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TIL...... [modified]

Scheduled Pinned Locked Moved Algorithms
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  • N NeverHeardOfMe

    OK... p^2 - 24*p + 143 = 0 So..?

    L Offline
    L Offline
    Luc Pattyn
    wrote on last edited by
    #8

    a quadratic equation like that has at most two solutions, so it is hardly a way to discover lots of primes. :)

    Luc Pattyn [Forum Guidelines] [Why QA sucks] [My Articles] Nil Volentibus Arduum

    Please use <PRE> tags for code snippets, they preserve indentation, and improve readability.

    modified on Thursday, November 4, 2010 12:05 PM

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    • N NeverHeardOfMe

      ...an extraordinary fact - probably known to half of you, but nevertheless I thought I'd share it. It's not an alogorithm, but never mind! The square of any prime number >= 5 can be expressed as 1 + a multiple of 24 or If p is prime, then p ^ 2 = 1 + 24 * n, for some n Don't know about you, but I think that's quite amazing. Why is it true at all, and given that it is, where does 24 come from?! (Pity it's not 42 really!) [edit] When I ask "where does 24 come from?" I am not asking for a mathermatical proof - I can look that up myself. It's more just a metaphysical musing...)

      modified on Thursday, November 4, 2010 6:37 AM

      L Offline
      L Offline
      Luc Pattyn
      wrote on last edited by
      #9

      that is correct, even when n needs to be 1/8 for p=2. :-D

      Luc Pattyn [Forum Guidelines] [Why QA sucks] [My Articles] Nil Volentibus Arduum

      Please use <PRE> tags for code snippets, they preserve indentation, and improve readability.

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      • L Luc Pattyn

        a quadratic equation like that has at most two solutions, so it is hardly a way to discover lots of primes. :)

        Luc Pattyn [Forum Guidelines] [Why QA sucks] [My Articles] Nil Volentibus Arduum

        Please use <PRE> tags for code snippets, they preserve indentation, and improve readability.

        modified on Thursday, November 4, 2010 12:05 PM

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        NeverHeardOfMe
        wrote on last edited by
        #10

        We have a saying round here: "Don't tell I, tell 'e"... especially as that particular one doesn't even have any (real) solutions at all!

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        • L Luc Pattyn

          that is correct, even when n needs to be 1/8 for p=2. :-D

          Luc Pattyn [Forum Guidelines] [Why QA sucks] [My Articles] Nil Volentibus Arduum

          Please use <PRE> tags for code snippets, they preserve indentation, and improve readability.

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          NeverHeardOfMe
          wrote on last edited by
          #11

          Actually, that's QI.. it also "works" for p=3 (n=1/3) - so in fact, the *only* value of p for which n is neither an integer nor a proper fraction is 4.[edit] OOPS what an idiot! since when was 4 a prime! :-O

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          • N NeverHeardOfMe

            Me :confused: too - ome of us is being a bit dumb here (most likely me...) I just re-wrote the equation you posted... what does it prove? Is there a typo in it (yours)?

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            Lost User
            wrote on last edited by
            #12

            No typo as far as I am aware. I just thought you wanted to know what was the value of 'n' in your original question.

            Just say 'NO' to evaluated arguments for diadic functions! Ash

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            • N NeverHeardOfMe

              We have a saying round here: "Don't tell I, tell 'e"... especially as that particular one doesn't even have any (real) solutions at all!

              L Offline
              L Offline
              Luc Pattyn
              wrote on last edited by
              #13

              you'll have more luck with

              x2 + x + 41

              for natural values of x. :)

              Luc Pattyn [Forum Guidelines] [Why QA sucks] [My Articles] Nil Volentibus Arduum

              Please use <PRE> tags for code snippets, they preserve indentation, and improve readability.

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              • L Lost User

                No typo as far as I am aware. I just thought you wanted to know what was the value of 'n' in your original question.

                Just say 'NO' to evaluated arguments for diadic functions! Ash

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                NeverHeardOfMe
                wrote on last edited by
                #14

                Ah, got you - except that it doesn't work for all values of p p=5, n=1 != p-6 p=7, n=2 != p-6 p=11, n=5 ok p=13, n=7 ok p=17, n=12 != p-6 ...

