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  4. [Resolved] C# to VB Adaption Problem with Lambda Expressions

[Resolved] C# to VB Adaption Problem with Lambda Expressions

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  • L Lost User

    Progress doesn't take a parameter, according to it's declaration. How did you resolve the fact that VB.NET lacks a "yield return" statement? ..and how about simply wrapping the C# code in an assembly and reference that from VB?

    Bastard Programmer from Hell :suss:

    S Offline
    S Offline
    Sonhospa
    wrote on last edited by
    #11

    From my initial message:

    Michael Schäuble wrote:

    In order to avoid problems with conversion of c# 'yield' operator, I put the extensions into a DLL and set a reference to that.

    According to IntelliSense 'progress' should be an integer value for 'percentProgress'. The funny thing is that it works as described as long as I stay in C# with the Main procedure - also when using the same referenced DLL for all the extensions:

                items
                    .WithProgressReporting(progress => worker.ReportProgress(progress))
                    .ForEach(item => Thread.Sleep(10)); // simulate some real work
    

    Line 2 results in the percentage, which is properly reported to the console. So there really must be something wrong with the lambda, which obviously is too cryptic for me... Still this is exactly the part of the code which I can't reference (main procedure "TestProgressReporting") since my application is written in VB.

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    • L Lost User

      Progress doesn't take a parameter, according to it's declaration. How did you resolve the fact that VB.NET lacks a "yield return" statement? ..and how about simply wrapping the C# code in an assembly and reference that from VB?

      Bastard Programmer from Hell :suss:

      L Offline
      L Offline
      Luc Pattyn
      wrote on last edited by
      #12

      Eddy Vluggen wrote:

      How did you resolve the fact that VB.NET lacks a "yield return" statement?

      perhaps with patience. Yield exists since VS2010 SP1 according to this[^]. And it is simply yield, not yield return, so for once VB.NET is less verbose than C#. :)

      Luc Pattyn [My Articles] Nil Volentibus Arduum

      S L T 3 Replies Last reply
      0
      • L Luc Pattyn

        Eddy Vluggen wrote:

        How did you resolve the fact that VB.NET lacks a "yield return" statement?

        perhaps with patience. Yield exists since VS2010 SP1 according to this[^]. And it is simply yield, not yield return, so for once VB.NET is less verbose than C#. :)

        Luc Pattyn [My Articles] Nil Volentibus Arduum

        S Offline
        S Offline
        Sonhospa
        wrote on last edited by
        #13

        Hey Luc, thanks for the hint, I'm just about downloading SP1. Still I'm afraid it wouldn't solve the problem I have: As I wrote I put all the extensions into a DLL which I'm referencing from my main VB code as well as from VB and C# test procedures. It seems pretty clear that there must be something wrong with the Lambda expressions. Would you have a look at them, please?

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        • S Sonhospa

          Hey Luc, thanks for the hint, I'm just about downloading SP1. Still I'm afraid it wouldn't solve the problem I have: As I wrote I put all the extensions into a DLL which I'm referencing from my main VB code as well as from VB and C# test procedures. It seems pretty clear that there must be something wrong with the Lambda expressions. Would you have a look at them, please?

          L Offline
          L Offline
          Luc Pattyn
          wrote on last edited by
          #14

          I seldom use lambda's, I probably can't help you. If they are in a separate DLL, why aren't you using C# for them? :)

          Luc Pattyn [My Articles] Nil Volentibus Arduum

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          • L Luc Pattyn

            I seldom use lambda's, I probably can't help you. If they are in a separate DLL, why aren't you using C# for them? :)

            Luc Pattyn [My Articles] Nil Volentibus Arduum

            S Offline
            S Offline
            Sonhospa
            wrote on last edited by
            #15

            You misunderstood me. All the extension methods, which contain the C# 'yield' operator, are in a separate DLL. My application is in VB so I have to call the extensions from VB using adapted code... and the sample code (pls. see link in the initial message) is in C# where the Lambdas work.

