #12

                  Hint: 4 * 7 = 28 :)

                  [Forum Guidelines]

                  1 Reply Last reply
                  0
                  • L leppie

                    SinghUlarity... wrote:

                    To be wrong

                    FFS, I missed reading one word! :doh: Damnit, now it is a lot harder!

                    xacc.ide
                    IronScheme - 1.0 RC 1 - out now!
                    ((λ (x) `(,x ',x)) '(λ (x) `(,x ',x))) The Scheme Programming Language – Fourth Edition

                    S Offline
                    S Offline
                    SinghUlarity
                    wrote on last edited by
                    #13

                    And that's how the clients end up with a Monkey when they order a Giraffe :laugh:

                    I are n00b.

                    1 Reply Last reply
                    0
                    • L leppie

                      Very sneaky! Finding the loophole. The OP should have used must instead of can :)

                      xacc.ide
                      IronScheme - 1.0 RC 1 - out now!
                      ((λ (x) `(,x ',x)) '(λ (x) `(,x ',x))) The Scheme Programming Language – Fourth Edition

                      A Offline
                      A Offline
                      AspDotNetDev
                      wrote on last edited by
                      #14

                      Just saw this bit: "You have to use them all to achieve your goal." :((

                      [Forum Guidelines]

                      1 Reply Last reply
                      0
                      • A AspDotNetDev

                        4 * (5 + 2)

                        [Forum Guidelines]

                        S Offline
                        S Offline
                        SinghUlarity
                        wrote on last edited by
                        #15

                        You have to use them all to achieve your goal. :rolleyes:

                        I are n00b.

                        1 Reply Last reply
                        0
                        • L leppie

                          Very sneaky! Finding the loophole. The OP should have used must instead of can :)

                          xacc.ide
                          IronScheme - 1.0 RC 1 - out now!
                          ((λ (x) `(,x ',x)) '(λ (x) `(,x ',x))) The Scheme Programming Language – Fourth Edition

                          H Offline
                          H Offline
                          Henry Minute
                          wrote on last edited by
                          #16

                          Mustafa did say "You have to use them all". Last sentence.

                          Henry Minute Do not read medical books! You could die of a misprint. - Mark Twain Girl: (staring) "Why do you need an icy cucumber?" “I want to report a fraud. The government is lying to us all.”

                          A 1 Reply Last reply
                          0
                          • H Henry Minute

                            Mustafa did say "You have to use them all". Last sentence.

                            Henry Minute Do not read medical books! You could die of a misprint. - Mark Twain Girl: (staring) "Why do you need an icy cucumber?" “I want to report a fraud. The government is lying to us all.”

                            A Offline
                            A Offline
                            AspDotNetDev
                            wrote on last edited by
                            #17

                            Perhaps the OP was mistaken. ;P

                            [Forum Guidelines]

                            M 1 Reply Last reply
                            0
                            • A AspDotNetDev

                              Perhaps the OP was mistaken. ;P

                              [Forum Guidelines]

                              M Offline
                              M Offline
                              Mustafa Ismail Mustafa
                              wrote on last edited by
                              #18

                              Nope, not mistaken :)

                              If the post was helpful, please vote, eh! Current activities: Playing Star Craft II. Don't bother me, eh? Now and forever, defiant to the end. What is Multiple Sclerosis[^]?

                              1 Reply Last reply
                              0
                              • M Mustafa Ismail Mustafa

                                OK, let's see if you guys can work this one out :) The numbers: 1, 2, 3, 4, 5 and the operations +, -, *, / can be used in any order (parenthesis are free to control the order of evaluation) All the preceding mentioned numbers and operations can be used in any order once and only once to provide the result of 28. Remember, each of the operations can be used once only and each of the numbers can be used once only. You have to use them all to achieve your goal. You may begin :) [solution] Credited to aspdotnetdev (4 - (1/2)) * (5 + 3) = 28. Points awarded. Would you like me to make this a feature? Sorta like the CCC but for us more Mathematically as opposed to being "constantly high on peyote in order to be able to answer the CCC"?

                                If the post was helpful, please vote, eh! Current activities: Playing Star Craft II. Don't bother me, eh? Now and forever, defiant to the end. What is Multiple Sclerosis[^]?

