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  4. [Resolved] C# to VB Adaption Problem with Lambda Expressions

[Resolved] C# to VB Adaption Problem with Lambda Expressions

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  • L Luc Pattyn

    Eddy Vluggen wrote:

    How did you resolve the fact that VB.NET lacks a "yield return" statement?

    perhaps with patience. Yield exists since VS2010 SP1 according to this[^]. And it is simply yield, not yield return, so for once VB.NET is less verbose than C#. :)

    Luc Pattyn [My Articles] Nil Volentibus Arduum

    S Offline
    S Offline
    Sonhospa
    wrote on last edited by
    #13

    Hey Luc, thanks for the hint, I'm just about downloading SP1. Still I'm afraid it wouldn't solve the problem I have: As I wrote I put all the extensions into a DLL which I'm referencing from my main VB code as well as from VB and C# test procedures. It seems pretty clear that there must be something wrong with the Lambda expressions. Would you have a look at them, please?

    L 1 Reply Last reply
    0
    • S Sonhospa

      Hey Luc, thanks for the hint, I'm just about downloading SP1. Still I'm afraid it wouldn't solve the problem I have: As I wrote I put all the extensions into a DLL which I'm referencing from my main VB code as well as from VB and C# test procedures. It seems pretty clear that there must be something wrong with the Lambda expressions. Would you have a look at them, please?

      L Offline
      L Offline
      Luc Pattyn
      wrote on last edited by
      #14

      I seldom use lambda's, I probably can't help you. If they are in a separate DLL, why aren't you using C# for them? :)

      Luc Pattyn [My Articles] Nil Volentibus Arduum

      S 1 Reply Last reply
      0
      • L Luc Pattyn

        I seldom use lambda's, I probably can't help you. If they are in a separate DLL, why aren't you using C# for them? :)

        Luc Pattyn [My Articles] Nil Volentibus Arduum

        S Offline
        S Offline
        Sonhospa
        wrote on last edited by
        #15

        You misunderstood me. All the extension methods, which contain the C# 'yield' operator, are in a separate DLL. My application is in VB so I have to call the extensions from VB using adapted code... and the sample code (pls. see link in the initial message) is in C# where the Lambdas work.

        1 Reply Last reply
        0
        • L Luc Pattyn

          Eddy Vluggen wrote:

          How did you resolve the fact that VB.NET lacks a "yield return" statement?

          perhaps with patience. Yield exists since VS2010 SP1 according to this[^]. And it is simply yield, not yield return, so for once VB.NET is less verbose than C#. :)

          Luc Pattyn [My Articles] Nil Volentibus Arduum

          L Offline
          L Offline
          Lost User
          wrote on last edited by
          #16

          Cool - I never missed the statement in VB, until this question popped up :)

          Bastard Programmer from Hell :suss:

          1 Reply Last reply
          0
          • S Sonhospa

            Hi guys, I hope you had a nice start into 2012! I've been trying to convert this^ piece of code into VB, using VS Express 2010 and #Develop. In order to avoid problems with conversion of c# 'yield' operator, I put the extensions into a DLL and set a reference to that. The translated code of the test implementation reads like:

            Shared Sub Main(ByVal args() As String)
            Dim worker As New BackgroundWorker()
            worker.WorkerReportsProgress = True
            AddHandler worker.DoWork, Function(sender, e)
            ' pretend we have a collection of items to process
            Dim items(999) As Integer
            items.WithProgressReporting(Function(progress) worker.ReportProgress(progress)).ForEach(Function(item) Thread.Sleep(10)) ' simulate some real work
            End Function

            AddHandler worker.ProgressChanged, Function(sender, e)
            ' make sure the figure is written to the
            ' same point on screen each time
            Console.SetCursorPosition(1, 0)
            Console.Write(e.ProgressPercentage)
            End Function
            
            worker.RunWorkerAsync()
            Console.Read()
            

            End Sub

            Unfortunately in VB the line

            items.WithProgressReporting(Function(progress) worker.ReportProgress(progress).ForEach(Function(item) Thread.Sleep(10)))

            throws an exception "Expression does not produce a value" at the underlined place. There's no such exception in C# where the test code compiles and executes fine. Having to implement the technique into my VB application, I'd like to understand where the problem arises. Could anyone of you tell me what's wrong in the (automatic) translation of the Lambda expression? Thank you Mick

