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  4. May be bad code or May not be!!!

May be bad code or May not be!!!

Scheduled Pinned Locked Moved The Weird and The Wonderful
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  • D Daniel Scott

    If equality is transitive (and I really hope it is), it can indeed never execute DoABC. Given A == B and B == C, it follows from transitivity that A == C, so A != C must be false.

    L Offline
    L Offline
    Luc Pattyn
    wrote on last edited by
    #7

    Under normal circumstances equality is transitive; but it also isn't permanent... :)

    Luc Pattyn [Forum Guidelines] [My Articles] Nil Volentibus Arduum

    Please use <PRE> tags for code snippets, they preserve indentation, improve readability, and make me actually look at the code.

    L 1 Reply Last reply
    0
    • R Ravi Sant

      Just saw this code at work:

      if( A==B )
      {
      if( B==C && A!=C)
      {
      DoABC();
      }
      else
      {
      DoWork();
      }
      }
      else if (C==A || C == B)
      {
      DoWork();
      }

      I have examined, tested over and over, but code never goes or will go to DoABC();

      // ♫ 99 little bugs in the code, // 99 bugs in the code // We fix a bug, compile it again // 101 little bugs in the code ♫

      L Offline
      L Offline
      Luc Pattyn
      wrote on last edited by
      #8

      You didn't tell us what types A, B, C are. They could be some type with the == operator overloaded by something counter-intuitive. They could also be just stupid integers, stored globally, marked volatile, and changing occasionally... So, yes it looks weird, it probably is a mistake, and OTOH it could function as intended and just be a case of bad, hardly readable, code. :)

      Luc Pattyn [Forum Guidelines] [My Articles] Nil Volentibus Arduum

      Please use <PRE> tags for code snippets, they preserve indentation, improve readability, and make me actually look at the code.

      R 1 Reply Last reply
      0
      • R Ravi Sant

        Just saw this code at work:

        if( A==B )
        {
        if( B==C && A!=C)
        {
        DoABC();
        }
        else
        {
        DoWork();
        }
        }
        else if (C==A || C == B)
        {
        DoWork();
        }

        I have examined, tested over and over, but code never goes or will go to DoABC();

        // ♫ 99 little bugs in the code, // 99 bugs in the code // We fix a bug, compile it again // 101 little bugs in the code ♫

        N Offline
        N Offline
        Narf the Mouse
        wrote on last edited by
        #9

        My Snark Detector is going off.

        1 Reply Last reply
        0
        • L Luc Pattyn

          You didn't tell us what types A, B, C are. They could be some type with the == operator overloaded by something counter-intuitive. They could also be just stupid integers, stored globally, marked volatile, and changing occasionally... So, yes it looks weird, it probably is a mistake, and OTOH it could function as intended and just be a case of bad, hardly readable, code. :)

          Luc Pattyn [Forum Guidelines] [My Articles] Nil Volentibus Arduum

          Please use <PRE> tags for code snippets, they preserve indentation, improve readability, and make me actually look at the code.

          R Offline
          R Offline
          Ravi Sant
          wrote on last edited by
          #10

          they are string(s) :)

          // ♫ 99 little bugs in the code, // 99 bugs in the code // We fix a bug, compile it again // 101 little bugs in the code ♫

          M 1 Reply Last reply
          0
          • M musefan

            I assume the data types for A, B and C are something basic? With custom operator overloads you could get to DoABC() using the above logic if you really wanted to. But I think you would need to have different data types

            I may or may not be responsible for my own actions

            R Offline
            R Offline
            Ravi Sant
            wrote on last edited by
            #11

            Yes they are string(s) and now i thing to replace this code with just one line DoWork();

            // ♫ 99 little bugs in the code, // 99 bugs in the code // We fix a bug, compile it again // 101 little bugs in the code ♫

            Richard DeemingR 1 Reply Last reply
            0
            • R Ravi Sant

              they are string(s) :)

              // ♫ 99 little bugs in the code, // 99 bugs in the code // We fix a bug, compile it again // 101 little bugs in the code ♫

              M Offline
              M Offline
              mahendren
              wrote on last edited by
              #12

              Your tag line is classic :) 101 little bugs in the code ♫

              R 1 Reply Last reply
              0
              • M mahendren

                Your tag line is classic :) 101 little bugs in the code ♫

                R Offline
                R Offline
                Ravi Sant
                wrote on last edited by
                #13

                ♫ Thanks ♫

                // ♫ 99 little bugs in the code, // 99 bugs in the code // We fix a bug, compile it again // 101 little bugs in the code ♫