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            • L Luc Pattyn

              Eddy Vluggen wrote:

              How did you resolve the fact that VB.NET lacks a "yield return" statement?

              perhaps with patience. Yield exists since VS2010 SP1 according to this[^]. And it is simply yield, not yield return, so for once VB.NET is less verbose than C#. :)

              Luc Pattyn [My Articles] Nil Volentibus Arduum

              L Offline
              L Offline
              Lost User
              wrote on last edited by
              #16

              Cool - I never missed the statement in VB, until this question popped up :)

              Bastard Programmer from Hell :suss:

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              • S Sonhospa

                Hi guys, I hope you had a nice start into 2012! I've been trying to convert this^ piece of code into VB, using VS Express 2010 and #Develop. In order to avoid problems with conversion of c# 'yield' operator, I put the extensions into a DLL and set a reference to that. The translated code of the test implementation reads like:

                Shared Sub Main(ByVal args() As String)
                Dim worker As New BackgroundWorker()
                worker.WorkerReportsProgress = True
                AddHandler worker.DoWork, Function(sender, e)
                ' pretend we have a collection of items to process
                Dim items(999) As Integer
                items.WithProgressReporting(Function(progress) worker.ReportProgress(progress)).ForEach(Function(item) Thread.Sleep(10)) ' simulate some real work
                End Function

                AddHandler worker.ProgressChanged, Function(sender, e)
                ' make sure the figure is written to the
                ' same point on screen each time
                Console.SetCursorPosition(1, 0)
                Console.Write(e.ProgressPercentage)
                End Function
                
                worker.RunWorkerAsync()
                Console.Read()
                

                End Sub

                Unfortunately in VB the line

                items.WithProgressReporting(Function(progress) worker.ReportProgress(progress).ForEach(Function(item) Thread.Sleep(10)))

                throws an exception "Expression does not produce a value" at the underlined place. There's no such exception in C# where the test code compiles and executes fine. Having to implement the technique into my VB application, I'd like to understand where the problem arises. Could anyone of you tell me what's wrong in the (automatic) translation of the Lambda expression? Thank you Mick

                S Offline
                S Offline
                Simon_Whale
                wrote on last edited by
                #17

                VB2010 has introduced sub(parameter) into the lambda specification. I haven't tested it but wouldn't the following work?

                items.WithProgressReporting(sub(progress) worker.ReportProgress(progress) end sub).forEach(function(item) thread.Sleep(10)))

                Lobster Thermidor aux crevettes with a Mornay sauce, served in a Provençale manner with shallots and aubergines, garnished with truffle pate, brandy and a fried egg on top and Spam - Monty Python Spam Sketch

                S 1 Reply Last reply
                0
                • S Sonhospa

                  Hi guys, I hope you had a nice start into 2012! I've been trying to convert this^ piece of code into VB, using VS Express 2010 and #Develop. In order to avoid problems with conversion of c# 'yield' operator, I put the extensions into a DLL and set a reference to that. The translated code of the test implementation reads like:

                  Shared Sub Main(ByVal args() As String)
                  Dim worker As New BackgroundWorker()
                  worker.WorkerReportsProgress = True
                  AddHandler worker.DoWork, Function(sender, e)
                  ' pretend we have a collection of items to process
                  Dim items(999) As Integer
                  items.WithProgressReporting(Function(progress) worker.ReportProgress(progress)).ForEach(Function(item) Thread.Sleep(10)) ' simulate some real work
                  End Function

                  AddHandler worker.ProgressChanged, Function(sender, e)
                  ' make sure the figure is written to the
                  ' same point on screen each time
                  Console.SetCursorPosition(1, 0)
                  Console.Write(e.ProgressPercentage)
                  End Function
                  
                  worker.RunWorkerAsync()
                  Console.Read()
                  

                  End Sub

                  Unfortunately in VB the line

                  items.WithProgressReporting(Function(progress) worker.ReportProgress(progress).ForEach(Function(item) Thread.Sleep(10)))

                  throws an exception "Expression does not produce a value" at the underlined place. There's no such exception in C# where the test code compiles and executes fine. Having to implement the technique into my VB application, I'd like to understand where the problem arises. Could anyone of you tell me what's wrong in the (automatic) translation of the Lambda expression? Thank you Mick

                  U Offline
                  U Offline
                  User 7825588
                  wrote on last edited by
                  #18

                  Try changing this line:

                  items.WithProgressReporting(Function(progress)
                  worker.ReportProgress(progress)).ForEach(Function(item) Thread.Sleep(10)) ' simulate some real work

                  To this:

                  items.WithProgressReporting(Function(progress) _
                  worker.ReportProgress(progress)).ToList.ForEach(Function(item) Thread.Sleep(10)) ' simulate some real work

                  The .ForEach extension method doesn't work with IEnumerables and since that's what WithProgressReporting returns, the resultset must first be cast as a Generic List. Also, I don't know for sure, but it looks like the converter inserted an extra line break. That's why I added the underscore to the end of the first line.

