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  4. May be bad code or May not be!!!

May be bad code or May not be!!!

Scheduled Pinned Locked Moved The Weird and The Wonderful
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  • R Ravi Sant

    Just saw this code at work:

    if( A==B )
    {
    if( B==C && A!=C)
    {
    DoABC();
    }
    else
    {
    DoWork();
    }
    }
    else if (C==A || C == B)
    {
    DoWork();
    }

    I have examined, tested over and over, but code never goes or will go to DoABC();

    // ♫ 99 little bugs in the code, // 99 bugs in the code // We fix a bug, compile it again // 101 little bugs in the code ♫

    L Offline
    L Offline
    Luc Pattyn
    wrote on last edited by
    #8

    You didn't tell us what types A, B, C are. They could be some type with the == operator overloaded by something counter-intuitive. They could also be just stupid integers, stored globally, marked volatile, and changing occasionally... So, yes it looks weird, it probably is a mistake, and OTOH it could function as intended and just be a case of bad, hardly readable, code. :)

    Luc Pattyn [Forum Guidelines] [My Articles] Nil Volentibus Arduum

    Please use <PRE> tags for code snippets, they preserve indentation, improve readability, and make me actually look at the code.

    R 1 Reply Last reply
    0
    • R Ravi Sant

      Just saw this code at work:

      if( A==B )
      {
      if( B==C && A!=C)
      {
      DoABC();
      }
      else
      {
      DoWork();
      }
      }
      else if (C==A || C == B)
      {
      DoWork();
      }

      I have examined, tested over and over, but code never goes or will go to DoABC();

      // ♫ 99 little bugs in the code, // 99 bugs in the code // We fix a bug, compile it again // 101 little bugs in the code ♫

      N Offline
      N Offline
      Narf the Mouse
      wrote on last edited by
      #9

      My Snark Detector is going off.

      1 Reply Last reply
      0
      • L Luc Pattyn

        You didn't tell us what types A, B, C are. They could be some type with the == operator overloaded by something counter-intuitive. They could also be just stupid integers, stored globally, marked volatile, and changing occasionally... So, yes it looks weird, it probably is a mistake, and OTOH it could function as intended and just be a case of bad, hardly readable, code. :)

        Luc Pattyn [Forum Guidelines] [My Articles] Nil Volentibus Arduum

        Please use <PRE> tags for code snippets, they preserve indentation, improve readability, and make me actually look at the code.

        R Offline
        R Offline
        Ravi Sant
        wrote on last edited by
        #10

        they are string(s) :)

        // ♫ 99 little bugs in the code, // 99 bugs in the code // We fix a bug, compile it again // 101 little bugs in the code ♫

        M 1 Reply Last reply
        0
        • M musefan

          I assume the data types for A, B and C are something basic? With custom operator overloads you could get to DoABC() using the above logic if you really wanted to. But I think you would need to have different data types

          I may or may not be responsible for my own actions

          R Offline
          R Offline
          Ravi Sant
          wrote on last edited by
          #11

          Yes they are string(s) and now i thing to replace this code with just one line DoWork();

          // ♫ 99 little bugs in the code, // 99 bugs in the code // We fix a bug, compile it again // 101 little bugs in the code ♫

          Richard DeemingR 1 Reply Last reply
          0
          • R Ravi Sant

            they are string(s) :)

            // ♫ 99 little bugs in the code, // 99 bugs in the code // We fix a bug, compile it again // 101 little bugs in the code ♫

            M Offline
            M Offline
            mahendren
            wrote on last edited by
            #12

            Your tag line is classic :) 101 little bugs in the code ♫

            R 1 Reply Last reply
            0
            • M mahendren

              Your tag line is classic :) 101 little bugs in the code ♫

              R Offline
              R Offline
              Ravi Sant
              wrote on last edited by
              #13

              ♫ Thanks ♫

              // ♫ 99 little bugs in the code, // 99 bugs in the code // We fix a bug, compile it again // 101 little bugs in the code ♫

              1 Reply Last reply
              0
              • R Ravi Sant

                Just saw this code at work:

                if( A==B )
                {
                if( B==C && A!=C)
                {
                DoABC();
                }
                else
                {
                DoWork();
                }
                }
                else if (C==A || C == B)
                {
                DoWork();
                }

                I have examined, tested over and over, but code never goes or will go to DoABC();

                // ♫ 99 little bugs in the code, // 99 bugs in the code // We fix a bug, compile it again // 101 little bugs in the code ♫

                R Offline
                R Offline
                R Erasmus
                wrote on last edited by
                #14