                1 Reply Last reply
                0
                • R Ravi Sant

                  Just saw this code at work:

                  if( A==B )
                  {
                  if( B==C && A!=C)
                  {
                  DoABC();
                  }
                  else
                  {
                  DoWork();
                  }
                  }
                  else if (C==A || C == B)
                  {
                  DoWork();
                  }

                  I have examined, tested over and over, but code never goes or will go to DoABC();

                  // ♫ 99 little bugs in the code, // 99 bugs in the code // We fix a bug, compile it again // 101 little bugs in the code ♫

                  R Offline
                  R Offline
                  R Erasmus
                  wrote on last edited by
                  #14

                  No matter how hard I try to find the good in this piece of code, I just can't, I'm sorry. 1st bug: meaningless variable names 2nd bug: No '()' to indicate and clarify precedence 3rd bug: Dead code

                  "Program testing can be used to show the presence of bugs, but never to show their absence." << please vote!! >>

                  R 1 Reply Last reply
                  0
                  • R R Erasmus

                    No matter how hard I try to find the good in this piece of code, I just can't, I'm sorry. 1st bug: meaningless variable names 2nd bug: No '()' to indicate and clarify precedence 3rd bug: Dead code

                    "Program testing can be used to show the presence of bugs, but never to show their absence." << please vote!! >>

                    R Offline
                    R Offline
                    Ravi Sant
                    wrote on last edited by
                    #15

                    yes, 1st is not bug, I did it purposely to hide actual busines variables. 2& 3 surely bad.

                    // ♫ 99 little bugs in the code, // 99 bugs in the code // We fix a bug, compile it again // 101 little bugs in the code ♫

                    R 1 Reply Last reply
                    0
                    • R Ravi Sant

                      yes, 1st is not bug, I did it purposely to hide actual busines variables. 2& 3 surely bad.

                      // ♫ 99 little bugs in the code, // 99 bugs in the code // We fix a bug, compile it again // 101 little bugs in the code ♫

                      R Offline
                      R Offline
                      R Erasmus
                      wrote on last edited by
                      #16

                      I guest that much. ;-)

                      "Program testing can be used to show the presence of bugs, but never to show their absence." << please vote!! >>

                      R D 2 Replies Last reply
                      0
                      • R R Erasmus

                        I guest that much. ;-)

                        "Program testing can be used to show the presence of bugs, but never to show their absence." << please vote!! >>

                        R Offline
                        R Offline
                        Ravi Sant
                        wrote on last edited by
                        #17

                        Thanks :)

                        // ♫ 99 little bugs in the code, // 99 bugs in the code // We fix a bug, compile it again // 101 little bugs in the code ♫

                        1 Reply Last reply
                        0
                        • R Ravi Sant

                          Just saw this code at work:

                          if( A==B )
                          {
                          if( B==C && A!=C)
                          {
                          DoABC();
                          }
                          else
                          {
                          DoWork();
                          }
                          }
                          else if (C==A || C == B)
                          {
                          DoWork();
                          }

                          I have examined, tested over and over, but code never goes or will go to DoABC();

                          // ♫ 99 little bugs in the code, // 99 bugs in the code // We fix a bug, compile it again // 101 little bugs in the code ♫

                          S Offline
                          S Offline
                          Stefan_Lang
                          wrote on last edited by
                          #18

                          Looks like a test to see if operator==() has been implemented correctly for whatever class the variables A, B, and C are instances of. DoABC() will only be called, if operator==() does not fulfil transitivity. Of course, there is one error: it should be !A==C instead of A!=C, otherwise we cannot be sure there is an error in operator!=(). ;) Yeah, right... ;P

                          R 1 Reply Last reply
                          0
                          • S Stefan_Lang

                            Looks like a test to see if operator==() has been implemented correctly for whatever class the variables A, B, and C are instances of. DoABC() will only be called, if operator==() does not fulfil transitivity. Of course, there is one error: it should be !A==C instead of A!=C, otherwise we cannot be sure there is an error in operator!=(). ;) Yeah, right... ;P

                            R Offline
                            R Offline
                            Ravi Sant
                            wrote on last edited by
                            #19

                            lol. Have 5 for the humor :laugh: :laugh:

                            // ♫ 99 little bugs in the code, // 99 bugs in the code // We fix a bug, compile it again // 101 little bugs in the code ♫

                            1 Reply Last reply
                            0
                            • R Ravi Sant

                              Just saw this code at work:

                              if( A==B )
                              {
                              if( B==C && A!=C)
                              {
                              DoABC();
                              }
                              else
                              {
                              DoWork();
                              }
                              }
                              else if (C==A || C == B)
                              {
                              DoWork();
                              }

                              I have examined, tested over and over, but code never goes or will go to DoABC();

                              // ♫ 99 little bugs in the code, // 99 bugs in the code // We fix a bug, compile it again // 101 little bugs in the code ♫

                              W Offline
                              W Offline
                              whiteclouds
                              wrote on last edited by
                              #20

                              Funny! I think if you want this code work as your meaning, you should override the operator "==", or you convey it into other language such as C#.

