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  3. Question about general equation for a line in 3d [modified]

Question about general equation for a line in 3d [modified]

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  • A AspDotNetDev

    So, a 3D version of y = mx + b?

    y = mx + Mz + b

    Note that m and M are just constants that may not have the same meaning as m in the original equation. Also note that I didn't understand a word you said, so I could be completely off base.

    [WikiLeaks Cablegate Cables]

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    Luc Pattyn
    wrote on last edited by
    #7

    Nope, that would be a plane, as for every pair (x,z) you get a y-value. :)

    Luc Pattyn [Forum Guidelines] [My Articles] Nil Volentibus Arduum

    Please use <PRE> tags for code snippets, they preserve indentation, improve readability, and make me actually look at the code.

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    • D DaveAuld

      whoooooooosh![^] [sound of that rapidly flying right over my head, in case youtube not working for you!]

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      Luc Pattyn
      wrote on last edited by
      #8

      landing gear inspection? :)

      Luc Pattyn [Forum Guidelines] [My Articles] Nil Volentibus Arduum

      Please use <PRE> tags for code snippets, they preserve indentation, improve readability, and make me actually look at the code.

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      • L Luc Pattyn

        landing gear inspection? :)

        Luc Pattyn [Forum Guidelines] [My Articles] Nil Volentibus Arduum

        Please use <PRE> tags for code snippets, they preserve indentation, improve readability, and make me actually look at the code.

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        DaveAuld
        wrote on last edited by
        #9

        so thats not the plane he's on about travelling from point a to b to c then.......... :rolleyes:

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        • D DaveAuld

          so thats not the plane he's on about travelling from point a to b to c then.......... :rolleyes:

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          Luc Pattyn
          wrote on last edited by
          #10

          No, mathematical planes are infinite; maybe slower than yours, but a lot bigger. :)

          Luc Pattyn [Forum Guidelines] [My Articles] Nil Volentibus Arduum

          Please use <PRE> tags for code snippets, they preserve indentation, improve readability, and make me actually look at the code.

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          • G GAMerritt

            Someone was asking about that a while back: Why is there no scalar equation for a line in three dimensions ? http://www.physicsforums.com/showthread.php?t=165472[^] I think the R-difference (from R3 to R1) in dimensionality accounts for it. That's why there's no form analogous to Ax + By + C that includes a z-coefficient. Any ideas ? The only equation that might come close to fitting the bill is this one: Ax2 + Bxy + Cy2 + Dx + Ey + F = 0 If B2 - 4AC is zero this equation might represent a line, or two lines if less than zero. But this requires a section by a plane of a conic surface; and although it's a scalar equation, it still isn't linear; so I don't think it's suitable.

            modified on Monday, March 14, 2011 5:09 PM

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            Iain Clarke Warrior Programmer
            wrote on last edited by
            #11

            GAMerritt wrote:

            Why is there no scalar equation for a line in three dimensions ?

            I'm thinking you have the question back to front. Let's pretend a 1D universe. Then you have this equation:

            ax = d

            aka, in a 1D world, a scalar equation defines a point, or 0D object. In a 2D universe, you get this equation:

            ax + by = d

            aka, in a 2D world, a scalar equation defines a line, or 1D object. In a 3D universe, you get this equation:

            ax + by + cz= d

            aka, in a 3D world, a scalar equation defines a plane, or 2D object. To extrapolate... Σ(1->n) coeff [n] * axis [n] = d give an n-1 dimensional object. We just happen to have names for the previous things. I have no idea what you'd call a 3d scalar object in a 4d world. A hyper-plane? I hope that made some sense. Knowing how these things work, some italian mathematician will have written this all much more nicely and elegantly four hundred years ago. Iain. [Modified to fix typo - twice]

            I am one of "those foreigners coming over here and stealing our jobs". Yay me!

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            • I Iain Clarke Warrior Programmer

              GAMerritt wrote:

              Why is there no scalar equation for a line in three dimensions ?

              I'm thinking you have the question back to front. Let's pretend a 1D universe. Then you have this equation:

              ax = d

              aka, in a 1D world, a scalar equation defines a point, or 0D object. In a 2D universe, you get this equation:

              ax + by = d

              aka, in a 2D world, a scalar equation defines a line, or 1D object. In a 3D universe, you get this equation:

              ax + by + cz= d

              aka, in a 3D world, a scalar equation defines a plane, or 2D object. To extrapolate... Σ(1->n) coeff [n] * axis [n] = d give an n-1 dimensional object. We just happen to have names for the previous things. I have no idea what you'd call a 3d scalar object in a 4d world. A hyper-plane? I hope that made some sense. Knowing how these things work, some italian mathematician will have written this all much more nicely and elegantly four hundred years ago. Iain. [Modified to fix typo - twice]

              I am one of "those foreigners coming over here and stealing our jobs". Yay me!

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              TheGreatAndPowerfulOz
              wrote on last edited by
              #12

              Iain Clarke, Warrior Programmer wrote:

              ax + by + cy= d

              did you mean ax + by + cz = d?

              "If your actions inspire others to dream more, learn more, do more and become more, you are a leader." - John Quincy Adams "Let me get this straight. You know her. She knows you. But she wants to eat him. And everybody's okay with this?" - Timon

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              • I Iain Clarke Warrior Programmer

                GAMerritt wrote:

                Why is there no scalar equation for a line in three dimensions ?