                No matter how hard I try to find the good in this piece of code, I just can't, I'm sorry. 1st bug: meaningless variable names 2nd bug: No '()' to indicate and clarify precedence 3rd bug: Dead code

                "Program testing can be used to show the presence of bugs, but never to show their absence." << please vote!! >>

                R 1 Reply Last reply
                0
                • R R Erasmus

                  No matter how hard I try to find the good in this piece of code, I just can't, I'm sorry. 1st bug: meaningless variable names 2nd bug: No '()' to indicate and clarify precedence 3rd bug: Dead code

                  "Program testing can be used to show the presence of bugs, but never to show their absence." << please vote!! >>

                  R Offline
                  R Offline
                  Ravi Sant
                  wrote on last edited by
                  #15

                  yes, 1st is not bug, I did it purposely to hide actual busines variables. 2& 3 surely bad.

                  // ♫ 99 little bugs in the code, // 99 bugs in the code // We fix a bug, compile it again // 101 little bugs in the code ♫

                  R 1 Reply Last reply
                  0
                  • R Ravi Sant

                    yes, 1st is not bug, I did it purposely to hide actual busines variables. 2& 3 surely bad.

                    // ♫ 99 little bugs in the code, // 99 bugs in the code // We fix a bug, compile it again // 101 little bugs in the code ♫

                    R Offline
                    R Offline
                    R Erasmus
                    wrote on last edited by
                    #16

                    I guest that much. ;-)

                    "Program testing can be used to show the presence of bugs, but never to show their absence." << please vote!! >>

                    R D 2 Replies Last reply
                    0
                    • R R Erasmus

                      I guest that much. ;-)

                      "Program testing can be used to show the presence of bugs, but never to show their absence." << please vote!! >>

                      R Offline
                      R Offline
                      Ravi Sant
                      wrote on last edited by
                      #17

                      Thanks :)

                      // ♫ 99 little bugs in the code, // 99 bugs in the code // We fix a bug, compile it again // 101 little bugs in the code ♫

                      1 Reply Last reply
                      0
                      • R Ravi Sant

                        Just saw this code at work:

                        if( A==B )
                        {
                        if( B==C && A!=C)
                        {
                        DoABC();
                        }
                        else
                        {
                        DoWork();
                        }
                        }
                        else if (C==A || C == B)
                        {
                        DoWork();
                        }

                        I have examined, tested over and over, but code never goes or will go to DoABC();

                        // ♫ 99 little bugs in the code, // 99 bugs in the code // We fix a bug, compile it again // 101 little bugs in the code ♫

                        S Offline
                        S Offline
                        Stefan_Lang
                        wrote on last edited by
                        #18

                        Looks like a test to see if operator==() has been implemented correctly for whatever class the variables A, B, and C are instances of. DoABC() will only be called, if operator==() does not fulfil transitivity. Of course, there is one error: it should be !A==C instead of A!=C, otherwise we cannot be sure there is an error in operator!=(). ;) Yeah, right... ;P

                        R 1 Reply Last reply
                        0
                        • S Stefan_Lang

                          Looks like a test to see if operator==() has been implemented correctly for whatever class the variables A, B, and C are instances of. DoABC() will only be called, if operator==() does not fulfil transitivity. Of course, there is one error: it should be !A==C instead of A!=C, otherwise we cannot be sure there is an error in operator!=(). ;) Yeah, right... ;P

                          R Offline
                          R Offline
                          Ravi Sant
                          wrote on last edited by
                          #19

                          lol. Have 5 for the humor :laugh: :laugh:

                          // ♫ 99 little bugs in the code, // 99 bugs in the code // We fix a bug, compile it again // 101 little bugs in the code ♫

                          1 Reply Last reply
                          0
                          • R Ravi Sant

                            Just saw this code at work:

                            if( A==B )
                            {
                            if( B==C && A!=C)
                            {
                            DoABC();
                            }
                            else
                            {
                            DoWork();
                            }
                            }
                            else if (C==A || C == B)
                            {
                            DoWork();
                            }

                            I have examined, tested over and over, but code never goes or will go to DoABC();

                            // ♫ 99 little bugs in the code, // 99 bugs in the code // We fix a bug, compile it again // 101 little bugs in the code ♫

                            W Offline
                            W Offline
                            whiteclouds
                            wrote on last edited by
                            #20

                            Funny! I think if you want this code work as your meaning, you should override the operator "==", or you convey it into other language such as C#.

                            There is some white cloud floating on the blue sky. That's the landscape I like.