                              There is some white cloud floating on the blue sky. That's the landscape I like.

                              1 Reply Last reply
                              0
                              • R Ravi Sant

                                Yes they are string(s) and now i thing to replace this code with just one line DoWork();

                                // ♫ 99 little bugs in the code, // 99 bugs in the code // We fix a bug, compile it again // 101 little bugs in the code ♫

                                Richard DeemingR Offline
                                Richard DeemingR Offline
                                Richard Deeming
                                wrote on last edited by
                                #21

                                Ravi Sant wrote:

                                replace this code with just one line DoWork();

                                But what if A != B && A != C && B != C? The original code won't execute DoWork in that case.


                                "These people looked deep within my soul and assigned me a number based on the order in which I joined." - Homer

                                "These people looked deep within my soul and assigned me a number based on the order in which I joined" - Homer

                                R 1 Reply Last reply
                                0
                                • Richard DeemingR Richard Deeming

                                  Ravi Sant wrote:

                                  replace this code with just one line DoWork();

                                  But what if A != B && A != C && B != C? The original code won't execute DoWork in that case.


                                  "These people looked deep within my soul and assigned me a number based on the order in which I joined." - Homer

                                  R Offline
                                  R Offline
                                  Ravi Sant
                                  wrote on last edited by
                                  #22

                                  Good Point .. :)

                                  // ♫ 99 little bugs in the code, // 99 bugs in the code // We fix a bug, compile it again // 101 little bugs in the code ♫

                                  1 Reply Last reply
                                  0
                                  • R Ravi Sant

                                    Just saw this code at work:

                                    if( A==B )
                                    {
                                    if( B==C && A!=C)
                                    {
                                    DoABC();
                                    }
                                    else
                                    {
                                    DoWork();
                                    }
                                    }
                                    else if (C==A || C == B)
                                    {
                                    DoWork();
                                    }

                                    I have examined, tested over and over, but code never goes or will go to DoABC();

                                    // ♫ 99 little bugs in the code, // 99 bugs in the code // We fix a bug, compile it again // 101 little bugs in the code ♫

                                    K Offline
                                    K Offline
                                    Kent K
                                    wrote on last edited by
                                    #23

                                    The only minute possibility of it being useful perhaps, is if there are multiple threads involved. . .and maybe if it is the case that A is static or something. . . .that if there was a CPU context switch between the lines if( A==B ) and if( B==C && A!=C) ...where A gets changed by another thread therefore the programmer had been trying to be uber careful about running DoABC(). . . . .??

                                    1 Reply Last reply
                                    0
                                    • D Daniel Scott

                                      If equality is transitive (and I really hope it is), it can indeed never execute DoABC. Given A == B and B == C, it follows from transitivity that A == C, so A != C must be false.

                                      A Offline
                                      A Offline
                                      agolddog
                                      wrote on last edited by
                                      #24

                                      Don't forget, in at least some languages, you're allowed to override operators. So A's == may not be the same as B's. That might be a path to DoABC. In the absence of that, though, what he said. In the presence of that, that's a whole other kind of bad development.

                                      1 Reply Last reply
                                      0
                                      • R Ravi Sant

                                        Just saw this code at work:

                                        if( A==B )
                                        {
                                        if( B==C && A!=C)
                                        {
                                        DoABC();
                                        }
                                        else
                                        {
                                        DoWork();
                                        }
                                        }
                                        else if (C==A || C == B)
                                        {
                                        DoWork();
                                        }

                                        I have examined, tested over and over, but code never goes or will go to DoABC();

                                        // ♫ 99 little bugs in the code, // 99 bugs in the code // We fix a bug, compile it again // 101 little bugs in the code ♫

                                        F Offline
                                        F Offline
                                        frattaro
                                        wrote on last edited by
                                        #25

                                        Are A, B and C all different object types that equate differently?

                                        1 Reply Last reply
                                        0
                                        • R R Erasmus

                                          I guest that much. ;-)

                                          "Program testing can be used to show the presence of bugs, but never to show their absence." << please vote!! >>

                                          D Offline
                                          D Offline
                                          DragonsRightWing
                                          wrote on last edited by
                                          #26

                                          R. Erasmus wrote:

                                          I guest that much.

                                          Did you guest anonymously? - Oh, sorry - the bad-English-and-spelling thread was yesterday ... ;)

                                          1 Reply Last reply
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