            S Offline
            S Offline
            Simon_Whale
            wrote on last edited by
            #17

            VB2010 has introduced sub(parameter) into the lambda specification. I haven't tested it but wouldn't the following work?

            items.WithProgressReporting(sub(progress) worker.ReportProgress(progress) end sub).forEach(function(item) thread.Sleep(10)))

            Lobster Thermidor aux crevettes with a Mornay sauce, served in a Provençale manner with shallots and aubergines, garnished with truffle pate, brandy and a fried egg on top and Spam - Monty Python Spam Sketch

            S 1 Reply Last reply
            0
            • S Sonhospa

              Hi guys, I hope you had a nice start into 2012! I've been trying to convert this^ piece of code into VB, using VS Express 2010 and #Develop. In order to avoid problems with conversion of c# 'yield' operator, I put the extensions into a DLL and set a reference to that. The translated code of the test implementation reads like:

              Shared Sub Main(ByVal args() As String)
              Dim worker As New BackgroundWorker()
              worker.WorkerReportsProgress = True
              AddHandler worker.DoWork, Function(sender, e)
              ' pretend we have a collection of items to process
              Dim items(999) As Integer
              items.WithProgressReporting(Function(progress) worker.ReportProgress(progress)).ForEach(Function(item) Thread.Sleep(10)) ' simulate some real work
              End Function

              AddHandler worker.ProgressChanged, Function(sender, e)
              ' make sure the figure is written to the
              ' same point on screen each time
              Console.SetCursorPosition(1, 0)
              Console.Write(e.ProgressPercentage)
              End Function
              
              worker.RunWorkerAsync()
              Console.Read()
              

              End Sub

              Unfortunately in VB the line

              items.WithProgressReporting(Function(progress) worker.ReportProgress(progress).ForEach(Function(item) Thread.Sleep(10)))

              throws an exception "Expression does not produce a value" at the underlined place. There's no such exception in C# where the test code compiles and executes fine. Having to implement the technique into my VB application, I'd like to understand where the problem arises. Could anyone of you tell me what's wrong in the (automatic) translation of the Lambda expression? Thank you Mick

              U Offline
              U Offline
              User 7825588
              wrote on last edited by
              #18

              Try changing this line:

              items.WithProgressReporting(Function(progress)
              worker.ReportProgress(progress)).ForEach(Function(item) Thread.Sleep(10)) ' simulate some real work

              To this:

              items.WithProgressReporting(Function(progress) _
              worker.ReportProgress(progress)).ToList.ForEach(Function(item) Thread.Sleep(10)) ' simulate some real work

              The .ForEach extension method doesn't work with IEnumerables and since that's what WithProgressReporting returns, the resultset must first be cast as a Generic List. Also, I don't know for sure, but it looks like the converter inserted an extra line break. That's why I added the underscore to the end of the first line.

              S 1 Reply Last reply
              0
              • S Sonhospa

                Hi guys, I hope you had a nice start into 2012! I've been trying to convert this^ piece of code into VB, using VS Express 2010 and #Develop. In order to avoid problems with conversion of c# 'yield' operator, I put the extensions into a DLL and set a reference to that. The translated code of the test implementation reads like:

                Shared Sub Main(ByVal args() As String)
                Dim worker As New BackgroundWorker()
                worker.WorkerReportsProgress = True
                AddHandler worker.DoWork, Function(sender, e)
                ' pretend we have a collection of items to process
                Dim items(999) As Integer
                items.WithProgressReporting(Function(progress) worker.ReportProgress(progress)).ForEach(Function(item) Thread.Sleep(10)) ' simulate some real work
                End Function

                AddHandler worker.ProgressChanged, Function(sender, e)
                ' make sure the figure is written to the
                ' same point on screen each time
                Console.SetCursorPosition(1, 0)
                Console.Write(e.ProgressPercentage)
                End Function
                
                worker.RunWorkerAsync()
                Console.Read()
                