                I'm thinking you have the question back to front. Let's pretend a 1D universe. Then you have this equation:

                ax = d

                aka, in a 1D world, a scalar equation defines a point, or 0D object. In a 2D universe, you get this equation:

                ax + by = d

                aka, in a 2D world, a scalar equation defines a line, or 1D object. In a 3D universe, you get this equation:

                ax + by + cz= d

                aka, in a 3D world, a scalar equation defines a plane, or 2D object. To extrapolate... Σ(1->n) coeff [n] * axis [n] = d give an n-1 dimensional object. We just happen to have names for the previous things. I have no idea what you'd call a 3d scalar object in a 4d world. A hyper-plane? I hope that made some sense. Knowing how these things work, some italian mathematician will have written this all much more nicely and elegantly four hundred years ago. Iain. [Modified to fix typo - twice]

                I am one of "those foreigners coming over here and stealing our jobs". Yay me!

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                Soulus83
                wrote on last edited by
                #13

                Iain Clarke, Warrior Programmer wrote:

                ax + by + cyz= d

                I suppose the number of dimensions is proportionally direct to the number of variables in a scalar equation XD

                Iain Clarke, Warrior Programmer wrote:

                I am one of "those foreigners coming over here and stealing our jobs". Yay me!

                Then we are two! :-D

                "Whether you think you can, or you think you can't--either way, you are right." — Henry Ford

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                • T TheGreatAndPowerfulOz

                  Iain Clarke, Warrior Programmer wrote:

                  ax + by + cy= d

                  did you mean ax + by + cz = d?

                  "If your actions inspire others to dream more, learn more, do more and become more, you are a leader." - John Quincy Adams "Let me get this straight. You know her. She knows you. But she wants to eat him. And everybody's okay with this?" - Timon

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                  Iain Clarke Warrior Programmer
                  wrote on last edited by
                  #14

                  ahmed zahmed wrote:

                  did you mean ax + by + cz = d?

                  It is possible, I suppose...

                  I am one of "those foreigners coming over here and stealing our jobs". Yay me!

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                  • I Iain Clarke Warrior Programmer

                    GAMerritt wrote:

                    Why is there no scalar equation for a line in three dimensions ?

                    I'm thinking you have the question back to front. Let's pretend a 1D universe. Then you have this equation:

                    ax = d

                    aka, in a 1D world, a scalar equation defines a point, or 0D object. In a 2D universe, you get this equation:

                    ax + by = d

                    aka, in a 2D world, a scalar equation defines a line, or 1D object. In a 3D universe, you get this equation:

                    ax + by + cz= d

                    aka, in a 3D world, a scalar equation defines a plane, or 2D object. To extrapolate... Σ(1->n) coeff [n] * axis [n] = d give an n-1 dimensional object. We just happen to have names for the previous things. I have no idea what you'd call a 3d scalar object in a 4d world. A hyper-plane? I hope that made some sense. Knowing how these things work, some italian mathematician will have written this all much more nicely and elegantly four hundred years ago. Iain. [Modified to fix typo - twice]

                    I am one of "those foreigners coming over here and stealing our jobs". Yay me!

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                    Lost User
                    wrote on last edited by
                    #15

                    Iain Clarke, Warrior Programmer wrote:

                    ax + by + cz= d

                    That's the equation for a plane. A line in 3 dimensions is the intersection of two planes. Cheers, Drew.

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                    • G GAMerritt

                      Someone was asking about that a while back: Why is there no scalar equation for a line in three dimensions ? http://www.physicsforums.com/showthread.php?t=165472[^] I think the R-difference (from R3 to R1) in dimensionality accounts for it. That's why there's no form analogous to Ax + By + C that includes a z-coefficient. Any ideas ? The only equation that might come close to fitting the bill is this one: Ax2 + Bxy + Cy2 + Dx + Ey + F = 0 If B2 - 4AC is zero this equation might represent a line, or two lines if less than zero. But this requires a section by a plane of a conic surface; and although it's a scalar equation, it still isn't linear; so I don't think it's suitable.

                      modified on Monday, March 14, 2011 5:09 PM

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                      Super Lloyd
                      wrote on last edited by
                      #16

                      the linear equation is, in "geometric term" OA . OM = 0 where OA is your line vector and M a point in the plane in 3D I guess you can try | OA ^ OM | = 0 So if AO = (a, b, c) and OM = (x, y, z) something along the lines of (IIR, might have some sign error) | (bz - cy, cx - az, ay - bx ) | = 0 (bz - cy)^2 + (cx - az)^2 + (ay -bx)^2 = 0

                      A train station is where the train stops. A bus station is where the bus stops. On my desk, I have a work station.... _________________________________________________________ My programs never have bugs, they just develop random features.

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                      • L Lost User

                        Iain Clarke, Warrior Programmer wrote:

                        ax + by + cz= d

                        That's the equation for a plane. A line in 3 dimensions is the intersection of two planes. Cheers, Drew.

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                        Iain Clarke Warrior Programmer
                        wrote on last edited by
                        #17

                        You are right, I did miswrite it. I do know it's a plane - that was kind of the central thesis. Seems I should not try to be deep near bedtime! Iain.

                        I am one of "those foreigners coming over here and stealing our jobs". Yay me!

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