                  S 1 Reply Last reply
                  0
                  • S Sonhospa

                    Hi guys, I hope you had a nice start into 2012! I've been trying to convert this^ piece of code into VB, using VS Express 2010 and #Develop. In order to avoid problems with conversion of c# 'yield' operator, I put the extensions into a DLL and set a reference to that. The translated code of the test implementation reads like:

                    Shared Sub Main(ByVal args() As String)
                    Dim worker As New BackgroundWorker()
                    worker.WorkerReportsProgress = True
                    AddHandler worker.DoWork, Function(sender, e)
                    ' pretend we have a collection of items to process
                    Dim items(999) As Integer
                    items.WithProgressReporting(Function(progress) worker.ReportProgress(progress)).ForEach(Function(item) Thread.Sleep(10)) ' simulate some real work
                    End Function

                    AddHandler worker.ProgressChanged, Function(sender, e)
                    ' make sure the figure is written to the
                    ' same point on screen each time
                    Console.SetCursorPosition(1, 0)
                    Console.Write(e.ProgressPercentage)
                    End Function
                    
                    worker.RunWorkerAsync()
                    Console.Read()
                    

                    End Sub

                    Unfortunately in VB the line

                    items.WithProgressReporting(Function(progress) worker.ReportProgress(progress).ForEach(Function(item) Thread.Sleep(10)))

                    throws an exception "Expression does not produce a value" at the underlined place. There's no such exception in C# where the test code compiles and executes fine. Having to implement the technique into my VB application, I'd like to understand where the problem arises. Could anyone of you tell me what's wrong in the (automatic) translation of the Lambda expression? Thank you Mick

                    E Offline
                    E Offline
                    Estys
                    wrote on last edited by
                    #19

                    I always have trouble with anonymous delegates in VB so I factored them out :

                    Class Program
                    Shared worker As BackgroundWorker
                    Public Shared Sub Main() 'ByVal args As String())
                    worker = New BackgroundWorker()
                    worker.WorkerReportsProgress = True
                    AddHandler worker.DoWork, AddressOf DoWork
                    AddHandler worker.ProgressChanged, AddressOf ProgressChanged
                    worker.RunWorkerAsync()
                    Console.Read()
                    End Sub

                    Private Shared Sub DoWork(ByVal sender As Object, ByVal e As DoWorkEventArgs)
                        Dim items = Enumerable.Range(1, 1000)
                        items.WithProgressReporting(AddressOf ReportProgress).ForEach(AddressOf DoSleep)
                    End Sub
                    Private Shared Sub ReportProgress(ByVal progress As Integer)
                        worker.ReportProgress(progress)
                    End Sub
                    Private Shared Sub DoSleep(ByVal item As Integer)
                        Thread.Sleep(10)
                    End Sub
                    Private Shared Sub ProgressChanged(ByVal sender As Object, ByVal e As ProgressChangedEventArgs)
                        Console.SetCursorPosition(1, 0)
                        Console.Write(e.ProgressPercentage)
                    End Sub
                    

                    End Class

                    Cheers

                    S 1 Reply Last reply
                    0
                    • L Luc Pattyn

                      Eddy Vluggen wrote:

                      How did you resolve the fact that VB.NET lacks a "yield return" statement?

                      perhaps with patience. Yield exists since VS2010 SP1 according to this[^]. And it is simply yield, not yield return, so for once VB.NET is less verbose than C#. :)

                      Luc Pattyn [My Articles] Nil Volentibus Arduum

                      T Offline
                      T Offline
                      Terence Wallace
                      wrote on last edited by
                      #20

                      Hey just wanted to say thanks Luc that link got me to several other links on the subject and could prove quite useful to me in the very near future. Thanks again. This is now supported in VS 2010 SP1, with the Async CTP, see: http://msdn.microsoft.com/en-us/vstudio/gg497937[^] Also see: http://www.microsoft.com/downloads/en/details.aspx?FamilyID=4738205d-5682-47bf-b62e-641f6441735b&displaylang=en[^]

                      "If you think it's expensive to hire a professional to do the job, wait until you hire an amateur." - Red Adair

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                      0
                      • S Sonhospa

                        Hi guys, I hope you had a nice start into 2012! I've been trying to convert this^ piece of code into VB, using VS Express 2010 and #Develop. In order to avoid problems with conversion of c# 'yield' operator, I put the extensions into a DLL and set a reference to that. The translated code of the test implementation reads like:

                        Shared Sub Main(ByVal args() As String)
                        Dim worker As New BackgroundWorker()
                        worker.WorkerReportsProgress = True
                        AddHandler worker.DoWork, Function(sender, e)
                        ' pretend we have a collection of items to process
                        Dim items(999) As Integer
                        items.WithProgressReporting(Function(progress) worker.ReportProgress(progress)).ForEach(Function(item) Thread.Sleep(10)) ' simulate some real work
                        End Function

