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  4. May be bad code or May not be!!!

May be bad code or May not be!!!

Scheduled Pinned Locked Moved The Weird and The Wonderful
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  • R Ravi Sant

    Just saw this code at work:

    if( A==B )
    {
    if( B==C && A!=C)
    {
    DoABC();
    }
    else
    {
    DoWork();
    }
    }
    else if (C==A || C == B)
    {
    DoWork();
    }

    I have examined, tested over and over, but code never goes or will go to DoABC();

    // ♫ 99 little bugs in the code, // 99 bugs in the code // We fix a bug, compile it again // 101 little bugs in the code ♫

    S Offline
    S Offline
    Stefan_Lang
    wrote on last edited by
    #18

    Looks like a test to see if operator==() has been implemented correctly for whatever class the variables A, B, and C are instances of. DoABC() will only be called, if operator==() does not fulfil transitivity. Of course, there is one error: it should be !A==C instead of A!=C, otherwise we cannot be sure there is an error in operator!=(). ;) Yeah, right... ;P

    R 1 Reply Last reply
    0
    • S Stefan_Lang

      Looks like a test to see if operator==() has been implemented correctly for whatever class the variables A, B, and C are instances of. DoABC() will only be called, if operator==() does not fulfil transitivity. Of course, there is one error: it should be !A==C instead of A!=C, otherwise we cannot be sure there is an error in operator!=(). ;) Yeah, right... ;P

      R Offline
      R Offline
      Ravi Sant
      wrote on last edited by
      #19

      lol. Have 5 for the humor :laugh: :laugh:

      // ♫ 99 little bugs in the code, // 99 bugs in the code // We fix a bug, compile it again // 101 little bugs in the code ♫

      1 Reply Last reply
      0
      • R Ravi Sant

        Just saw this code at work:

        if( A==B )
        {
        if( B==C && A!=C)
        {
        DoABC();
        }
        else
        {
        DoWork();
        }
        }
        else if (C==A || C == B)
        {
        DoWork();
        }

        I have examined, tested over and over, but code never goes or will go to DoABC();

        // ♫ 99 little bugs in the code, // 99 bugs in the code // We fix a bug, compile it again // 101 little bugs in the code ♫

        W Offline
        W Offline
        whiteclouds
        wrote on last edited by
        #20

        Funny! I think if you want this code work as your meaning, you should override the operator "==", or you convey it into other language such as C#.

        There is some white cloud floating on the blue sky. That's the landscape I like.

        1 Reply Last reply
        0
        • R Ravi Sant

          Yes they are string(s) and now i thing to replace this code with just one line DoWork();

          // ♫ 99 little bugs in the code, // 99 bugs in the code // We fix a bug, compile it again // 101 little bugs in the code ♫

          Richard DeemingR Offline
          Richard DeemingR Offline
          Richard Deeming
          wrote on last edited by
          #21

          Ravi Sant wrote:

          replace this code with just one line DoWork();

          But what if A != B && A != C && B != C? The original code won't execute DoWork in that case.


          "These people looked deep within my soul and assigned me a number based on the order in which I joined." - Homer

          "These people looked deep within my soul and assigned me a number based on the order in which I joined" - Homer

          R 1 Reply Last reply
          0
          • Richard DeemingR Richard Deeming

            Ravi Sant wrote:

            replace this code with just one line DoWork();

            But what if A != B && A != C && B != C? The original code won't execute DoWork in that case.


            "These people looked deep within my soul and assigned me a number based on the order in which I joined." - Homer

            R Offline
            R Offline
            Ravi Sant
            wrote on last edited by
            #22

            Good Point .. :)

            // ♫ 99 little bugs in the code, // 99 bugs in the code // We fix a bug, compile it again // 101 little bugs in the code ♫

            1 Reply Last reply
            0
            • R Ravi Sant

              Just saw this code at work:

              if( A==B )
              {
              if( B==C && A!=C)
              {
              DoABC();
              }
              else
              {
              DoWork();
              }
              }
              else if (C==A || C == B)
              {
              DoWork();
              }

              I have examined, tested over and over, but code never goes or will go to DoABC();

              // ♫ 99 little bugs in the code, // 99 bugs in the code // We fix a bug, compile it again // 101 little bugs in the code ♫

              K Offline
              K Offline
              Kent K
              wrote on last edited by
              #23

              The only minute possibility of it being useful perhaps, is if there are multiple threads involved. . .and maybe if it is the case that A is static or something. . . .that if there was a CPU context switch between the lines if( A==B ) and if( B==C && A!=C) ...where A gets changed by another thread therefore the programmer had been trying to be uber careful about running DoABC(). . . . .??

              1 Reply Last reply
              0
              • D Daniel Scott

                If equality is transitive (and I really hope it is), it can indeed never execute DoABC. Given A == B and B == C, it follows from transitivity that A == C, so A != C must be false.

                A Offline
                A Offline
                agolddog
                wrote on last edited by
                #24

                Don't forget, in at least some languages, you're allowed to override operators. So A's == may not be the same as B's. That might be a path to DoABC. In the absence of that, though, what he said. In the presence of that, that's a whole other kind of bad development.

                1 Reply Last reply
                0
                • R Ravi Sant

                  Just saw this code at work:

                  if( A==B )
                  {
                  if( B==C && A!=C)
                  {
                  DoABC();
                  }
                  else
                  {
                  DoWork();
                  }
                  }
                  else if (C==A || C == B)
                  {
                  DoWork();
                  }

                  I have examined, tested over and over, but code never goes or will go to DoABC();

                  // ♫ 99 little bugs in the code, // 99 bugs in the code // We fix a bug, compile it again // 101 little bugs in the code ♫

                  F Offline
                  F Offline
                  frattaro
                  wrote on last edited by
                  #25

                  Are A, B and C all different object types that equate differently?

                  1 Reply Last reply
                  0
                  • R R Erasmus

                    I guest that much. ;-)

                    "Program testing can be used to show the presence of bugs, but never to show their absence." << please vote!! >>

                    D Offline
                    D Offline
                    DragonsRightWing
                    wrote on last edited by
                    #26

                    R. Erasmus wrote:

                    I guest that much.

                    Did you guest anonymously? - Oh, sorry - the bad-English-and-spelling thread was yesterday ... ;)

                    1 Reply Last reply
                    0
                    • L Luc Pattyn

                      Under normal circumstances equality is transitive; but it also isn't permanent... :)

                      Luc Pattyn [Forum Guidelines] [My Articles] Nil Volentibus Arduum

                      Please use <PRE> tags for code snippets, they preserve indentation, improve readability, and make me actually look at the code.

                      L Offline
                      L Offline
                      Lost User
                      wrote on last edited by
                      #27

                      "isn't permanent"? can you explain that?

                      L 1 Reply Last reply
                      0
                      • L Lost User

                        "isn't permanent"? can you explain that?

                        L Offline
                        L Offline
                        Luc Pattyn
                        wrote on last edited by
                        #28

                        The variables A, B, C may be equal at some point in time, they also are variables, hence their value can change. See also here[^]. :)

                        Luc Pattyn [Forum Guidelines] [My Articles] Nil Volentibus Arduum

                        Please use <PRE> tags for code snippets, they preserve indentation, improve readability, and make me actually look at the code.

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