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  3. Neither is this a programming question.

Neither is this a programming question.

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  • B Offline
    B Offline
    Brady Kelly
    wrote on last edited by
    #1

    It's an arithmetic question, and I'm feeling very dense for asking it, but I have coding to get on with and haven't time to play with arithmetic, i.e. for two columns my problem is solved, and I move on. But, let's say I have x items and y columns. How do I determine the maximum number of items per column? I said I was feeling dense. :doh: I'm just going to carry on with simple C# for the remainder of the evening. ;P

    T L G N 4 Replies Last reply
    0
    • B Brady Kelly

      It's an arithmetic question, and I'm feeling very dense for asking it, but I have coding to get on with and haven't time to play with arithmetic, i.e. for two columns my problem is solved, and I move on. But, let's say I have x items and y columns. How do I determine the maximum number of items per column? I said I was feeling dense. :doh: I'm just going to carry on with simple C# for the remainder of the evening. ;P

      T Offline
      T Offline
      TheGreatAndPowerfulOz
      wrote on last edited by
      #2

      x

      If your actions inspire others to dream more, learn more, do more and become more, you are a leader." - John Quincy Adams
      You must accept one of two basic premises: Either we are alone in the universe, or we are not alone in the universe. And either way, the implications are staggering” - Wernher von Braun

      C 1 Reply Last reply
      0
      • T TheGreatAndPowerfulOz

        x

        If your actions inspire others to dream more, learn more, do more and become more, you are a leader." - John Quincy Adams
        You must accept one of two basic premises: Either we are alone in the universe, or we are not alone in the universe. And either way, the implications are staggering” - Wernher von Braun

        C Offline
        C Offline
        Chris Meech
        wrote on last edited by
        #3

        That's what I thought. I think Brady forgot to post some more info. :)

        Chris Meech I am Canadian. [heard in a local bar] In theory there is no difference between theory and practice. In practice there is. [Yogi Berra] posting about Crystal Reports here is like discussing gay marriage on a catholic church’s website.[Nishant Sivakumar]

        K 1 Reply Last reply
        0
        • C Chris Meech

          That's what I thought. I think Brady forgot to post some more info. :)

          Chris Meech I am Canadian. [heard in a local bar] In theory there is no difference between theory and practice. In practice there is. [Yogi Berra] posting about Crystal Reports here is like discussing gay marriage on a catholic church’s website.[Nishant Sivakumar]

          K Offline
          K Offline
          Kyle Sponable
          wrote on last edited by
          #4

          Sorry I was completely wrong, you need to know how many items to initialize the arrays, umm well couldn't you store in a linked list and then iterate through the entries with a counter?

          B 1 Reply Last reply
          0
          • B Brady Kelly

            It's an arithmetic question, and I'm feeling very dense for asking it, but I have coding to get on with and haven't time to play with arithmetic, i.e. for two columns my problem is solved, and I move on. But, let's say I have x items and y columns. How do I determine the maximum number of items per column? I said I was feeling dense. :doh: I'm just going to carry on with simple C# for the remainder of the evening. ;P

            L Offline
            L Offline
            Lost User
            wrote on last edited by
            #5

            Math.Ceiling(x/y) ??

            B 1 Reply Last reply
            0
            • K Kyle Sponable

              Sorry I was completely wrong, you need to know how many items to initialize the arrays, umm well couldn't you store in a linked list and then iterate through the entries with a counter?

              B Offline
              B Offline
              Brady Kelly
              wrote on last edited by
              #6

              Surely there must be a mathematical answer? I keep getting distracted to try and work it out anyway, so I'm trying again.

              1 Reply Last reply
              0
              • B Brady Kelly

                It's an arithmetic question, and I'm feeling very dense for asking it, but I have coding to get on with and haven't time to play with arithmetic, i.e. for two columns my problem is solved, and I move on. But, let's say I have x items and y columns. How do I determine the maximum number of items per column? I said I was feeling dense. :doh: I'm just going to carry on with simple C# for the remainder of the evening. ;P

                G Offline
                G Offline
                Gary Wheeler
                wrote on last edited by
                #7

                With x total items, and y columns:

                int x,y;
                int items_per_column;
                 
                items_per_column = x / y;
                if ((x % y) != 0) items_per_column += 1;

                Software Zen: delete this;

                C 1 Reply Last reply
                0
                • L Lost User

                  Math.Ceiling(x/y) ??

                  B Offline
                  B Offline
                  Brady Kelly
                  wrote on last edited by
                  #8

                  Sweet, thanks! :thumbsup: Now for real man points, how do does one do that with integer arithmetic?

                  L M 2 Replies Last reply
                  0
                  • B Brady Kelly

                    Sweet, thanks! :thumbsup: Now for real man points, how do does one do that with integer arithmetic?

                    L Offline
                    L Offline
                    Lost User
                    wrote on last edited by
                    #9

                    Convert.ToInt32(x/y)+1 :) Edit, don't use convert, it rounds up if remainder is greater than .5, just use simple division, that discards the remainder

                    1 Reply Last reply
                    0
                    • G Gary Wheeler

                      With x total items, and y columns:

                      int x,y;
                      int items_per_column;
                       
                      items_per_column = x / y;
                      if ((x % y) != 0) items_per_column += 1;

                      Software Zen: delete this;

                      C Offline
                      C Offline
                      CPallini
                      wrote on last edited by
                      #10

                      In my columnless house your program is buggy. :rolleyes:

                      If the Lord God Almighty had consulted me before embarking upon the Creation, I would have recommended something simpler. -- Alfonso the Wise, 13th Century King of Castile.
                      This is going on my arrogant assumptions. You may have a superb reason why I'm completely wrong. -- Iain Clarke
                      [My articles]

                      G 1 Reply Last reply
                      0
                      • B Brady Kelly

                        Sweet, thanks! :thumbsup: Now for real man points, how do does one do that with integer arithmetic?