                                modified on Friday, October 15, 2010 2:52 PM

                                A Offline
                                A Offline
                                AspDotNetDev
                                wrote on last edited by
                                #19

                                I do not think a solution exists. The closest my computer could get was 27. :((

                                using System.Collections.Generic;
                                using System.Windows.Forms;

                                namespace WindowsFormsApplication1
                                {
                                public partial class Form1 : Form
                                {

                                    delegate double Op(double num1, double num2);
                                
                                    public Form1()
                                    {
                                        InitializeComponent();
                                
                                        List<Op> ops = new List<Op> { new Op(M), new Op(D), new Op(A), new Op(S) };
                                
                                        List<int> opOrder = new List<int> { 0, 0, 0, 0 };
                                
                                        List<double> results = new List<double>();
                                        for (int op1 = 0; op1 < 4; op1++)
                                        {
                                            for (int op2 = 0; op2 < 4; op2++)
                                            {
                                                for (int op3 = 0; op3 < 4; op3++)
                                                {
                                                    for (int op4 = 0; op4 < 4; op4++)
                                                    {
                                                        for (int n1 = 1; n1 <= 5; n1++)
                                                        {
                                                            for (int n2 = 1; n2 <= 5; n2++)
                                                            {
                                                                for (int n3 = 1; n3 <= 5; n3++)
                                                                {
                                                                    for (int n4 = 1; n4 <= 5; n4++)
                                                                    {
                                                                        for (int n5 = 1; n5 <= 5; n5++)
                                                                        {
                                                                            bool valid = true;
                                                                            List<int> opTest = new List<int> { op1, op2, op3, op4 };
                                                                            List<int> numTest = new List<int> { n1, n2, n3, n4, n5 };
                                                                            for (int i = 0; i < 4; i++)
                                                                            {
                                                                                for (int j = 0; j < 4; j++)
                                                                                {
                                                                                    if (i != j)
                                                                                    {
                                                                                        if (opTest\[i\] == opTest\[j\])
                                                                                        {
                                                                                            valid = false;
                                                                                        }
                                                                                    }
                                
                                I S 2 Replies Last reply
                                0
                                • A AspDotNetDev

                                  I do not think a solution exists. The closest my computer could get was 27. :((

                                  using System.Collections.Generic;
                                  using System.Windows.Forms;

                                  namespace WindowsFormsApplication1
                                  {
                                  public partial class Form1 : Form
                                  {

                                      delegate double Op(double num1, double num2);
                                  
                                      public Form1()
                                      {
                                          InitializeComponent();
                                  
                                          List<Op> ops = new List<Op> { new Op(M), new Op(D), new Op(A), new Op(S) };
                                  
                                          List<int> opOrder = new List<int> { 0, 0, 0, 0 };
                                  
                                          List<double> results = new List<double>();
                                          for (int op1 = 0; op1 < 4; op1++)
                                          {
                                              for (int op2 = 0; op2 < 4; op2++)
                                              {
                                                  for (int op3 = 0; op3 < 4; op3++)
                                                  {
                                                      for (int op4 = 0; op4 < 4; op4++)
                                                      {
                                                          for (int n1 = 1; n1 <= 5; n1++)
                                                          {
                                                              for (int n2 = 1; n2 <= 5; n2++)
                                                              {
                                                                  for (int n3 = 1; n3 <= 5; n3++)
                                                                  {
                                                                      for (int n4 = 1; n4 <= 5; n4++)
                                                                      {
                                                                          for (int n5 = 1; n5 <= 5; n5++)
                                                                          {
                                                                              bool valid = true;
                                                                              List<int> opTest = new List<int> { op1, op2, op3, op4 };
                                                                              List<int> numTest = new List<int> { n1, n2, n3, n4, n5 };
                                                                              for (int i = 0; i < 4; i++)
                                                                              {
                                                                                  for (int j = 0; j < 4; j++)
                                                                                  {
                                                                                      if (i != j)
                                                                                      {
                                                                                          if (opTest\[i\] == opTest\[j\])
                                                                                          {
                                                                                              valid = false;
                                                                                          }
                                                                                      }
                                  
                                  I Offline
                                  I Offline
                                  Ian Shlasko
                                  wrote on last edited by
                                  #20

                                  static void Main(string[] args)
                                  {
                                  int[] nums = new int[] { 1,1,1,1,1};

                                  while (true)
                                  {
                                      Signs\[\] signs = new Signs\[4\];
                                  
                                      while (true)
                                      {
                                          if (nums.Sum() == 15)
                                          {
                                  