                End Sub

                Unfortunately in VB the line

                items.WithProgressReporting(Function(progress) worker.ReportProgress(progress).ForEach(Function(item) Thread.Sleep(10)))

                throws an exception "Expression does not produce a value" at the underlined place. There's no such exception in C# where the test code compiles and executes fine. Having to implement the technique into my VB application, I'd like to understand where the problem arises. Could anyone of you tell me what's wrong in the (automatic) translation of the Lambda expression? Thank you Mick

                E Offline
                E Offline
                Estys
                wrote on last edited by
                #19

                I always have trouble with anonymous delegates in VB so I factored them out :

                Class Program
                Shared worker As BackgroundWorker
                Public Shared Sub Main() 'ByVal args As String())
                worker = New BackgroundWorker()
                worker.WorkerReportsProgress = True
                AddHandler worker.DoWork, AddressOf DoWork
                AddHandler worker.ProgressChanged, AddressOf ProgressChanged
                worker.RunWorkerAsync()
                Console.Read()
                End Sub

                Private Shared Sub DoWork(ByVal sender As Object, ByVal e As DoWorkEventArgs)
                    Dim items = Enumerable.Range(1, 1000)
                    items.WithProgressReporting(AddressOf ReportProgress).ForEach(AddressOf DoSleep)
                End Sub
                Private Shared Sub ReportProgress(ByVal progress As Integer)
                    worker.ReportProgress(progress)
                End Sub
                Private Shared Sub DoSleep(ByVal item As Integer)
                    Thread.Sleep(10)
                End Sub
                Private Shared Sub ProgressChanged(ByVal sender As Object, ByVal e As ProgressChangedEventArgs)
                    Console.SetCursorPosition(1, 0)
                    Console.Write(e.ProgressPercentage)
                End Sub
                

                End Class

                Cheers

                S 1 Reply Last reply
                0
                • L Luc Pattyn

                  Eddy Vluggen wrote:

                  How did you resolve the fact that VB.NET lacks a "yield return" statement?

                  perhaps with patience. Yield exists since VS2010 SP1 according to this[^]. And it is simply yield, not yield return, so for once VB.NET is less verbose than C#. :)

                  Luc Pattyn [My Articles] Nil Volentibus Arduum

                  T Offline
                  T Offline
                  Terence Wallace
                  wrote on last edited by
                  #20

                  Hey just wanted to say thanks Luc that link got me to several other links on the subject and could prove quite useful to me in the very near future. Thanks again. This is now supported in VS 2010 SP1, with the Async CTP, see: http://msdn.microsoft.com/en-us/vstudio/gg497937[^] Also see: http://www.microsoft.com/downloads/en/details.aspx?FamilyID=4738205d-5682-47bf-b62e-641f6441735b&displaylang=en[^]

                  "If you think it's expensive to hire a professional to do the job, wait until you hire an amateur." - Red Adair

                  1 Reply Last reply
                  0
                  • S Sonhospa

                    Hi guys, I hope you had a nice start into 2012! I've been trying to convert this^ piece of code into VB, using VS Express 2010 and #Develop. In order to avoid problems with conversion of c# 'yield' operator, I put the extensions into a DLL and set a reference to that. The translated code of the test implementation reads like:

                    Shared Sub Main(ByVal args() As String)
                    Dim worker As New BackgroundWorker()
                    worker.WorkerReportsProgress = True
                    AddHandler worker.DoWork, Function(sender, e)
                    ' pretend we have a collection of items to process
                    Dim items(999) As Integer
                    items.WithProgressReporting(Function(progress) worker.ReportProgress(progress)).ForEach(Function(item) Thread.Sleep(10)) ' simulate some real work
                    End Function

                    AddHandler worker.ProgressChanged, Function(sender, e)
                    ' make sure the figure is written to the
                    ' same point on screen each time
                    Console.SetCursorPosition(1, 0)
                    Console.Write(e.ProgressPercentage)
                    End Function
                    
                    worker.RunWorkerAsync()
                    Console.Read()
                    

                    End Sub

                    Unfortunately in VB the line

                    items.WithProgressReporting(Function(progress) worker.ReportProgress(progress).ForEach(Function(item) Thread.Sleep(10)))

                    throws an exception "Expression does not produce a value" at the underlined place. There's no such exception in C# where the test code compiles and executes fine. Having to implement the technique into my VB application, I'd like to understand where the problem arises. Could anyone of you tell me what's wrong in the (automatic) translation of the Lambda expression? Thank you Mick