                        M Offline
                        M Offline
                        Manfred Rudolf Bihy
                        wrote on last edited by
                        #11

                        int x = 113;
                        int y = 23:

                        // Making sure x is evenly divisable by y
                        // So to speak Math.Ceiling for integer division
                        int r = (x + (y - x % y)) / y;

                        Cheers!

                        —MRB

                        "With sufficient thrust, pigs fly just fine."

                        Ross Callon, The Twelve Networking Truths, RFC1925

                        B 1 Reply Last reply
                        0
                        • B Brady Kelly

                          It's an arithmetic question, and I'm feeling very dense for asking it, but I have coding to get on with and haven't time to play with arithmetic, i.e. for two columns my problem is solved, and I move on. But, let's say I have x items and y columns. How do I determine the maximum number of items per column? I said I was feeling dense. :doh: I'm just going to carry on with simple C# for the remainder of the evening. ;P

                          N Offline
                          N Offline
                          Not Active
                          wrote on last edited by
                          #12

                          The answer is always 42


                          No comment

                          1 Reply Last reply
                          0
                          • M Manfred Rudolf Bihy

                            int x = 113;
                            int y = 23:

                            // Making sure x is evenly divisable by y
                            // So to speak Math.Ceiling for integer division
                            int r = (x + (y - x % y)) / y;

                            Cheers!

                            —MRB

                            "With sufficient thrust, pigs fly just fine."

                            Ross Callon, The Twelve Networking Truths, RFC1925

                            B Offline
                            B Offline
                            Brady Kelly
                            wrote on last edited by
                            #13

                            Thank you, have some points! :rose:

                            1 Reply Last reply
                            0
                            • C CPallini

                              In my columnless house your program is buggy. :rolleyes:

                              If the Lord God Almighty had consulted me before embarking upon the Creation, I would have recommended something simpler. -- Alfonso the Wise, 13th Century King of Castile.
                              This is going on my arrogant assumptions. You may have a superb reason why I'm completely wrong. -- Iain Clarke
                              [My articles]

                              G Offline
                              G Offline
                              Gary Wheeler
                              wrote on last edited by
                              #14

                              int x,y;
                              int items_per_column;

                              if (y != 0)
                              {
                              items_per_column = x / y;
                              if ((x % y) != 0) items_per_column += 1;
                              }
                              else
                              {
                              items_per_column = x; // for lack of anything better to do
                              }

                              Bitch, bitch, bitch...

                              Software Zen: delete this;

                              C 1 Reply Last reply
                              0
                              • G Gary Wheeler

                                int x,y;
                                int items_per_column;

                                if (y != 0)
                                {
                                items_per_column = x / y;
                                if ((x % y) != 0) items_per_column += 1;
                                }
                                else
                                {
                                items_per_column = x; // for lack of anything better to do
                                }

                                Bitch, bitch, bitch...

                                Software Zen: delete this;

                                C Offline
                                C Offline
                                CPallini
                                wrote on last edited by
                                #15

                                Nope, Nope, Nope!

                                if (y != 0)
                                {
                                items_per_column = x / y;
                                if ((x % y) != 0) items_per_column += 1;
                                }
                                else if ( x != 0)
                                {
                                items_per_column = IM_SORRY_JACK_WE_NEED_MORE_MEMORY_FOR_INTEGERS;
                                }
                                else
                                {
                                items_per_column = PLEASE_PICK_ONE_OR_ANOTHER_OR;
                                }

                                :laugh:

                                If the Lord God Almighty had consulted me before embarking upon the Creation, I would have recommended something simpler. -- Alfonso the Wise, 13th Century King of Castile.
                                This is going on my arrogant assumptions. You may have a superb reason why I'm completely wrong. -- Iain Clarke
                                [My articles]

                                G 1 Reply Last reply
                                0
                                • C CPallini

                                  Nope, Nope, Nope!

                                  if (y != 0)
                                  {
                                  items_per_column = x / y;
                                  if ((x % y) != 0) items_per_column += 1;
                                  }
                                  else if ( x != 0)
                                  {
                                  items_per_column = IM_SORRY_JACK_WE_NEED_MORE_MEMORY_FOR_INTEGERS;
                                  }
                                  else
                                  {
                                  items_per_column = PLEASE_PICK_ONE_OR_ANOTHER_OR;
                                  }

                                  :laugh:

                                  If the Lord God Almighty had consulted me before embarking upon the Creation, I would have recommended something simpler. -- Alfonso the Wise, 13th Century King of Castile.
                                  This is going on my arrogant assumptions. You may have a superb reason why I'm completely wrong. -- Iain Clarke
                                  [My articles]

                                  G Offline
                                  G Offline
                                  Gary Wheeler
                                  wrote on last edited by
                                  #16

                                  int x,y;
                                  int items_per_column;

                                  if (y > 0)
                                  {
                                  items_per_column = x / y;
                                  if ((x % y) != 0) items_per_column += 1;
                                  }
                                  else if (y < 0)
                                  {
                                  throw new WTF_Exception();
                                  }
                                  else
                                  {
                                  throw new YourePissingMeOffException();
                                  }

                                  Software Zen: delete this;

                                  1 Reply Last reply
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