                                              double x = nums\[0\];
                                              for (int idx = 1; idx < 5; idx++)
                                                  switch (signs\[idx - 1\])
                                                  {
                                                      case Signs.Plus: x += nums\[idx\]; break;
                                                      case Signs.Minus: x -= nums\[idx\]; break;
                                                      case Signs.Div: x /= Convert.ToDouble(nums\[idx\]); break;
                                                      case Signs.Times: x \*= nums\[idx\]; break;
                                                  }
                                  
                                              if (x == 28 && nums.Distinct().Count() != 5 && signs.Distinct().Count() == 4)
                                              {
                                                  // Breakpoint here... What?  I'm lazy.
                                              }
                                  
                                          }
                                  
                                          signs\[3\]++;
                                          for (int idx = 3; idx > 0; idx--)
                                              if ((int)signs\[idx\] == 4)
                                              {
                                                  signs\[idx\] = Signs.Plus;
                                                  signs\[idx - 1\]++;
                                              }
                                          if ((int)signs\[0\] > 3) break;
                                  
                                          Console.Write('.');
                                      }
                                  
                                  
                                  
                                      nums\[4\]++;
                                      for (int idx = 4; idx > 0; idx--)
                                      {
                                          if (nums\[idx\] > 5)
                                          {
                                              nums\[idx\] = 1;
                                              nums\[idx - 1\]++;
                                          }
                                      }
                                      if (nums\[0\] > 5) break;
                                  }
                                  

                                  }

                                  private enum Signs : int
                                  {
                                  Plus = 0,
                                  Minus = 1,
                                  Times = 2,
                                  Div = 3
                                  }

                                  But this isn't inclusive... It wouldn't try something like (5+1)*(4-3)/2, because you can't do that sequentially.

                                  Proud to have finally moved to the A-Ark. Which one are you in?
                                  Author of the Guardians Saga (Sci-Fi/Fantasy novels)

                                  A 1 Reply Last reply
                                  0
                                  • I Ian Shlasko

                                    static void Main(string[] args)
                                    {
                                    int[] nums = new int[] { 1,1,1,1,1};

                                    while (true)
                                    {
                                        Signs\[\] signs = new Signs\[4\];
                                    
                                        while (true)
                                        {
                                            if (nums.Sum() == 15)
                                            {
                                    
                                                double x = nums\[0\];
                                                for (int idx = 1; idx < 5; idx++)
                                                    switch (signs\[idx - 1\])
                                                    {
                                                        case Signs.Plus: x += nums\[idx\]; break;
                                                        case Signs.Minus: x -= nums\[idx\]; break;
                                                        case Signs.Div: x /= Convert.ToDouble(nums\[idx\]); break;
                                                        case Signs.Times: x \*= nums\[idx\]; break;
                                                    }
                                    
                                                if (x == 28 && nums.Distinct().Count() != 5 && signs.Distinct().Count() == 4)
                                                {
                                                    // Breakpoint here... What?  I'm lazy.
                                                }
                                    
                                            }
                                    
                                            signs\[3\]++;
                                            for (int idx = 3; idx > 0; idx--)
                                                if ((int)signs\[idx\] == 4)
                                                {
                                                    signs\[idx\] = Signs.Plus;
                                                    signs\[idx - 1\]++;
                                                }
                                            if ((int)signs\[0\] > 3) break;
                                    
                                            Console.Write('.');
                                        }
                                    
                                    
                                    
                                        nums\[4\]++;
                                        for (int idx = 4; idx > 0; idx--)
                                        {
                                            if (nums\[idx\] > 5)
                                            {
                                                nums\[idx\] = 1;
                                                nums\[idx - 1\]++;
                                            }
                                        }
                                        if (nums\[0\] > 5) break;
                                    }
                                    

                                    }

                                    private enum Signs : int
                                    {
                                    Plus = 0,
                                    Minus = 1,
                                    Times = 2,
                                    Div = 3
                                    }

                                    But this isn't inclusive... It wouldn't try something like (5+1)*(4-3)/2, because you can't do that sequentially.

                                    Proud to have finally moved to the A-Ark. Which one are you in?
                                    Author of the Guardians Saga (Sci-Fi/Fantasy novels)

                                    A Offline
                                    A Offline
                                    AspDotNetDev
                                    wrote on last edited by
                                    #21

                                    Dang, I think you're right. I didn't account for parens. Will attempt to modify...

