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  4. May be bad code or May not be!!!

May be bad code or May not be!!!

Scheduled Pinned Locked Moved The Weird and The Wonderful
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  • R R Erasmus

    I guest that much. ;-)

    "Program testing can be used to show the presence of bugs, but never to show their absence." << please vote!! >>

    R Offline
    R Offline
    Ravi Sant
    wrote on last edited by
    #17

    Thanks :)

    // ♫ 99 little bugs in the code, // 99 bugs in the code // We fix a bug, compile it again // 101 little bugs in the code ♫

    1 Reply Last reply
    0
    • R Ravi Sant

      Just saw this code at work:

      if( A==B )
      {
      if( B==C && A!=C)
      {
      DoABC();
      }
      else
      {
      DoWork();
      }
      }
      else if (C==A || C == B)
      {
      DoWork();
      }

      I have examined, tested over and over, but code never goes or will go to DoABC();

      // ♫ 99 little bugs in the code, // 99 bugs in the code // We fix a bug, compile it again // 101 little bugs in the code ♫

      S Offline
      S Offline
      Stefan_Lang
      wrote on last edited by
      #18

      Looks like a test to see if operator==() has been implemented correctly for whatever class the variables A, B, and C are instances of. DoABC() will only be called, if operator==() does not fulfil transitivity. Of course, there is one error: it should be !A==C instead of A!=C, otherwise we cannot be sure there is an error in operator!=(). ;) Yeah, right... ;P

      R 1 Reply Last reply
      0
      • S Stefan_Lang

        Looks like a test to see if operator==() has been implemented correctly for whatever class the variables A, B, and C are instances of. DoABC() will only be called, if operator==() does not fulfil transitivity. Of course, there is one error: it should be !A==C instead of A!=C, otherwise we cannot be sure there is an error in operator!=(). ;) Yeah, right... ;P

        R Offline
        R Offline
        Ravi Sant
        wrote on last edited by
        #19

        lol. Have 5 for the humor :laugh: :laugh:

        // ♫ 99 little bugs in the code, // 99 bugs in the code // We fix a bug, compile it again // 101 little bugs in the code ♫

        1 Reply Last reply
        0
        • R Ravi Sant

          Just saw this code at work:

          if( A==B )
          {
          if( B==C && A!=C)
          {
          DoABC();
          }
          else
          {
          DoWork();
          }
          }
          else if (C==A || C == B)
          {
          DoWork();
          }

          I have examined, tested over and over, but code never goes or will go to DoABC();

          // ♫ 99 little bugs in the code, // 99 bugs in the code // We fix a bug, compile it again // 101 little bugs in the code ♫

          W Offline
          W Offline
          whiteclouds
          wrote on last edited by
          #20

          Funny! I think if you want this code work as your meaning, you should override the operator "==", or you convey it into other language such as C#.

          There is some white cloud floating on the blue sky. That's the landscape I like.

          1 Reply Last reply
          0
          • R Ravi Sant

            Yes they are string(s) and now i thing to replace this code with just one line DoWork();

            // ♫ 99 little bugs in the code, // 99 bugs in the code // We fix a bug, compile it again // 101 little bugs in the code ♫

            Richard DeemingR Offline
            Richard DeemingR Offline
            Richard Deeming
            wrote on last edited by
            #21

            Ravi Sant wrote:

            replace this code with just one line DoWork();

            But what if A != B && A != C && B != C? The original code won't execute DoWork in that case.


            "These people looked deep within my soul and assigned me a number based on the order in which I joined." - Homer

            "These people looked deep within my soul and assigned me a number based on the order in which I joined" - Homer

            R 1 Reply Last reply
            0
            • Richard DeemingR Richard Deeming

              Ravi Sant wrote:

              replace this code with just one line DoWork();

              But what if A != B && A != C && B != C? The original code won't execute DoWork in that case.