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                • L Luc Pattyn

                  you'll have more luck with

                  x2 + x + 41

                  for natural values of x. :)

                  Luc Pattyn [Forum Guidelines] [Why QA sucks] [My Articles] Nil Volentibus Arduum

                  Please use <PRE> tags for code snippets, they preserve indentation, and improve readability.

                  N Offline
                  N Offline
                  NeverHeardOfMe
                  wrote on last edited by
                  #15

                  Now you're just confusing me....

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                  • N NeverHeardOfMe

                    ...an extraordinary fact - probably known to half of you, but nevertheless I thought I'd share it. It's not an alogorithm, but never mind! The square of any prime number >= 5 can be expressed as 1 + a multiple of 24 or If p is prime, then p ^ 2 = 1 + 24 * n, for some n Don't know about you, but I think that's quite amazing. Why is it true at all, and given that it is, where does 24 come from?! (Pity it's not 42 really!) [edit] When I ask "where does 24 come from?" I am not asking for a mathermatical proof - I can look that up myself. It's more just a metaphysical musing...)

                    modified on Thursday, November 4, 2010 6:37 AM

                    _ Offline
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                    _Erik_
                    wrote on last edited by
                    #16

                    Well, I know you are not asking for a mathematical proof, but like I am much better at maths than metaphisics... Where does 24 come from? Since p is prime and greater than 5, p cannot be an even number. So: p2-1=(p-1)*(p+1). Like p is odd, both (p-1) and (p+1) are even, so we can say: p2-1=2a*2b=4ab. Like (p-1) and (p+1) are two consecutive even numbers, one of them must be multiple of 4, so 2a is multiple of 4 or 2b is multiple of 4, so we can express this like: p2-1=4a*2c=8ac or p2-1=4b*2d=8bd I will examine just one of these two cases becouse they are symmetrical. Now, like (p-1) and (p+1) are two consecutive even numbers, one of them must be multiple of 3, so: p2-1=8a*3d=24ad or p2-1=8c*3e=24ce And there it is.

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                    • _ _Erik_

                      Well, I know you are not asking for a mathematical proof, but like I am much better at maths than metaphisics... Where does 24 come from? Since p is prime and greater than 5, p cannot be an even number. So: p2-1=(p-1)*(p+1). Like p is odd, both (p-1) and (p+1) are even, so we can say: p2-1=2a*2b=4ab. Like (p-1) and (p+1) are two consecutive even numbers, one of them must be multiple of 4, so 2a is multiple of 4 or 2b is multiple of 4, so we can express this like: p2-1=4a*2c=8ac or p2-1=4b*2d=8bd I will examine just one of these two cases becouse they are symmetrical. Now, like (p-1) and (p+1) are two consecutive even numbers, one of them must be multiple of 3, so: p2-1=8a*3d=24ad or p2-1=8c*3e=24ce And there it is.

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                      NeverHeardOfMe
                      wrote on last edited by
                      #17

                      You haven't explained the last step correctly, and the statement

                      _Erik_ wrote:

                      Now, like (p-1) and (p+1) are two consecutive even numbers, one of them must be multiple of 3

                      is wrong.

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                      • N NeverHeardOfMe

                        You haven't explained the last step correctly, and the statement

                        _Erik_ wrote:

                        Now, like (p-1) and (p+1) are two consecutive even numbers, one of them must be multiple of 3

                        is wrong.

                        _ Offline
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                        _Erik_
                        wrote on last edited by
                        #18

                        It is not wrong, becouse p is a prime number, what means: if p mod 3 = 1 then (p-1) mod 3=0, so (p-1) is multiple of 3. if p mod 3 = 2 then (p+1) mod 3=0, so (p+1) is multiple of 3. if p mod 3 = 0 then p would not be prime and we would not be following our premise

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                        • _ _Erik_

                          It is not wrong, becouse p is a prime number, what means: if p mod 3 = 1 then (p-1) mod 3=0, so (p-1) is multiple of 3. if p mod 3 = 2 then (p+1) mod 3=0, so (p+1) is multiple of 3. if p mod 3 = 0 then p would not be prime and we would not be following our premise

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                          NeverHeardOfMe
                          wrote on last edited by
                          #19

                          Yes, sorry - I was forgetting that p is prime! Time to knock off for the day I think...