                        AddHandler worker.ProgressChanged, Function(sender, e)
                        ' make sure the figure is written to the
                        ' same point on screen each time
                        Console.SetCursorPosition(1, 0)
                        Console.Write(e.ProgressPercentage)
                        End Function
                        
                        worker.RunWorkerAsync()
                        Console.Read()
                        

                        End Sub

                        Unfortunately in VB the line

                        items.WithProgressReporting(Function(progress) worker.ReportProgress(progress).ForEach(Function(item) Thread.Sleep(10)))

                        throws an exception "Expression does not produce a value" at the underlined place. There's no such exception in C# where the test code compiles and executes fine. Having to implement the technique into my VB application, I'd like to understand where the problem arises. Could anyone of you tell me what's wrong in the (automatic) translation of the Lambda expression? Thank you Mick

                        D Offline
                        D Offline
                        DavidSherwood
                        wrote on last edited by
                        #21

                        In VB, a function that returns void is a "Sub". This is true with lambda function as well. So your ForEach lambda should be

                        ForEach(Sub(item) Thread.Sleep(10))

                        S S 2 Replies Last reply
                        0
                        • D DavidSherwood

                          In VB, a function that returns void is a "Sub". This is true with lambda function as well. So your ForEach lambda should be

                          ForEach(Sub(item) Thread.Sleep(10))

                          S Offline
                          S Offline
                          Simon_Whale
                          wrote on last edited by
                          #22

                          Only true with 2010 though, as there is many time I would loved to of used it in my current project that is 3.5 framework

                          Lobster Thermidor aux crevettes with a Mornay sauce, served in a Provençale manner with shallots and aubergines, garnished with truffle pate, brandy and a fried egg on top and Spam - Monty Python Spam Sketch

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                          • S Simon_Whale

                            VB2010 has introduced sub(parameter) into the lambda specification. I haven't tested it but wouldn't the following work?

                            items.WithProgressReporting(sub(progress) worker.ReportProgress(progress) end sub).forEach(function(item) thread.Sleep(10)))

                            Lobster Thermidor aux crevettes with a Mornay sauce, served in a Provençale manner with shallots and aubergines, garnished with truffle pate, brandy and a fried egg on top and Spam - Monty Python Spam Sketch

                            S Offline
                            S Offline
                            Sonhospa
                            wrote on last edited by
                            #23

                            Hi Simon, sorry for the late response which was due to a short holiday of mine. Thanks for your hint which pushed me in the right direction: In the end, all I had to do was change "function" into "sub" in VB. It's finally solved now, and the line

                            items.WithProgressReporting(Sub(progress) worker.ReportProgress(progress)).ForEach(Sub(item) Thread.Sleep(10))

                            works, as well as Estys suggestion to factor out the subs. No "end" needed here. Regards - Mick

                            S 1 Reply Last reply
                            0
                            • S Sonhospa

                              Hi Simon, sorry for the late response which was due to a short holiday of mine. Thanks for your hint which pushed me in the right direction: In the end, all I had to do was change "function" into "sub" in VB. It's finally solved now, and the line

                              items.WithProgressReporting(Sub(progress) worker.ReportProgress(progress)).ForEach(Sub(item) Thread.Sleep(10))

                              works, as well as Estys suggestion to factor out the subs. No "end" needed here. Regards - Mick

                              S Offline
                              S Offline
                              Simon_Whale
                              wrote on last edited by
                              #24

                              Glad it helped :thumbsup:

                              Lobster Thermidor aux crevettes with a Mornay sauce, served in a Provençale manner with shallots and aubergines, garnished with truffle pate, brandy and a fried egg on top and Spam - Monty Python Spam Sketch

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                              0
                              • U User 7825588

                                Try changing this line:

                                items.WithProgressReporting(Function(progress)
                                worker.ReportProgress(progress)).ForEach(Function(item) Thread.Sleep(10)) ' simulate some real work

                                To this:

                                items.WithProgressReporting(Function(progress) _
                                worker.ReportProgress(progress)).ToList.ForEach(Function(item) Thread.Sleep(10)) ' simulate some real work

                                The .ForEach extension method doesn't work with IEnumerables and since that's what WithProgressReporting returns, the resultset must first be cast as a Generic List. Also, I don't know for sure, but it looks like the converter inserted an extra line break. That's why I added the underscore to the end of the first line.