                            1 Reply Last reply
                            0
                            • R Ravi Sant

                              Yes they are string(s) and now i thing to replace this code with just one line DoWork();

                              // ♫ 99 little bugs in the code, // 99 bugs in the code // We fix a bug, compile it again // 101 little bugs in the code ♫

                              Richard DeemingR Offline
                              Richard DeemingR Offline
                              Richard Deeming
                              wrote on last edited by
                              #21

                              Ravi Sant wrote:

                              replace this code with just one line DoWork();

                              But what if A != B && A != C && B != C? The original code won't execute DoWork in that case.


                              "These people looked deep within my soul and assigned me a number based on the order in which I joined." - Homer

                              "These people looked deep within my soul and assigned me a number based on the order in which I joined" - Homer

                              R 1 Reply Last reply
                              0
                              • Richard DeemingR Richard Deeming

                                Ravi Sant wrote:

                                replace this code with just one line DoWork();

                                But what if A != B && A != C && B != C? The original code won't execute DoWork in that case.


                                "These people looked deep within my soul and assigned me a number based on the order in which I joined." - Homer

                                R Offline
                                R Offline
                                Ravi Sant
                                wrote on last edited by
                                #22

                                Good Point .. :)

                                // ♫ 99 little bugs in the code, // 99 bugs in the code // We fix a bug, compile it again // 101 little bugs in the code ♫

                                1 Reply Last reply
                                0
                                • R Ravi Sant

                                  Just saw this code at work:

                                  if( A==B )
                                  {
                                  if( B==C && A!=C)
                                  {
                                  DoABC();
                                  }
                                  else
                                  {
                                  DoWork();
                                  }
                                  }
                                  else if (C==A || C == B)
                                  {
                                  DoWork();
                                  }

                                  I have examined, tested over and over, but code never goes or will go to DoABC();

                                  // ♫ 99 little bugs in the code, // 99 bugs in the code // We fix a bug, compile it again // 101 little bugs in the code ♫

                                  K Offline
                                  K Offline
                                  Kent K
                                  wrote on last edited by
                                  #23

                                  The only minute possibility of it being useful perhaps, is if there are multiple threads involved. . .and maybe if it is the case that A is static or something. . . .that if there was a CPU context switch between the lines if( A==B ) and if( B==C && A!=C) ...where A gets changed by another thread therefore the programmer had been trying to be uber careful about running DoABC(). . . . .??

                                  1 Reply Last reply
                                  0
                                  • D Daniel Scott

                                    If equality is transitive (and I really hope it is), it can indeed never execute DoABC. Given A == B and B == C, it follows from transitivity that A == C, so A != C must be false.

                                    A Offline
                                    A Offline
                                    agolddog
                                    wrote on last edited by
                                    #24

                                    Don't forget, in at least some languages, you're allowed to override operators. So A's == may not be the same as B's. That might be a path to DoABC. In the absence of that, though, what he said. In the presence of that, that's a whole other kind of bad development.

                                    1 Reply Last reply
                                    0
                                    • R Ravi Sant

                                      Just saw this code at work:

                                      if( A==B )
                                      {
                                      if( B==C && A!=C)
                                      {
                                      DoABC();
                                      }
                                      else
                                      {
                                      DoWork();
                                      }
                                      }
                                      else if (C==A || C == B)
                                      {
                                      DoWork();
                                      }

                                      I have examined, tested over and over, but code never goes or will go to DoABC();

                                      // ♫ 99 little bugs in the code, // 99 bugs in the code // We fix a bug, compile it again // 101 little bugs in the code ♫

                                      F Offline
                                      F Offline
                                      frattaro
                                      wrote on last edited by
                                      #25

                                      Are A, B and C all different object types that equate differently?

                                      1 Reply Last reply
                                      0
                                      • R R Erasmus

                                        I guest that much. ;-)

                                        "Program testing can be used to show the presence of bugs, but never to show their absence." << please vote!! >>

                                        D Offline
                                        D Offline
                                        DragonsRightWing
                                        wrote on last edited by
                                        #26

                                        R. Erasmus wrote:

                                        I guest that much.

                                        Did you guest anonymously? - Oh, sorry - the bad-English-and-spelling thread was yesterday ... ;)

                                        1 Reply Last reply
                                        0
                                        • L Luc Pattyn

                                          Under normal circumstances equality is transitive; but it also isn't permanent... :)

                                          Luc Pattyn [Forum Guidelines] [My Articles] Nil Volentibus Arduum

                                          Please use <PRE> tags for code snippets, they preserve indentation, improve readability, and make me actually look at the code.

                                          L Offline
                                          L Offline
                                          Lost User
                                          wrote on last edited by
                                          #27

                                          "isn't permanent"? can you explain that?

                                          L 1 Reply Last reply
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