                    D Offline
                    D Offline
                    DavidSherwood
                    wrote on last edited by
                    #21

                    In VB, a function that returns void is a "Sub". This is true with lambda function as well. So your ForEach lambda should be

                    ForEach(Sub(item) Thread.Sleep(10))

                    S S 2 Replies Last reply
                    0
                    • D DavidSherwood

                      In VB, a function that returns void is a "Sub". This is true with lambda function as well. So your ForEach lambda should be

                      ForEach(Sub(item) Thread.Sleep(10))

                      S Offline
                      S Offline
                      Simon_Whale
                      wrote on last edited by
                      #22

                      Only true with 2010 though, as there is many time I would loved to of used it in my current project that is 3.5 framework

                      Lobster Thermidor aux crevettes with a Mornay sauce, served in a Provençale manner with shallots and aubergines, garnished with truffle pate, brandy and a fried egg on top and Spam - Monty Python Spam Sketch

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                      0
                      • S Simon_Whale

                        VB2010 has introduced sub(parameter) into the lambda specification. I haven't tested it but wouldn't the following work?

                        items.WithProgressReporting(sub(progress) worker.ReportProgress(progress) end sub).forEach(function(item) thread.Sleep(10)))

                        Lobster Thermidor aux crevettes with a Mornay sauce, served in a Provençale manner with shallots and aubergines, garnished with truffle pate, brandy and a fried egg on top and Spam - Monty Python Spam Sketch

                        S Offline
                        S Offline
                        Sonhospa
                        wrote on last edited by
                        #23

                        Hi Simon, sorry for the late response which was due to a short holiday of mine. Thanks for your hint which pushed me in the right direction: In the end, all I had to do was change "function" into "sub" in VB. It's finally solved now, and the line

                        items.WithProgressReporting(Sub(progress) worker.ReportProgress(progress)).ForEach(Sub(item) Thread.Sleep(10))

                        works, as well as Estys suggestion to factor out the subs. No "end" needed here. Regards - Mick

                        S 1 Reply Last reply
                        0
                        • S Sonhospa

                          Hi Simon, sorry for the late response which was due to a short holiday of mine. Thanks for your hint which pushed me in the right direction: In the end, all I had to do was change "function" into "sub" in VB. It's finally solved now, and the line

                          items.WithProgressReporting(Sub(progress) worker.ReportProgress(progress)).ForEach(Sub(item) Thread.Sleep(10))

                          works, as well as Estys suggestion to factor out the subs. No "end" needed here. Regards - Mick

                          S Offline
                          S Offline
                          Simon_Whale
                          wrote on last edited by
                          #24

                          Glad it helped :thumbsup:

                          Lobster Thermidor aux crevettes with a Mornay sauce, served in a Provençale manner with shallots and aubergines, garnished with truffle pate, brandy and a fried egg on top and Spam - Monty Python Spam Sketch

                          1 Reply Last reply
                          0
                          • U User 7825588

                            Try changing this line:

                            items.WithProgressReporting(Function(progress)
                            worker.ReportProgress(progress)).ForEach(Function(item) Thread.Sleep(10)) ' simulate some real work

                            To this:

                            items.WithProgressReporting(Function(progress) _
                            worker.ReportProgress(progress)).ToList.ForEach(Function(item) Thread.Sleep(10)) ' simulate some real work

                            The .ForEach extension method doesn't work with IEnumerables and since that's what WithProgressReporting returns, the resultset must first be cast as a Generic List. Also, I don't know for sure, but it looks like the converter inserted an extra line break. That's why I added the underscore to the end of the first line.