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                          • _ _Erik_

                            Well, I know you are not asking for a mathematical proof, but like I am much better at maths than metaphisics... Where does 24 come from? Since p is prime and greater than 5, p cannot be an even number. So: p2-1=(p-1)*(p+1). Like p is odd, both (p-1) and (p+1) are even, so we can say: p2-1=2a*2b=4ab. Like (p-1) and (p+1) are two consecutive even numbers, one of them must be multiple of 4, so 2a is multiple of 4 or 2b is multiple of 4, so we can express this like: p2-1=4a*2c=8ac or p2-1=4b*2d=8bd I will examine just one of these two cases becouse they are symmetrical. Now, like (p-1) and (p+1) are two consecutive even numbers, one of them must be multiple of 3, so: p2-1=8a*3d=24ad or p2-1=8c*3e=24ce And there it is.

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                            MarkLoboo
                            wrote on last edited by
                            #20

                            3 cheers !!:thumbsup:

                            All are born right-handed. Only gifted few overcome it. There's NO excuse for not commenting your code.

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                            • L Lost User

                              Try

                              p ^ 2 = 1 + 24 * (p - 6)

                              Just say 'NO' to evaluated arguments for diadic functions! Ash

                              R Offline
                              R Offline
                              redbones
                              wrote on last edited by
                              #21

                              actually that's not correct; when p=7 then by your formula we would have 49=1+24*1 = 25

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                              • N NeverHeardOfMe

                                ...an extraordinary fact - probably known to half of you, but nevertheless I thought I'd share it. It's not an alogorithm, but never mind! The square of any prime number >= 5 can be expressed as 1 + a multiple of 24 or If p is prime, then p ^ 2 = 1 + 24 * n, for some n Don't know about you, but I think that's quite amazing. Why is it true at all, and given that it is, where does 24 come from?! (Pity it's not 42 really!) [edit] When I ask "where does 24 come from?" I am not asking for a mathermatical proof - I can look that up myself. It's more just a metaphysical musing...)

                                modified on Thursday, November 4, 2010 6:37 AM

                                D Offline
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                                dbaechtel
                                wrote on last edited by
                                #22

                                WolramAlpha say that the equation p^2 = 24*d*e+1 is a hyperboloid of one sheet which means that it is of the form x^2/a^2 + y^2/b^2 - z^2/c^2 = 1

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                                • N NeverHeardOfMe

                                  ...an extraordinary fact - probably known to half of you, but nevertheless I thought I'd share it. It's not an alogorithm, but never mind! The square of any prime number >= 5 can be expressed as 1 + a multiple of 24 or If p is prime, then p ^ 2 = 1 + 24 * n, for some n Don't know about you, but I think that's quite amazing. Why is it true at all, and given that it is, where does 24 come from?! (Pity it's not 42 really!) [edit] When I ask "where does 24 come from?" I am not asking for a mathermatical proof - I can look that up myself. It's more just a metaphysical musing...)

                                  modified on Thursday, November 4, 2010 6:37 AM

                                  D Offline
                                  D Offline
                                  Daniel Pfeffer
                                  wrote on last edited by
                                  #23

                                  For p = 5, p^2 = 24 * 1 + 1 All primes > 5 have the form p = 30*k + l, where l is 1, 7, 11, 13, 17, 19, 23 or 29. All other values of l have a common factor > 1 with 30, and therefore cannot produce primes. p^2 = 900*k^2 + 60*k*l + l^2 Rewrite the first 2 terms as 60*( 15*k^2 + k*l ). The sum in the parentheses is always even, so the entire expression is divisible by 24. We are left with l^2. By inspection: 1^2 = 24 * 0 + 1 7^2 = 24 * 2 + 1 11^2 = 24 * 5 + 1 13^2 = 24 * 7 + 1 17^2 = 24 * 12 + 1 19^2 = 24 * 15 + 1 23^2 = 24 * 22 + 1 29^2 = 24 * 35 + 1 QED

                                  N 1 Reply Last reply
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                                  • N NeverHeardOfMe

                                    ...an extraordinary fact - probably known to half of you, but nevertheless I thought I'd share it. It's not an alogorithm, but never mind! The square of any prime number >= 5 can be expressed as 1 + a multiple of 24 or If p is prime, then p ^ 2 = 1 + 24 * n, for some n Don't know about you, but I think that's quite amazing. Why is it true at all, and given that it is, where does 24 come from?! (Pity it's not 42 really!) [edit] When I ask "where does 24 come from?" I am not asking for a mathermatical proof - I can look that up myself. It's more just a metaphysical musing...)