                                    [Forum Guidelines]

                                    1 Reply Last reply
                                    0
                                    • A AspDotNetDev

                                      I do not think a solution exists. The closest my computer could get was 27. :((

                                      using System.Collections.Generic;
                                      using System.Windows.Forms;

                                      namespace WindowsFormsApplication1
                                      {
                                      public partial class Form1 : Form
                                      {

                                          delegate double Op(double num1, double num2);
                                      
                                          public Form1()
                                          {
                                              InitializeComponent();
                                      
                                              List<Op> ops = new List<Op> { new Op(M), new Op(D), new Op(A), new Op(S) };
                                      
                                              List<int> opOrder = new List<int> { 0, 0, 0, 0 };
                                      
                                              List<double> results = new List<double>();
                                              for (int op1 = 0; op1 < 4; op1++)
                                              {
                                                  for (int op2 = 0; op2 < 4; op2++)
                                                  {
                                                      for (int op3 = 0; op3 < 4; op3++)
                                                      {
                                                          for (int op4 = 0; op4 < 4; op4++)
                                                          {
                                                              for (int n1 = 1; n1 <= 5; n1++)
                                                              {
                                                                  for (int n2 = 1; n2 <= 5; n2++)
                                                                  {
                                                                      for (int n3 = 1; n3 <= 5; n3++)
                                                                      {
                                                                          for (int n4 = 1; n4 <= 5; n4++)
                                                                          {
                                                                              for (int n5 = 1; n5 <= 5; n5++)
                                                                              {
                                                                                  bool valid = true;
                                                                                  List<int> opTest = new List<int> { op1, op2, op3, op4 };
                                                                                  List<int> numTest = new List<int> { n1, n2, n3, n4, n5 };
                                                                                  for (int i = 0; i < 4; i++)
                                                                                  {
                                                                                      for (int j = 0; j < 4; j++)
                                                                                      {
                                                                                          if (i != j)
                                                                                          {
                                                                                              if (opTest\[i\] == opTest\[j\])
                                                                                              {
                                                                                                  valid = false;
                                                                                              }
                                                                                          }
                                      
                                      S Offline
                                      S Offline
                                      SinghUlarity
                                      wrote on last edited by
                                      #22

                                      While we kill ourselves over this problem, Mustafa is out somewhere enjoying his weekend. This is all a set-up :suss:

                                      I are n00b.

                                      M 1 Reply Last reply
                                      0
                                      • M Mustafa Ismail Mustafa

                                        OK, let's see if you guys can work this one out :) The numbers: 1, 2, 3, 4, 5 and the operations +, -, *, / can be used in any order (parenthesis are free to control the order of evaluation) All the preceding mentioned numbers and operations can be used in any order once and only once to provide the result of 28. Remember, each of the operations can be used once only and each of the numbers can be used once only. You have to use them all to achieve your goal. You may begin :) [solution] Credited to aspdotnetdev (4 - (1/2)) * (5 + 3) = 28. Points awarded. Would you like me to make this a feature? Sorta like the CCC but for us more Mathematically as opposed to being "constantly high on peyote in order to be able to answer the CCC"?

                                        If the post was helpful, please vote, eh! Current activities: Playing Star Craft II. Don't bother me, eh? Now and forever, defiant to the end. What is Multiple Sclerosis[^]?

                                        modified on Friday, October 15, 2010 2:52 PM

                                        G Offline
                                        G Offline
                                        GrumbleDuke
                                        wrote on last edited by
                                        #23

                                        Using integer math: 4*(5+2)-1/3 = 28

                                        I 1 Reply Last reply
                                        0
                                        • G GrumbleDuke

                                          Using integer math: 4*(5+2)-1/3 = 28

                                          I Offline
                                          I Offline
                                          Ian Shlasko
                                          wrote on last edited by
                                          #24

                                          But he said numbers, not integers, so you can't just round it :)

                                          Proud to have finally moved to the A-Ark. Which one are you in?
                                          Author of the Guardians Saga (Sci-Fi/Fantasy novels)

                                          1 Reply Last reply
                                          0
                                          Reply
                                          • Reply as topic
                                          Log in to reply
                                          • Oldest to Newest
                                          • Newest to Oldest
                                          • Most Votes


                                          • Login

                                          • Don't have an account? Register

                                          • Login or register to search.
                                          • First post
                                            Last post
                                          0
                                          • Categories
                                          • Recent
                                          • Tags
                                          • Popular
                                          • World
                                          • Users
                                          • Groups