                            S Offline
                            S Offline
                            Sonhospa
                            wrote on last edited by
                            #25

                            Hi Member... ;) , sorry for the late response which was due to a short holiday of mine. Thanks for your hint which unfortunately didn't work: In the end, all I had to do was change "function" into "sub" in VB. It's finally solved now, and the line

                            items.WithProgressReporting(Sub(progress) worker.ReportProgress(progress)).ForEach(Sub(item) Thread.Sleep(10))

                            works, as well as Estys suggestion to factor out the subs (no "end" or "ToList" constructions needed). Regards - Mick

                            1 Reply Last reply
                            0
                            • E Estys

                              I always have trouble with anonymous delegates in VB so I factored them out :

                              Class Program
                              Shared worker As BackgroundWorker
                              Public Shared Sub Main() 'ByVal args As String())
                              worker = New BackgroundWorker()
                              worker.WorkerReportsProgress = True
                              AddHandler worker.DoWork, AddressOf DoWork
                              AddHandler worker.ProgressChanged, AddressOf ProgressChanged
                              worker.RunWorkerAsync()
                              Console.Read()
                              End Sub

                              Private Shared Sub DoWork(ByVal sender As Object, ByVal e As DoWorkEventArgs)
                                  Dim items = Enumerable.Range(1, 1000)
                                  items.WithProgressReporting(AddressOf ReportProgress).ForEach(AddressOf DoSleep)
                              End Sub
                              Private Shared Sub ReportProgress(ByVal progress As Integer)
                                  worker.ReportProgress(progress)
                              End Sub
                              Private Shared Sub DoSleep(ByVal item As Integer)
                                  Thread.Sleep(10)
                              End Sub
                              Private Shared Sub ProgressChanged(ByVal sender As Object, ByVal e As ProgressChangedEventArgs)
                                  Console.SetCursorPosition(1, 0)
                                  Console.Write(e.ProgressPercentage)
                              End Sub
                              

                              End Class

                              Cheers

                              S Offline
                              S Offline
                              Sonhospa
                              wrote on last edited by
                              #26

                              Hi Estys, sorry for the late response which was due to a short holiday of mine. Thanks for your hint which, together with the other guys' ideas, pushed me in the right direction: In the end, all I had to do was change "function" into "sub" in VB. It's finally solved now, and the line

                              items.WithProgressReporting(Sub(progress) worker.ReportProgress(progress)).ForEach(Sub(item) Thread.Sleep(10))

                              works, as well as your suggestion to factor out the subs. Just to complete: In your snippet I had to change the definition of 'items' to:

                              Dim items As IEnumerable(Of Integer) = Enumerable.Range(1, 1000)

                              in VB. But the most important thing: It works - and I hope I understand it a little better ;) Thanks again, regards - Mick

                              E 1 Reply Last reply
                              0
                              • D DavidSherwood

                                In VB, a function that returns void is a "Sub". This is true with lambda function as well. So your ForEach lambda should be

                                ForEach(Sub(item) Thread.Sleep(10))

                                S Offline
                                S Offline
                                Sonhospa
                                wrote on last edited by
                                #27

                                Hi David, sorry for the late response which was due to a short holiday of mine. Thanks for your hint which pushed me in the right direction: In the end, all I had to do was simply change "function" into "sub" in VB. It's finally solved now, and the line

                                items.WithProgressReporting(Sub(progress) worker.ReportProgress(progress)).ForEach(Sub(item) Thread.Sleep(10))

                                works, as well as Estys suggestion to factor out the subs (slightly changed). Thanks again, regards - Mick

                                1 Reply Last reply
                                0
                                • S Sonhospa

                                  Hi Estys, sorry for the late response which was due to a short holiday of mine. Thanks for your hint which, together with the other guys' ideas, pushed me in the right direction: In the end, all I had to do was change "function" into "sub" in VB. It's finally solved now, and the line

                                  items.WithProgressReporting(Sub(progress) worker.ReportProgress(progress)).ForEach(Sub(item) Thread.Sleep(10))

                                  works, as well as your suggestion to factor out the subs. Just to complete: In your snippet I had to change the definition of 'items' to:

                                  Dim items As IEnumerable(Of Integer) = Enumerable.Range(1, 1000)

                                  in VB. But the most important thing: It works - and I hope I understand it a little better ;) Thanks again, regards - Mick

                                  E Offline
                                  E Offline
                                  Estys
                                  wrote on last edited by
                                  #28

                                  Michael Schäuble wrote:

                                  I had to change the definition of 'items'

                                  That's odd, with me it worked as I posted it. I'm on .NET 3.5, VB Express 2008 Cheers

                                  If you can read this, you don't have Papyrus installed

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