                                S Offline
                                S Offline
                                Sonhospa
                                wrote on last edited by
                                #25

                                Hi Member... ;) , sorry for the late response which was due to a short holiday of mine. Thanks for your hint which unfortunately didn't work: In the end, all I had to do was change "function" into "sub" in VB. It's finally solved now, and the line

                                items.WithProgressReporting(Sub(progress) worker.ReportProgress(progress)).ForEach(Sub(item) Thread.Sleep(10))

                                works, as well as Estys suggestion to factor out the subs (no "end" or "ToList" constructions needed). Regards - Mick

                                1 Reply Last reply
                                0
                                • E Estys

                                  I always have trouble with anonymous delegates in VB so I factored them out :

                                  Class Program
                                  Shared worker As BackgroundWorker
                                  Public Shared Sub Main() 'ByVal args As String())
                                  worker = New BackgroundWorker()
                                  worker.WorkerReportsProgress = True
                                  AddHandler worker.DoWork, AddressOf DoWork
                                  AddHandler worker.ProgressChanged, AddressOf ProgressChanged
                                  worker.RunWorkerAsync()
                                  Console.Read()
                                  End Sub

                                  Private Shared Sub DoWork(ByVal sender As Object, ByVal e As DoWorkEventArgs)
                                      Dim items = Enumerable.Range(1, 1000)
                                      items.WithProgressReporting(AddressOf ReportProgress).ForEach(AddressOf DoSleep)
                                  End Sub
                                  Private Shared Sub ReportProgress(ByVal progress As Integer)
                                      worker.ReportProgress(progress)
                                  End Sub
                                  Private Shared Sub DoSleep(ByVal item As Integer)
                                      Thread.Sleep(10)
                                  End Sub
                                  Private Shared Sub ProgressChanged(ByVal sender As Object, ByVal e As ProgressChangedEventArgs)
                                      Console.SetCursorPosition(1, 0)
                                      Console.Write(e.ProgressPercentage)
                                  End Sub
                                  

                                  End Class

                                  Cheers

                                  S Offline
                                  S Offline
                                  Sonhospa
                                  wrote on last edited by
                                  #26

                                  Hi Estys, sorry for the late response which was due to a short holiday of mine. Thanks for your hint which, together with the other guys' ideas, pushed me in the right direction: In the end, all I had to do was change "function" into "sub" in VB. It's finally solved now, and the line

                                  items.WithProgressReporting(Sub(progress) worker.ReportProgress(progress)).ForEach(Sub(item) Thread.Sleep(10))

                                  works, as well as your suggestion to factor out the subs. Just to complete: In your snippet I had to change the definition of 'items' to:

                                  Dim items As IEnumerable(Of Integer) = Enumerable.Range(1, 1000)

                                  in VB. But the most important thing: It works - and I hope I understand it a little better ;) Thanks again, regards - Mick

                                  E 1 Reply Last reply
                                  0
                                  • D DavidSherwood

                                    In VB, a function that returns void is a "Sub". This is true with lambda function as well. So your ForEach lambda should be

                                    ForEach(Sub(item) Thread.Sleep(10))

                                    S Offline
                                    S Offline
                                    Sonhospa
                                    wrote on last edited by
                                    #27

                                    Hi David, sorry for the late response which was due to a short holiday of mine. Thanks for your hint which pushed me in the right direction: In the end, all I had to do was simply change "function" into "sub" in VB. It's finally solved now, and the line

                                    items.WithProgressReporting(Sub(progress) worker.ReportProgress(progress)).ForEach(Sub(item) Thread.Sleep(10))

                                    works, as well as Estys suggestion to factor out the subs (slightly changed). Thanks again, regards - Mick

                                    1 Reply Last reply
                                    0
                                    • S Sonhospa

                                      Hi Estys, sorry for the late response which was due to a short holiday of mine. Thanks for your hint which, together with the other guys' ideas, pushed me in the right direction: In the end, all I had to do was change "function" into "sub" in VB. It's finally solved now, and the line

                                      items.WithProgressReporting(Sub(progress) worker.ReportProgress(progress)).ForEach(Sub(item) Thread.Sleep(10))

                                      works, as well as your suggestion to factor out the subs. Just to complete: In your snippet I had to change the definition of 'items' to:

                                      Dim items As IEnumerable(Of Integer) = Enumerable.Range(1, 1000)

                                      in VB. But the most important thing: It works - and I hope I understand it a little better ;) Thanks again, regards - Mick

                                      E Offline
                                      E Offline
                                      Estys
                                      wrote on last edited by
                                      #28

                                      Michael Schäuble wrote:

                                      I had to change the definition of 'items'

                                      That's odd, with me it worked as I posted it. I'm on .NET 3.5, VB Express 2008 Cheers

                                      If you can read this, you don't have Papyrus installed

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