                                    modified on Thursday, November 4, 2010 6:37 AM

                                    M Offline
                                    M Offline
                                    Michael Waters
                                    wrote on last edited by
                                    #24

                                    So to put it another way, to test the primality of any number, first square it, then mod it by 24. If the answer is 1, it's possibly prime. Nifty. Perhaps impractical for cryptological purposes, but nifty nonetheless. Reminds me of p = 6*n + 1 OR p = 6*n - 1 for all p given some n.

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                                    • D Daniel Pfeffer

                                      For p = 5, p^2 = 24 * 1 + 1 All primes > 5 have the form p = 30*k + l, where l is 1, 7, 11, 13, 17, 19, 23 or 29. All other values of l have a common factor > 1 with 30, and therefore cannot produce primes. p^2 = 900*k^2 + 60*k*l + l^2 Rewrite the first 2 terms as 60*( 15*k^2 + k*l ). The sum in the parentheses is always even, so the entire expression is divisible by 24. We are left with l^2. By inspection: 1^2 = 24 * 0 + 1 7^2 = 24 * 2 + 1 11^2 = 24 * 5 + 1 13^2 = 24 * 7 + 1 17^2 = 24 * 12 + 1 19^2 = 24 * 15 + 1 23^2 = 24 * 22 + 1 29^2 = 24 * 35 + 1 QED

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                                      NeverHeardOfMe
                                      wrote on last edited by
                                      #25

                                      Daniel Pfeffer wrote:

                                      All primes > 5 have the form p = 30*k + l, where l is 1, 7, 11, 13, 17, 19, 23 or 29. All other values of l have a common factor > 1 with 30, and therefore cannot produce primes.

                                      That's quite an assertion... not saying it's wrong, but it can't be s starting point for a proof of anything; it has to be proved first. Surely.

                                      D 2 Replies Last reply
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                                      • N NeverHeardOfMe

                                        ...an extraordinary fact - probably known to half of you, but nevertheless I thought I'd share it. It's not an alogorithm, but never mind! The square of any prime number >= 5 can be expressed as 1 + a multiple of 24 or If p is prime, then p ^ 2 = 1 + 24 * n, for some n Don't know about you, but I think that's quite amazing. Why is it true at all, and given that it is, where does 24 come from?! (Pity it's not 42 really!) [edit] When I ask "where does 24 come from?" I am not asking for a mathermatical proof - I can look that up myself. It's more just a metaphysical musing...)

                                        modified on Thursday, November 4, 2010 6:37 AM

                                        C Offline
                                        C Offline
                                        cp9876
                                        wrote on last edited by
                                        #26

                                        NeverHeardOfMe wrote:

                                        If p is prime, then p ^ 2 = 1 + 24 * n, for some n Don't know about you, but I think that's quite amazing. Why is it true at all, and given that it is, where does 24 come from?! (Pity it's not 42 really!)

                                        It only needs a small modification to use 42: If p is prime and p > 7 then

                                        p^6 = 1 + 42n for some n

                                        Peter "Until the invention of the computer, the machine gun was the device that enabled humans to make the most mistakes in the smallest amount of time."

                                        modified on Wednesday, November 10, 2010 11:37 PM

                                        B 1 Reply Last reply
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                                        • N NeverHeardOfMe

                                          ...an extraordinary fact - probably known to half of you, but nevertheless I thought I'd share it. It's not an alogorithm, but never mind! The square of any prime number >= 5 can be expressed as 1 + a multiple of 24 or If p is prime, then p ^ 2 = 1 + 24 * n, for some n Don't know about you, but I think that's quite amazing. Why is it true at all, and given that it is, where does 24 come from?! (Pity it's not 42 really!) [edit] When I ask "where does 24 come from?" I am not asking for a mathermatical proof - I can look that up myself. It's more just a metaphysical musing...)

                                          modified on Thursday, November 4, 2010 6:37 AM

                                          D Offline
                                          D Offline
                                          dpminusa
                                          wrote on last edited by
                                          #27

                                          Your algorithm finds the nth prime with reasonable speed. If you eliminate the (1 + (24 * N))^.5 that are not integers the calculation is almost trivial. This could be very useful in cryptographic and password gen. apps.

                                          "Coding for fun and profit ... mostly fun"

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