What a gem.

[Paladin2000]

Actually, it's:

Return (SystemInformation.PowerStatus.BatteryLifePercent * 100).ToString() + "%"

You did the ToString before the multiplication. Note that this:

SystemInformation.PowerStatus.BatteryLifePercent.ToString("p")

...does create a percentage conversion, but since it has decimals and a space it is not equivalent.

[Mark AJA]

I used & and not + as & can join a string and a number. + will only add two nunbers or attach two strings. I would usually use CStr$() but as I was not to sure what language this was, used & as it's used in a number of languages.

[GBSC]

NA is correct because if you can't determine the battery percentage you must be dealing with sodium :)

[James Lonero]

I did something like this when I was programming in assembly language back in college. I was making a way to get a value out of a register out to the terminal in an integer form. Then, we only had 16 bit registers and could only output -32738 to 32737. But, there was no library routines to output to the terminal.

[Fabio Franco]

Well, although in assembly one can develop a routine for that, it's forgivable if you don't, specially in college while learning. What's unforgivable is having this in a high level language in production code for a mission critical application.

"To alcohol! The cause of, and solution to, all of life's problems" - Homer Simpson

[Paladin2000]

The "+" operator does work here, it implicitly converts the number to a string and concatenates it to the other. But yes, the "&" operator is for concatenation explicitly. However, in your example, my key point was that you used the "*" operator between a number and a string...

[Mark AJA]

I don't know what language uses a * between two strings. * is usually used to multiply two numbers. EG 123*4 = 492 + is used to add two numbers. EG 123+4 = 127. 123+"4" = error & is used to join two numbers, strings or a number and a string. EG 123 & 4 = "1234" If a language returns 492 or "492" from 123*"4" then in my opinion the language needs an update. The following Visual Basic 5 code:

Private Sub Form_Load()
Dim a As Integer ' or as Long or Double
Dim b As String
a = 123
b = "4"
MsgBox a * b
End Sub

displays 492, but should display an error acording to other versions of Basic.

[bbirajdar]

excellent observation

[Mohibur Rashid]

Well, I can see he has time to do code :))))))))))

[krumia]

Quote:

' This code will retrieve the BatteryLifePercent property and convert it to a percent.

Really? Why would someone convert something to percent which is already in percent?