              "These people looked deep within my soul and assigned me a number based on the order in which I joined." - Homer

              R Offline
              R Offline
              Ravi Sant
              wrote on last edited by
              #22

              Good Point .. :)

              // ♫ 99 little bugs in the code, // 99 bugs in the code // We fix a bug, compile it again // 101 little bugs in the code ♫

              1 Reply Last reply
              0
              • R Ravi Sant

                Just saw this code at work:

                if( A==B )
                {
                if( B==C && A!=C)
                {
                DoABC();
                }
                else
                {
                DoWork();
                }
                }
                else if (C==A || C == B)
                {
                DoWork();
                }

                I have examined, tested over and over, but code never goes or will go to DoABC();

                // ♫ 99 little bugs in the code, // 99 bugs in the code // We fix a bug, compile it again // 101 little bugs in the code ♫

                K Offline
                K Offline
                Kent K
                wrote on last edited by
                #23

                The only minute possibility of it being useful perhaps, is if there are multiple threads involved. . .and maybe if it is the case that A is static or something. . . .that if there was a CPU context switch between the lines if( A==B ) and if( B==C && A!=C) ...where A gets changed by another thread therefore the programmer had been trying to be uber careful about running DoABC(). . . . .??

                1 Reply Last reply
                0
                • D Daniel Scott

                  If equality is transitive (and I really hope it is), it can indeed never execute DoABC. Given A == B and B == C, it follows from transitivity that A == C, so A != C must be false.

                  A Offline
                  A Offline
                  agolddog
                  wrote on last edited by
                  #24

                  Don't forget, in at least some languages, you're allowed to override operators. So A's == may not be the same as B's. That might be a path to DoABC. In the absence of that, though, what he said. In the presence of that, that's a whole other kind of bad development.

                  1 Reply Last reply
                  0
                  • R Ravi Sant

                    Just saw this code at work:

                    if( A==B )
                    {
                    if( B==C && A!=C)
                    {
                    DoABC();
                    }
                    else
                    {
                    DoWork();
                    }
                    }
                    else if (C==A || C == B)
                    {
                    DoWork();
                    }

                    I have examined, tested over and over, but code never goes or will go to DoABC();

                    // ♫ 99 little bugs in the code, // 99 bugs in the code // We fix a bug, compile it again // 101 little bugs in the code ♫

                    F Offline
                    F Offline
                    frattaro
                    wrote on last edited by
                    #25

                    Are A, B and C all different object types that equate differently?

                    1 Reply Last reply
                    0
                    • R R Erasmus

                      I guest that much. ;-)

                      "Program testing can be used to show the presence of bugs, but never to show their absence." << please vote!! >>

                      D Offline
                      D Offline
                      DragonsRightWing
                      wrote on last edited by
                      #26

                      R. Erasmus wrote:

                      I guest that much.

                      Did you guest anonymously? - Oh, sorry - the bad-English-and-spelling thread was yesterday ... ;)

                      1 Reply Last reply
                      0
                      • L Luc Pattyn

                        Under normal circumstances equality is transitive; but it also isn't permanent... :)

                        Luc Pattyn [Forum Guidelines] [My Articles] Nil Volentibus Arduum

                        Please use <PRE> tags for code snippets, they preserve indentation, improve readability, and make me actually look at the code.

                        L Offline
                        L Offline
                        Lost User
                        wrote on last edited by
                        #27

                        "isn't permanent"? can you explain that?

                        L 1 Reply Last reply
                        0
                        • L Lost User

                          "isn't permanent"? can you explain that?

                          L Offline
                          L Offline
                          Luc Pattyn
                          wrote on last edited by
                          #28

                          The variables A, B, C may be equal at some point in time, they also are variables, hence their value can change. See also here[^]. :)

                          Luc Pattyn [Forum Guidelines] [My Articles] Nil Volentibus Arduum

                          Please use <PRE> tags for code snippets, they preserve indentation, improve readability, and make me actually look at the code.

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